Thanks sir, 😊😊 last 37:50 wale me correction hai that's not correct one, at x= -1 function is not defined. Also as x tends to -1 on right side it will tend to -ive infinity and on left side of -1 it will tend to +ive infinite. And at x = 0 (-ive, -0.01) y is negative At x= 0 (+ive, 0.01) y is +ive So finally it will be type of -1/x Or just write y as 1-(1/1-x) which is simply understandably as shifted 1 unit upwards and leftwards of y= -1/x graph The graph u draw here is like of e^-(1/|x|)
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Value of any sin(y) will be always between -1 to 1. So cosec (y) ki value always be less than or equal to -1 and greater than or equal to 1. If we take cosec y = x. Than x can take values less than or equal to 1 and greater than or equal to 1. Hope it helps.
