Sir at 10:31 you said two points they are 1)If we make Re value high the power supply voltage should also be me made high. 2)If we made Rb value as low the collector-base junction will become reverse biased. Coloud you plz justify above two points?
I think If we make Rb value low then Ib will increase because Ib = (Vbb-Vbe)/Rb and due to this Ic will reduce because Ie = Ic + Ib due to which Vc will increase because Vc = Vcc - IcRc {Vc is potential at point at collector terminal} due to which Vbc which is reverse bias voltage across J2 will decrease because Vbc = Vb - Vc i.e reverse bias voltage will become less positive. If anyone thinks this is wrong approach kindly correct me. thanks...
@@snappywho666 Because most of the electrons that emitter emits is collected by collector and almost no electron goes into the base region that's why base current remains very very low
as you explain increase in collector current will increase voltage drop across emitter and this lead to decrease in base current.... but we know Ie=Ic+Ib.... now Collector and emitter current increase but why base current decrease ... please explain it apart from prove by equation ... mean what exactly happens inside
Sir if base current decreases there will be less recombination rate ...so if recombination rate decreases there will be more carriers collected at collector region ...so we will have increase in Ic current ...but u said Ic decreases (according to Ic = beta Ib ) which reason should be considered sir....please reply
during different bias circuit explanation sometimes Ic = B.Ib sometimes Ic = B. Ic + (B+1) Icbo what are you the conditions and scenarios for the choice?
4:00 how Ie is nearly equal to Ic They are equal in common base configuration As Ic= (alpha)Ib this equation was proved in solving common bases configuration
thank you for just just wonderful and interesting lecture ,sir i have seen in book "introductory electronic devices and circuits " by robert T.paynter ,,he used two supply in emitter bias configuration one is Vcc and other is Vee,,and you have used only one supply which is Vcc,,sir please elaborate?
why your concepts in this video are so much different than Thomas L. Floyd (Electronic Devices)? why there aren't 2 biasing potentials Vcc and Vee and the base is grounded?
Sir gate questions please a separate 1-2hrs lec at the end of subject , only tell us how to slove, don't slove step by step(saves time plus more questions /concepts will be covered)
Pintu Kumar yeah might depend upon rb....if we consider Ie=ic+ib from output loop and also see input look so very much some assumption have been taken too....for ic=ie
Informative video without stupid music- thank you. But please go to 1:00 and you will notice how much clearer yellow text on a black background is ...need I say more?