Doing u-substitution twice (second time with w) 

I've never heard such a smooth phrase, than 'I hope you dont't hear that crow outside, he's getting quite obnoxious.'

There was no need to take double substitution, but I think he did it in the case of more complicated problems. Thank you Sal!

That crow is taking Calc as well bruh

Guess you can call it Double-U substitution, ayyyyeeee

This helped me so much! I just transferred from a community college into a four year school, and I'm currently taking cal 2 at my new school. However, I did not learn anything from my cal 1 class, so been suffering in my cal 2 class. I watched 4 of your videos now, and they are great. I will keep use your videos to study, and thank you for your videos.

6:26 “... really hold yourself, feel too bad if you didn't see that insight ...” 😂😂😂 on point Sal. You r really a nice human being over all i think.

mojiganga2, the indefinite integral of -1/5 * e^u is -1/5 * e^(u) + c. I understand your logic and it would be true if "e" was a variable like "y" instead, but "e" is a constant rather than a variable. Think of it like the derivative of e^x is e^x as well as its integral is e^x. Hope this helps!

So, Arthur the aardvark's sister is equal to -du?

Your videos are very helpful when I forget how to do things like this!

really good crow commentary on this one

no homo, i really do love this guy lol im one of his biggest fans and admire everything he does

wen hes doing the simpler method he says the du/dx of -sin(5x) = -5 cos(5x), correct me if im wrong but isnt the d/dx sin(5x)= -5 cos(5x). wouldnt the - infront of the sin affect the - in the -5cos5x ? lol sorry if this doesnt make sense

dang crow

That's one u sub two many.. Quoth the raven... Sol means solution to us bird brains.... Thanks again for helping, God bless 🙏

Couldn't you just do power rule of e^-u after the first integral to get the e^u * u' which would result in your -e^u? (Times the 1/5 in front of course)

Omg it took me like 3 hours to solve a problem like this thank you

Even though it's not mine, I would like to dedicate this video to Leonhard Euler. The disease in his eye did not prevent him from seeing in mathematics what those before him had missed. Thank you, Khan, and thank you, Euler.

holy shit tried that question before playing the video and got it right woo :D:D

who thought of hey arthur when he said D-W hahaha

but how do the limits change if you do 2 substitutions??

Edgar Allen Poe is a Math teacher. Amazing

what if i simply just sub u=sin(5x)

7:37 I think you forgot to take the integral. I think the answer would be (-1/5) (e^u+1/u+1)+c .... Please correct me if I am wrong

Dang Crow haha

Nice but it could be easier if just take it as exp(-u)= exp(-1.u)=exp(a.u) Where a=-1

I know you've been very busy today, but maybe sometime in the future, are there any examples where you are forced to do 2 substitutions and there is no way to do it in one?

Sal thank u very much

THANK YOU!!!!!!!!!!!!!!!

Shout out to that crow though

You're never "forced" to use any type of substitution once you find patterns

couldn't the answer just be 1/5 ln(e^sin(5x)) ?????

Argh. I stopped paying attention to what he said and started listening to the crow!

THANK UUUUUUUUUU-- lol get it. U-

obnoxious crow. lol