EPTS - Lecture 19: Numerical Problems ( on calculation of Sag and Tension) 

what if tension is unknown? should we assume the total weight of the conductor is the tension? like if we have 10 lb/ft conductor and length of conductor between two poles is 50 ft, so the tension will be 10 * 50 = 500 lb ?

If we neglect wind pressure and determine sag for only conductor weight that is the equal to vertical sag. Easier way but confused it right or not? Anwser please.

Tq sir. Because of your lecture, this concept became very easy..

May I purchase this software ?

What is the ultimate strength and safety factor can u explain? Sir

Very helpful sir❤️.but the question on gradient wasn’t solved 😓

When do we use Slant sag=wt*l^2/2T ??

Thankyou sir....

in one problem you said tension = ultimate strength / safety factor and in another the formula is different

At a river crossing an overhead transmission line has a span of 560 m with the two supports of the lowest conductor at 15 m and 95 m above the water level. The weight of the conductor is 0.394 kgf/m. If the tension is adjusted to 1200 kgf determine clearance of the conductor above the adjusted to 1200 kgf determine clearance of the conductor above the water level at a point 215 m from the base of the higher tower. Iska answer bata do koi

Thank you sir ❤

Good work thanks for sharing

It is super but sums on ice on sag sir i want that

Super sir clearly explained ... Thank you sir

Do more videos

Vk mehtha book

Hindi me chahiye sir