determine the vertical reactions at each of the four outriggers as a function of the boom angle

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The mobile crane is symmetrically supported by two
outriggers at A and two at B in order to relieve the
suspension of the truck upon which it rests and to provide
greater stability. If the crane boom and truck have a mass of
18 Mg and center of mass at G1, and the boom has a mass
of 1.8 Mg and a center of mass at G2, determine the vertical
reactions at each of the four outriggers as a function of the
boom angle u when the boom is supporting a load having a
mass of 1.2 Mg. Plot the results measured from u = 0° to the
critical angle where tipping starts to occur.

Опубликовано:

19 сен 2024

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Комментарии : 32

@MorganParkinson 6 лет назад

Love this explanation. Working hard to understand it fully. Would really love the same example worked with the boom facing backwards as well, so I can understand it better. Especially how it works if G2 is between A and G1. For expert mode difficulty, can you even show a worked example where the boom isn't orthogonal. What if the boom isn't straight ahead or behind?

@beebuh 7 лет назад

Did you round differently? In the solutions to this problem, the answer shows: theta to be 70.3 degrees , N'A to be (29.4-31.3 sin(theta) kN and N'B to be 73.6+31.3 sin(theta)kN My professor used the sum of moments from B for this. Update: the error occurs at 7:05 in the video.I think you may have just looked at the sin(theta) wrong when writing it down. It was supposed to be 62.538.

@jamesfinch8375 7 лет назад

I think your N'B is supposed to be 73.6+31.3 sin(theta) kN

@SpaceShark240 6 лет назад

Divide his answer by two. The answer requires the Na and Nb for each of the FOUR legs, not two which is in the picture.

@雀枕 3 года назад

@@SpaceShark240 yah, he said that at first and took the note....

@mode1charlie170 6 лет назад

kind of confusing at first...boom angle being measured from the vertical. In real life however boom angle would be measured from the horizontal. i.e. tipping would occur at approximately 20 degrees boom angle. Great explanation however!

@earlkennethgeroche8140 3 года назад

How did you get the 70.63?

@p0045403 4 года назад

Just subscribed... GREAT presentation!!!

@Peace-th7yy 6 лет назад

Can you please explain how you get the values for NB=147.15+62.38 and the values for NA =58.85-62.38 that's where I get lost

@philliplai7275 3 года назад

I got lost too

@GinaFKN 3 года назад

I’m actually trying to work out the outrigger loads/reaction forces for my Kobelco RK-160-2 mobile crane as they aren’t available to me through the manual. I would really appreciate it if that is something you could work out for me and possibly provide a spreadsheet of those values at varying angles/degrees at its maximum lift capacity of 16t.

@nkanyezinhlumayo6817 Год назад

Hi Gina, Have you manage to work out the maximum lift capacitiy of the cranes? I am currently looking to find out the same

@jose-jonathanarthur7885 2 года назад

Thank you so much this was really helpful. I was absolutely lost.

@rajeshreegaikwad05 4 года назад

Can you do the same for telescopic boom lift? And one thing to mention, when angle changes, the CG shifts backward, which you have not considered, please cinder that as well

@mode1charlie170 3 года назад

Can you do the same calculation with the boom rotated off of the longitudinal centreline of the carrier.

@joaohenriques7428 3 года назад

How did you get the value 62.38?

@shohel1718 5 месяцев назад

how did you get NB and NA equations please. 147.15??? & 62.38??? How?

@shohel1718 5 месяцев назад

Hi also weight W1 & W2 where you get??? If you assumed then ok what about others also assumed only😂😂😂

@firankorteshome2168 6 лет назад

please if you have any concepts on the the kinematics of tower crane analysis share it !

@rickjljr11 4 года назад

it says the crane boom and the truck have a mass of 18. then it says the mass of the boom is 1.8. so is the mass of the truck and boom 19.8 or (16.2 + 1.8)? The later gives a theta of 60 deg instead of 70, not a good mistake to make if you are running a crane.