The way you explain things on your videos is very clear, direct to the point and easy to understand. So far, this is the best channel for pharmacy calculations. Thanks for the great help Sir!
You all prolly dont give a damn but does someone know of a tool to log back into an instagram account..? I somehow lost the password. I love any tips you can offer me
@Nathan Ares thanks for your reply. I got to the site on google and Im waiting for the hacking stuff now. I see it takes quite some time so I will reply here later when my account password hopefully is recovered.
Is the 1:500w/v equivalent to density concentration? If that's the case, could we have used density "conc= mass/volume" to solve this problem. Thank you for your presentation too. Very helpful. From 🇬🇭
Thank you @nii3589 for watching and for the comment. Yes, the 1:500w/v may be considered as a mass or density concentration and you could use the "conc= mass/volume" to solve the problem. Hope this helps. Keep up the good work.
Why can't you be our instructor. You are so clear and step by step. You have taught me more in one night than I have in the last month of class. Keep up the good work
May I ask a question Sir? Where did the 100mL came from in the last problem of osmolarity? Was that an assumption that for every 0.9g of NaCl there is 100mL in ratio? And also, I didnt mean to offend you Sir, but pls could you include the derivations of the formula in your videos? Some might wonder where did that formula came from (not all can understand it immediately). Thank you Sir, God Bless you.
@@fahadabdulrazaq670 Here are two videos on dose calculations: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-abFJrf-_kZQ.html , ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-O7z6B7I9NAQ.html . There are a few more on the channel.
Thank you TheCc064, for your comment and for watching our video! We're thrilled to have you as a part of our community and look forward to creating more content that you'll love. Here is how you get the 200 g. 10% w/v x 2 L. Since, 2 L is 2000 mL, this implies ((10g/100 mL) x 2000 mL) = 200g. Hope this helps.
This is the best explained pharmaceutical calculations i have ever had in my life, thank you very much Sir for this, my mind is so at ease because i have an exam in 10 days, and i feel much better. Do you have videos on molarity and normality and molality?
Hello sir, Please guide me through this question; How many ml of water should be added to 200 ml of a 1:125 w/v solution to make a solution such that 50 ml diluted to 100 ml will provide a 1:4000 dilution?
14% C1 ×Q1 (red) >>product (blue) Q2 Petrolatum has 0% sulfur for dilution product C2 final product(purple) has 10%×60g= how much sulfur is there and how much you will end with, Q1(original product)10%×60g/14%=42.9g Q2 (final product dilution)60g-42.9g=17.1g
14% sulfur C1×Q1(ORIGINAL) dilute adding petrolatum that has a lower amount of sulfur that is used. 10% =C2 × Q2(FINAL PRODUCT DILUTED OR STRENGTHENED ) C1=14% Q1=Q2 (0%)(10%)
+pwincess0101 Thank you for your comments. What are some of the topics you would like to see covered? I would be happy to do videos on those topics too. Also, you may check out www.rxcalculations.com for additional resources. Take care and all the best.
+Pharmaceutical Calculation thank you for replying!! and thank you for recommending that website it is really good! if possible could you please cover displacement volumes and values and infusion rates. thank you!
Hi! Do you mind replying back to how you would answer this question: What weight of a substance is required to make 375mL of a solution such that 25mL diluted to 2L will give a 1 in 1000 solution? It's the wording of the question that confuses me, and i cant seem to get the to the right answer. the answer is 30 But i dont know how to calculate it
Hello Hevin: See solution to the question here ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-Wl3xTVIb6ms.html. There is some introduction in the beginning to help understand what is going on in the question. However, you can go straight to 3:27 minutes if you just want to see the worked out solution. Hope this helps.
STRENGTHENED product to make more concentrated, 4% Coal tar ×36g =pure coal tar 100%xQ2 =Qf (4)36g + (100%)Q2=(10%)(36g+ Q2) 144g+100Q2=360g+10Q2 90Q2=360g-144g=216g 216g /90=2.4g how much of the 100% coal tar you will use to concentrate/strengthen the product.
Hello Bryan. Yes, those trituration questions are typically worded that way. Let me know if more solved examples will help. Thanks for watching and for the comment.
