Divisibility Rules upto 100 ## 2 Rules for All Numbers ## Make Your Own Rule # First Time on Youtube 

Superb sir. Thanks 🙏

I am impressed sir

Simple method: Isolate the last digit , multiply by 2 and the subtract it from the truncated number. If the result is zero or a number which is a multiple of 7, then that number will be divisible by 7. E.g Take 343. Isolate the last 3 and multiply by 2 , i.e. 3 x2 =6. Now subtract 6 from 34 = 28. 28 is a multiple of 7, hence 343 is divisible by 7. Similarly for 13, isolate the last no. multiply by 4 and add to the truncated number, if it is zero or a no. a multiple of 13, then that no. is divisible by 13 For 17. it is proceed as above , the multiplying no. 5 and subtract For 19 - it is multiply by 2 and add. Procedure as above.

Sir, what about divisibility rules of other numbers?

what abt dividing by 13, 17, 19

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Hello, I write from Europe 🇪🇺 and I could to play the JOKER 🤡 about all divisibility rules between 1 to 1000 or more. But we both know that with big numbers isn't sense to Chek if a number for example 1634781 is divisible by 893 or 623 , because his OSCULATORS were be very big numbers and to do the calculations will bring us to much time!! But I still knew all OSCULATORS that you said and for this reason another way, and also *"really more faster"* , to know the DIVISIBILITY RULE of *11* ....i just subtract of any step just the unit "OSCULATORS 1" by the last digit of that number till to Chek i!! But what means to subtract just the "OSCULATORS 1" by the last digit? Easy, that means to subtract alwsys *"just the same last digit of the number that we will have step to step"* . For example *"235169"* is divisible by 11?? Of course yes, because -1×9= - 9, that means always the same digit: 23516|9 -9 ---------- 2350|7 then just subtract -7 -7 -------- 234|3 then just -3 -3 ------ 231 and now is very difficult to subtract just MINUS 1 😭, but I will try to do it🤣. So 23|1 -1 ---- *22* which is divisible by 11, but if somebody didn't know that 22 is divisible by 11, you could to continue to Chek it, doing simply 2|2-2= 0. 😩 But with the number *231* we could still stop to find the divisibility rule by 12, because we all know cause the MAGIC TRICK that 11×21 = the sum of the digit of 21 ~> 2+1=3, where we this 3 put in the midfke of 21 ~> 231. But why we can just to subtract the "OSCULATOR 1" by the divisibility rule of 11??For the same reason that you explained in your video: 11×1=11 and so 11-1=10 and so we take the only then ~> (1) that we have. But to do it a little bit more difficult(just 2%😂😂) we could to take also the *"OSCULATOR +10"* because 11×9=99 and so 99+1= 100. The question is, how many "THENS" we have in 100?? Of course only 10. So is easy that THE other OSCULATOR could be only the *"10"* . About any divisibility rule, if we Chek the first(of boths) *"osculators"* then the other is *"always the difference between the DIVISIBILITY RULE of a number X"* , in this case "11" and 1 = 10(which is the second oscurato. About the DIV. RULE of 7 are 5 and 2 because his sum is 7, about 13 are 4 and 9 because his sum is 13, just that every time one of them OSCURSTOR will be positive and the other negative!! Have a nice day. 💪🤙👍🇪🇺