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Plz clear one doubt...if the turns are in the same sense in both the coils then mutual and self fluxes will be opposing each other in both coils in parallel connection ...i.e. total flux through first coil would be (L1.I1 - M.I2) and vice versa ...and therefore in the denominator of Leq it should be (L1+L2+2M)....am I correct sir
sir can you please tell why in both the cases(supporting and opposing) if we take perfectly linked coils the L effective is 0 also if L1= L2 and then perfectly linked then would the answer be L+M/2 or 0 (in supporting case)
@@PhysicswithAkashGoyal sir does that mean jee 2020 mutual inductance was ambiguous and unfairly evaluated or was there a means to know whether the question was asking for aiding or opposing flux??