Double-slit interference with phasors

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Using phasors to investigate the interference pattern I(θ) produced when a wave diffracts through two narrow slits separated by a distance d.
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About me: I studied Physics at the University of Cambridge, then stayed on to get a PhD in Astronomy. During my PhD, I also spent four years teaching Physics undergraduates at the university. Now, I'm working as a private tutor, teaching Physics & Maths up to A Level standard.
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#physics #mathematics #diffraction #interference #light #waves #doubleslit #doubleslitexperiment #laser #intensity #amplitude #oscillations #fringes #phasors #trigonometry #cosinerule #exponential #complexnumbers #arganddiagram #superposition #soundwaves #electromagneticwaves #physicsproblems #maths #math #science #education

Опубликовано:

19 сен 2024

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Комментарии : 4

@mingmiao364 6 месяцев назад

More optics content please!

@apq3710 6 месяцев назад

Is it possible to derive this result from the expression for the displacement produced by a single slit? I mean A is proportional to sin(½ka*sin(theta))/½ka*sin(theta) where a is a width of the slit I tried but got something really different. However, double slit is clearly just a superposition of two slits Btw great video!

@DrBenYelverton 6 месяцев назад

It is indeed, but note that the result you quoted applies to a slit of finite width while I'm assuming in this video that the slits are infinitesimally thin. The full analysis is mostly the same as in the video, except |A| is no longer a constant and should really be replaced by your expression involving the sinc function. So the phasor diagram I drew is still valid, but you have to imagine that the length of the two phasors we're adding changes as θ varies. That means the full solution is really the product of the expression in the video and the sinc function. In the limit a -> 0, the single-slit part of the expression tends to a constant independent of θ, because sinc(0) = 1, and you recover the result from the video.

@apq3710 6 месяцев назад

@@DrBenYelverton makes sense, thank you!