@@sakshigupta8324 chatgpt reply -The function you provided is a semicircle equation centered at the origin with a radius of 3. The range of this function represents the set of all possible y-values it can take. To determine the range, we need to find the minimum and maximum values of y for the given function. Since the function represents a semicircle, the y-values will range from the lowest point on the semicircle to the highest point. The lowest point occurs at the bottom of the semicircle, where x = 0. Plugging x = 0 into the equation, we get: y = √(9 - 0^2) = √9 = 3. So, the lowest y-value is 3. The highest point on the semicircle occurs at the top, where the x-coordinate is either 3 or -3. Plugging these values into the equation, we get: For x = 3: y = √(9 - 3^2) = √(9 - 9) = √0 = 0. For x = -3: y = √(9 - (-3)^2) = √(9 - 9) = √0 = 0. Therefore, the highest y-value is 0. Hence, the range of the function y = √(9 - x^2) is [0, 3]. aur waise bhi y=+√9-x2 hai toh y ki negative value consider nahi karenge
Sir Q.3 mein y ki range [0,3] hi hogi..cause question mein given hai Y=√(9-x²) ....iska matlab y is equal to some positive quantity matlab y greater than 0
in Q no.2 based ondomain and range there is a error in the solution for finding range, when you were applying quadratic formula , instead of 2 we have to write 2y in the denominater and the final answer of range is [ -1/2 to 1/2] -{0}.
Domain = R/{5} (B) option And Range = R/{0} It takes 2 seconds to solve this question thank you so much sir for providing top notch content in free of cost 🙏🏻🙏🏻
Answer of last question should be option b as all real numbers can be placed except 5 because at 5 whole expression will tend to infinity as denominator would turn 0 but any other real value except 5 wouldn't do so Hence option b
Sir , pls make a video on metric space i.e. connected metric space , continuity in metric space and compact metric space. I'm not understanding the topics of metric space .kindly make a video on above topic . Pls sir 🙏
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B Sir, there is a slight correction in the last question the range of the function sqrt(9-x^2) would be [0,3] since the domain is [-3,3] therefore, on putting the extreme values the results is zero and on the minimal value that is 0 in domain the range will have the maximum value as 3
@@pixie_dust2089 it is given that y = root(9-x^2), and we know that a real number under root can never be negative so we get from here that y>=0. and hence discard -ve values
Proposnal and predicate logic and trees graphs and combination bhi sir jaldi se cover kar di jiye uske bhi video share kariye sir external exam hai 26 ko 🙏
sir an you please make some more video related to Nepal's University related topic...as I can understand the topic more by watching your video......rather than in college
