what do u do when the number of values for X1 and X2 are different, u can just put 0 for the the less numbered signal but how do we know if it should be on the left or right?
great video indeed !! but a little doubt that is as convolution is performed here, don't we need to flip one sequence ???? then do the rest of the thing
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Thank you very much sir..... Please I want to ask if y(n)={-2,-1,0,3,2,1,8} and x(n)={4,-1,1,2} find the system response h(n) How would I go about it...... thank you
Hello Neso academy. Is there a reference (a book/article/paper etc) which i can cite in my report (i need citation) for the above tabular method. Thank you.
Sorry but this doesn't seem to work in all case. Try the following example, it fails: x[n] = d[n] + 2d[n-1] - d[n-3] , h[n] = 2d[n+1] + 2d[n-1]. If you do the tabular method you end up with y[n] = -d[n+4] - 2d[n+3] + 2d[n+1] + 3d[n+1] - d[n-1]. That answer is incorrect, the true answer would be y[n] = 2d[n+1] + 4d[n] + 2d[n-2] + 2d[n-1] - 2d[n-4]. If I found one example of where it doesn't work, there's bound to be infinitely more.