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52:20 Q9: Ans is 50, bcz Car1 traveled 50Km from left & Car2 traveled 50Km from right.. Road is of 150Km.. 50+x+50 = 150 ∆ x = 50Km❤ (Distance bt both car after traveled in opposite direction of both/road)
I have made the flow chart as it is but there is no distance given between L and K then how can we find the distance between C and K Can you please tell me?
Thank u so much sir direction chapter aur syllogism chpater pdhane ke liye mujhse ek v questions direction ka slove nhi hota tha jab se aapke video Dekhi hu tb se sara questions mera bnnne lga h thank u so much sir aapke pdhane ka tarika bht hi acha hai
Thank you so much for the session sir I follow your offline videos and I appreciate your efforts how you're accentuating each and every topic relevant to our syllabus and taking 2 - 3 classes on each, noone has ever done this before thank you so much for making my concept sharper, I hope you earn the fame and respect like most of the faculties
@@CR-xw7fu ik it's too late to answer your question but when asked about distance we need to find via pythagoras theorem first if there is a possibility otherwise we add just the way you did i.e. 14
In Qn no 4 , first person walks 20 km east we assume this direction from home , then turn right and walk 10km here we assume right direction a/c person . Now again he turn right and walk 20 km ,here we also assume direction a/c to that person Then he walk south direction for 10km ,why don't we took this south direction according to that person , if we assume south direction according to person then should in the direction where he should back 10km on the same direction . But here sir u have taken the south direction according to Indian map Plz solve my doubts 🙏🙏🙏 Eagerly waiting for ur reply 🙏🙏🙏
Brother hua kya doubt clear... Because this type of questions appeared in one of my recent exam...I took south direction according to map and answered the question...But I'm still in doubt...I think when it comes to direction like N,E,W,S we have to work on these according to map
Q10. answer Direction - point K is south of point C Distance - AB = CP = 7km DL = PK = 5km therefore CP + PK = distance of point C to point K 7km + 5km = 12 km will be the distance of point c to point k thanks you so much
Nice session sir... You are too good..you are providing more than the expectation sir thank you very much... Sir please Do not stop the RU-vid class... everyday we egarly wait for your class.. Till now haven't felt comfortable with any other session like yours.. Its humble request🙏🙏🙏
@@sunitahosur8823 I mean u prepared for bank exam till 2 years so I thought why not I ask u that are u achieved ur goal? Just because here u commented before 2 years and I am beginner bank aspirant so I am here in this lecture... I saw ur comment so I asked that question Plzz tell me na Now are u joined bank
answer will be 10 km option given was correct..total distance covered will be 25+25+15+15=80,..if both cars travelling in same speed then second car also covers 80 km in same time...toal distance covered by both car=80+80=160,but the total initial ditance given was 150km..that means the cars have croosed their intersecting point ,distance between them=160-150=10km,option c was correctly printed,no need to change that.
Silly mistake that even i did at first is by letting (15+15)km on the main road when it actually travelled off the main road, thereby the distance which the first car travelled on the main road is (25+25) km which leaves us the answer 20km. 50km travelled by the first car on the main road and 80 km by the 2nd car on the main road = 130 km . Hence, 20km
@@mahi97- Bro, Q no. 8 has nothing to do with the speed, it directly said that the 2nd car travelled 35 kms. Please understand both the questions are asking the distance between the cars(distance between them on the main road), So the first car travelled 50 kms in the same distance (no matter whether it took off the main road, it was back on it and the total distance it travelled in the same direction was 50 kms (25+25) and the second car travelled 35 so the distance between them was 150- (50+35) = 65 kms But in Q. No 9 , the question mentions the speed is equal in both the cars so if the first car travelled 25+15+25+15= 80 kms then the 2nd car also travelled 80kms. But the catch is the 1st car travelled (15+15)kms in the wrong direction so it can't be put into account. Therefore the 1st car travelled only (25+25) kms in the correct direction. Hence the distance between them is 50kms by the 1st car and 80 kms(nothing mentioned so we assume it travelled in the correct direction) by the 2nd car , therefore distance between them is 150 - (50+80) = 20 kms I hope it is clear now👍🏻
Thank you sir for these free classes ........i was hoping i could find a full set of reasoning chapters and then join any paid batch.......I'm only half way through but i think I'm getting a lot better now
Ans is (Data is not sufficient) Dont waste time to solve to questions n0 10 because this question is wrong A person starts from point D in south direction. He walks 5 km and reaches point L and then turns towards west and reaches point K which is in south of point C. Find the direction and distance from point C to K? To determine the direction and distance from point C to K, let's break down the movement step by step: 1. Starting Point D: The person walks 5 km south to point L. 2. From L to K: The person turns west and reaches point K, which is stated to be south of point C. Since K is south of C, the distance and direction from C to K is directly north. The exact distance from C to K isn't provided, but the direction is clear: Direction from C to K: North If you need to calculate the distance, additional information about the specific distance between C and K would be required. Point B is 7 km north of point A. Point A is 8 km east of point G. Point B is 12 km east of point C. Point E is 9 km north of point D which is 12 km east of point A. Find the direction and distance from point C to K? Let's analyze the information step by step to locate each point and find the position of K: 1. Point G: Let’s place point G at (0, 0). 2. Point A: Point A is 8 km east of G: A = (8, 0) 3. Point B: Point B is 7 km north of A: B = (8, 7) 4. Point C: Point B is 12 km east of C: C = (8 - 12, 7) = (-4, 7) 5. Point D: Point D is 12 km east of A: D = (8 + 12, 0) = (20, 0) 6. Point E: Point E is 9 km north of D: E = (20, 0 + 9) = (20, 9) Now we have the coordinates: G: (0, 0) A: (8, 0) B: (8, 7) C: (-4, 7) D: (20, 0) E: (20, 9) Finding Point K: The problem does not provide specific details about point K. If K is defined in relation to the points already established, please specify that relationship to assist further. Distance and Direction from C to K: Without additional details about K's location, I cannot provide the distance and direction from C to K. If you can clarify K's position or its relationship to the other points, I'd be happy to help you find the answer!
Sir...ty so much for your efforts which u r making for all of us ...n Yess I'm learning a lot of things in reasoning just because of yur teaching pattern...I want to ask u one thing that is ...in the last question I didn't understood the distance 20 km how u have calculated becoz the other car will also follow the same path then we will minus the same 80 km from the total distance...help me in this question 😑
Anitha and Kathir are two friends studying in the XYZ Arts College. Anitha starts walking from her house in north direction. After walking 120m, she reached the Axis Bank. Then she turns and walks 40m in north-east direction. Then she turns 90 degree clock wise direction and walks 30m to reach Kathir’s house which is in the east of the Axis Bank. Then from Kathir’s house both of them walk 130m in south-east direction to reach their college which is east of Anitha’s house. What is the shortest distance between Anitha’s House and XYZ Arts College? A- 100 B- 110 C-120 D- 130 E-CND Pls sir tell me how to solve this type of questions
Q9... Distance will be 50 no sir.... We are refering to 150 km so, A travelled 50km and B with same speed will also cover 50 km wrt 150km. Hence, distance is 50km
Doubt Question - Point F is 3m to the north of point E. Point C is 6m to the south of point D. Shortest distance between D&A is 8m. Point A is to the west of point B. Ravish started walked from point E and after walking 4m head he reached point D from where he kept on walking in the same direction from where he started and reached point B after walking 12m. Point A lies somewhere between point D & B in a Straight line. E walked 4m ahead is time East side ya West side konsa hoga ...kaise decide karengea?? I have doubt on this part. If you can kindly suggest.
