Hello mwalimu! My name is Abdi Aden Muhumed I first appreciate the good work your doing really you are amazing!! After this, I wanted you plz to show us this titration practically especially direct titration this one you are now emphasizing in the last part based on the s.v like the 3 students samples they did there is a student who got in the last titration 24.5 which emerges the s.v. show us this pls sir Thank you so much❤️❤️❤️
Hello sir,,, if a student have 7 as is average titre while the school value is 13.0f cource Accuracy =0...... but What about the remaining parts will he/she be wrong?? Or it will be marked in accordance to the students value
Yes, Samuel. Good news! You only lose 2 marks; accuracy and final answer (final accuracy). Just use your volumes honestly in the calculations! All the best
Hi sir. The titration table has only 4 marks as usually indicated on the marks. The next question on the average has 1 mark. Does that mean that you have transferred the question on the average which usually has 1 mark to the titration table . I hope u are getting me I wish I could have called you and ask you this verbally.
Exactly, the 1 mark for average volume, the very first question after the table is where we get:- 1. The mark for Principle of averaging and, 2. The mark for Final Answer. That gives a total of 5 marks Thanks. For more explanation on this, watch this to the end 👉 ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-PPa-vuir_Cw.html
Hi teacher. If someone is not within the range of school value for accuracy, does that mean that such student will not get the mark for final answer and accuracy.
Exactly Abdul, but the student loses only those 2 marks, the rest of the workings are marked as a consequence of the wrong values (using the 'wrong' values if correctly used)
@@thekenyanteacher thank you sir, for the first time I have learnt how marks are awarded in the titration I would like you to guides us how electrode potentials is used to determine whether or not , a reaction will take place or not. I have a problem in that part. I know that if the emf is positive, a reaction will occur and if the emf is negative, a reaction will not occur. But when I try to calculate it, I normally get a positive emf which sometimes is wrong
