Digital Pins Are Amplifiers - What TTL And CMOS Invalid Voltages Really Are - Simply Put

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Why is there a central range of invalid voltage between 'high' and 'low', instead of there just being a single switch point? Why is it important that digital inputs (especially clock inputs) switch rapidly? Because, despite being a digital chip that is supposed to operate only in a digital manner, transistors of all kinds still are fundamentally analog devices, and operating them in an analog manner can mess up an entire chip's logical process. Also, you could totally use a digital inverter chip as a goofy analog amplifier if you were really careful about it.
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22 июн 2020

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Комментарии : 33

@tbandikoota 4 года назад

I cannot begin to explain how valuable these lessons are. You are sharing facinating detail that explains so much, yet it is easily missed when you glance over a datasheet. Thank you 🙏

@philipgiacalone5605 Год назад

Best electronics teacher on Earth. Your videos are fantastic. Thank you.

@sydallan6083 3 года назад

This guy may be the most underrated RU-vidr I have ever seen

@asdpc 4 года назад

I'm starting to hit like on this guy's videos preemptively instead of adding them to "watch later" because I simply know upfront that I will like them 🤣

@ydoesgooglesuck1960 3 года назад

Bless you brother! Nail got wacked on the head while we watched

@Reverend11dMEOW Год назад

this brings back harsh reality setting in as switch noise kept me flummoxed 'til this day, which de-bouncing efforts failed me on my first and last effort to use analog switch IC inside the guitar pedals I had modified in moving the switches for multple pedals off-board to one long extruded aluminum bar, but dang, man. Any hints what I missed, all I received was an even more powerful SNAP when the player hit any of my misplaced switches and had to undo the whole mess....... It seemed so obvious, but I was clueless. CD4066 IIRC thanks! Digikey's "how-to-implement-hardware-debounce-for-switches-and-relays" link is pretty-much what I followed.

@philipatkinson1532 3 года назад

Now- you have it. People fail to be curious. We therefore never move. Well said sir, I’m guessing most of your viewers are curious, and such a relief to see this

@metalman5798 2 года назад

I’m too curious to go buy a new guitar amplifier for myself with old electronics laying around here and I have a new infatuation with the best RU-vid creations I ever saw I may be starting my own curious channel and asking why so I haven’t seen anything more than two of you so far and I’m definitely going through the whole RU-vid channel to see you and what you have discovered! It’s like I have a new favorite textbook I cannot stop learning so there goes all my future plans for the day at least I’m going to have so much fun and annoy my peers with amazing things that they don’t want to hear me try and make them feel half as excited about lol but I’m so excited about it it’s just amazing!

@sullivanzheng9586 2 года назад

Really love the way to talk it in such simple way, and always in discovery mode.

@rcottam Год назад

The real benefit of CMOS is found by spending minimal time in the transition zone. The transition zone forces the transistors to dissipate heat. That's a waste of power. You want the chip to be cool and efficient.

@jimmatheson9125 4 месяца назад

There were synthesizers (gnat and wasp) that abused cmos ICs to make analog oscillators and filters.

@parapos 4 года назад

well explained as usual, thank you.

@shaywave 2 года назад

YOLO, Ilove it!! Keep up the great work. -Chaos

@TimPerfetto Год назад

Thank you

@dustyswitch4047 4 года назад

Please make the video you mentioned a few back about the best set of 'beginner' chips for experimenting. That would be great. This video was great too. As always.... Thanks

@sullivanzheng9586 2 года назад

The inverters are frequently used as analog amplifiers in generating clock signals for MCUs and LO for RF mixers. Actually, to make sure the inverter stays in the amplification region (linear, "bad" transition region), a feedback resistor, usually 1MOhm or something like that, connects the output of the inverter to the input of the inverter to create a negative feedback, so that the inverter is biased to the transition state. You can check "pierce oscillator using inverters/NOR gates/NAND gates" to see how such digital analog inverters are used as analog amplifiers, in almost every clock generation circuit, using L-C network or Crystal-C network. A example here: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-2Dg_GYXs4Ss.html

@taihatranduc8613 3 года назад

I love you as a person

@zerocash9080 9 месяцев назад

You are like Ron Swanson, but a more tech savy one :)

@philipatkinson1532 3 года назад

And I’ll be watching ya, bet you hate the phrase ‘ You cant be too safe’ as much as I do. Stasis is very dull I think.

@Pikachu871 4 года назад

I really like your whiteboard diagrams, maybe would've been cool if you illustrated the triple inversion vs not with the whiteboard. Please do keep making videos!

@simplyput2796 4 года назад

Yep, I should have. I kind of just forgot. True professional right here.

@rudrakshavegad1999 4 года назад

Sir, I really like how you dive into very basics intricately and that's the case with me too . Can yo please explain me how to solve the 0.7 deadzone In bjts. I mean how an op amp made of bjts can sense very small voltage . Iam trying to make a basic voltage comparator with bjts on breadboard and iam having problem of 0.7v deadzone . My circuit can only sense voltages above 0.7.

@simplyput2796 4 года назад

I'm still learning op-amps (i do want to do videos on making them in the future), but I do know that for normal class A amplifiers like common emitter, usually the base+input is biased so that the transistor never goes into saturation or cutoff, so you have less total voltage range to work with, but it's always within the active region. That's my best guess at the moment, and usually the way to deal with transistors turning off below 0.7V: Don't let them get below 0.7V.

@sadface7457 4 года назад

Could you do a video on how to deal with part tolerances? it something that you always encounter and sure you have figured you way arround over the years.

@simplyput2796 4 года назад

Could you elaborate on what you're looking for? What kinds of parts and what tolerances, like resistor value +/- %or such?

@sadface7457 4 года назад

@@simplyput2796 How do you design arround having % tolerances in component parts how do you include them in calculation then how do you compensate in the design

@simplyput2796 4 года назад

It's similar to managing error bars in physics. Let's say you want to use a voltage divider to cut a signal in half, so you use two resistors that are equal in value but have 5% tolerance. The worst possible result is that one is plus 5% and the other is minus 5%, so that means instead of 50% you might get as little as 47.5% or as much as 52.5% as your actual signal gain change. So then you just look at what you're doing with that signal and say "Is this okay?". If so, then check it off and move on; If not, buy better parts or design a more complex circuit.

@sadface7457 4 года назад

@@simplyput2796 I have heard of people putting sets of resistors in parallel so that their combined error is lowwer and adding trim pots to tweak values.

@simplyput2796 4 года назад

Interesting about combining resistors to affect their combined error. I'll look into doing a video on that.

@BIGRIP87 3 года назад

i am curious

@vrjb100 2 года назад

Curiosity made the expert. You can't do this. Why? Because I've learned not to do this. That's not an expert. Well let's find out why and become the expert.