Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET || 

For PDF Notes and best Assignments visit @ physicswallahalakhpandey.com/ To support me in my journey you can donate (Paytm@ 9161123482) or Alakh Pandey ,Bank of Baroda, Rajrooppur, Allahabad,U.P IFSC: BARB0RAJROO Account No: 19210100020819 A small amount of Rs 100 even will be of great help. Follow us on: Instagram instagram.com/physicswallah/ Facebook: facebook.com/physicswallah Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on RU-vid) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chapter 7 | Equilibrium | Chemical Equilibrium 01 : Introduction | IIT JEE MAINS / NEET ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-sCUgeC5ACv8.html Equlibrium | Chemical Equilibrium 02 | Equilibrium Constant Kp and Kc | IIT JEE MAINS /NEET ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-oyr7q5BrGEA.html&pbjreload=10 Equilibrium | Chemical Equlibrium 03 | Law Of chemical Equilibrium Numericals IIT JEE / NEET ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-z2G52O_7nd4.html Equlibrium | Chemical Equilibrium 04 | Degree of Dissociation and Observed density IIT JEE / NEET ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-x13K19_JwgY.html Equilibrium || Chemical Equilibrium 05 || Le - Chatelier's Principle IIT JEE MAINS / NEET || ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-NVZ4Jb9tLX4.html ----------------- IONIC EQUILIBRIUM ------------- Class 11 chapter 7 | Equilibrium | Ionic Equilibrium 01 | Theories Of Acids and Bases JEE MAINS/NEET ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-Uql1eQGq9Dg.html Ionic Equilibrium 02 | Ionisation Constant Of Weak Acid and Base | Ionic Product of Water JEE /NEET ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-Dgdz6bfRMdc.html Ionic Equilibrium 03 || PH Of Solutions | How to find PH | How to calculate PH of any Solution ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-uuGl5o8b3Zk.html Ionic Equilibrium 04 || Common - Ion Effect IIT JEE MAINS/ NEET || ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-xqq78GsLXSA.html Equilibrium | Ionic Equilibrium 05 | Buffer Solutions JEE MAINS/NEET /JEE ADVANCE -Part 1 ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-KH0w5TZnJaA.html Equilibrium | Ionic Equilibrium 06 | Buffer Solutions JEE MAINS/ NEET/ JEE ADVANCE -Part 2 ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-30eFAm74wp0.html Ionic Equilibrium 07 || Salt Hydrolysis IIT JEE MAINS / JEE ADVANCE / NEET || pH of Salts ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-I33BwmAz1sY.html Ionic Equilibrium 08 | Solubility and Solubility Product IIT JEE MAINS / JEE ADVANCE / NEET || ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-1tRdbmroncE.html

For the last Question, N204 = 2N02; 1)Temp = Since, its a decomposition reaction [DIMER - MONOMER] heat should be supplied to it, which means It is ENDOTHERMIC, there temp should be high 2)Pressure = should be lower as, high pressure means eq. shifts towards lower mole side 3)Inert material = should be Added as, eq shifts to the side having more moles of substance

Ans for the last question: Pressure = low Inert material should be added. Is it exo or endo, it,s not mentioned in the equation , so, temp isn't defined.

I am watching this video after 5years (2023) full crystal clear concepts explain by sir (salute)

Effect of: Conc- 11:42 Pressure- 18:29 Temp- 31:16 Inert Material- 42:35

Sir hamara toh 12th khatam ho gaya lekin aap jo kar rahe ho woh laakho ki zindagi badlega yeh tution walle ne sab cheezo ko apna buisness bana rakha hai zyaada aur education kam...aap jo karr rahe ho wohh karte rehna pls rukna matt aapko saari tution industry ko karara jawab dena hai aur unko batana hai that education is same for all wheather a person is average or class topper

Answer for the last question... 1) Increase the concentration of N2O4 2) high temperature is required 3) Low pressure is required 4) addition of inert material at constant pressure is also required... Thank you sir, you are doing a great job...

I am watching this video after 3 yrs . I must say that this man is genius . I have never seen a teacher even in coachings also who can teach both physics and chemistry with so much fun and feel . I wonder that how this video got 728 dislikes

Sir I love your T-shirts 😂 "Rise above Stereotypes" ✌️✌️

Temperature : High (since it is an endothermic reaction although not mentioned) Pressure: Low Inert material : we will use as it shifts the equilibrium forward towards more no of moles.

It is #DecompositionReaction and also N2O4 is a dimer of NO2. Temp= high Pressure= low Inert material is required at constant pressure

There is one more point . . . 5. The addition of catalyst: it doesn't effect the concentration of equilibrium mixture, as it only increases or decrease the time to attain equilibrium.

Me every time “lechatle” principle 😂😂

Alakh sir teaches chemistry extremely good... i almost forgot that his name actually is physics wallah

Ans. temperature should be high as it is a decomposition reaction. pressure should be low. inert material should be added at constant pressure.

1:07:46 N2O4 2NO2 Temp : High (Cuz bond breaking..i.e endothermic) Pressure: Low Inert material: Should be added

सर आप तो केमिस्ट्री और फिजिक्स दोनों के प्रोफेसर हैं 😯😯😯✌️😚🇮🇳🔥❤️

The person who disliked this video please remove it ,,,,,,,,,,,please like it ,,,it's request from physics walla channel followers😈😈😈😈😇😇😇😇

1)Exothermic kee liye-temp low Endothermic ke liye temp High 2) pressure-low 3)inert material 1) constant vol no effect 2) constant pressure

After 5 years also this video is a boon ❤

answer of homework question PRESSURE ----- PRESSURE SHOULD BE LOW TEMP----- TEMPERATURE SHOULD BE HIGH AS ENERGY IS REQUIRED TO BREAK BOND --- N204 IS DIMER OF NO2 AND ENERGY IS REQUIRED TO BREAK THE N---N BOND SO THE RXN IS ENDOTHERMIC AND TEMP SHOULD BE HIGH INERT MATERIAL---- SHOULD BE ADDED

Stay blessed sir( From Pakistan)

Huge respect for this extraordinary personality his lectures are mind-blowing

Pressure=low Inert material should be added Temp exo or endo not mention in this equation

Temp:- not defined cuz it's not that reaction is endo or exo. Pressure :- low Inert gas should be added. *Sir aap hum bachcho ke liye vardan ho.* 🙏🏻🙏🏻😁😁

Best lecture on Le- Chatelier's Principle you'll find on youtube 😊👍👍👍👍

Ans of H.W ques: 1. Pressure should be low 2. Inert material should be added at constant pressure 3. Temperature is not defined

Alakh sir teaches really good. His videos helped in building concepts for mdcat and were helpful in cracking it. Respect from Pakistan 🇵🇰

11:08 Sir hum to forever ready hain aapke sath antakshari khelne ke liye bas aap live aa jao😅

1. Pressure - Decrease 2. Temperature - Increase ( because it is an endothermic reaction with ∆H = +57) 3. Inert Material - It should be added.

Guys have u noticed,at 26:00 jo sir ne example dia tha usme reaction ka direction phle forward bataya tha,but after some seconds sir ne usko edit krke backward krdia.?isse ye pta chlta hai sir bhi kbi kbi confuse hote hai.no problem sir hota hai : )

No change in temperature would be required as the reaction is not endothermic or exothermic By decreasing pressure By adding inert material

Sir, you are a great teacher in the world.And you have proved that old is gold.Your old videoes help me a lot . Thank you sir 🙂🙂🙂

These videos can never be got old. After 3 years......... Thank you very much sir🙏🙏🙏🙏🙏🙏

11:58 i) concentration ii) 18:02 Change in Pressure iii) 31:20 Chnage of Temperature iv) 44:39 Addition of inert

This channel is literal the best for chemistry and physics . Love this

Well... There are many intro sounds nowadays But alakh sir's intro sound is the best of them all

U are the best teacher I have ever met in my life...u r just awesome and your examples just strike on my mind in few micro seconds😎😂 hope that meet u soon...lots of love alakh sir😍

Answer is Pressure low Yes inert material should be used No think about temp because there is no heat relevant information

After five years, still video is relevant. Hats off to the legend.Thanks sir. Never will I ever forget your contribution. 😥😥😓😓

1:07:02 ans is temperature increase And pressure decreed and Const volume =0 and const pressure =forward shifting .

High temp As this reaction is endothermic in forward direc Low pressure Yes inert material dalna haii

Hats off to you sir... You are inspiration for millions.. one day i will also become successful and will definitely help those in need whether economically or through teaching free of cost just like you..

I usually understand this principle by using the " Mad man method " where it is said that mad man will do the opposite you do.. You increase pressure, mad man tries to decrease it, he goes there.. You increase conc., mad man tries to decrease it, he goes to less moles... You increase temp. , mad man tries to decrease it, he goes to less temp. system... like that it can be easy..

1) Temp - increase ( decomposition reaction) 2) pressure - low (eq shifts right , more moles) 3) inert material (const pressure) - required

Anyone who thinks(must think😉😉😉) alakh sir is the best hit the like button.

Like to respect ALAK SIR .👍 . . . . . . . . . . .👍

Sir Temp Not Defined Inert material add Pressure Low

Sir temp. should be high Pressure should be low Inert material at cons. pressure should be added

Thank you soo much Alakh Sir for making Le Chatelier's Principle so crystal clear!Hats off to you Sir!Lots of Love and Respect...👏😎👌👌🤓😌🙏🙏😎😁😉

Watched Amit mahajan sir's lecture, didn't understand much... Watched Shishir mittal sir's lecture, feel nhi aayii... Watched Alakh Pandey sir's lecture, concept is now coming into my dreams too.. 😂❤❤ alakh sir OP

Temp not defined Pressure low means high vol therefore no of mole production high Inter gas c vol no effect And c pressure more no of moles therefore in the forward direction sir❤

Sir doesn't need to tell people to like the video, we automatically after watching it like it immediately

IT IS NOT ONLY PHYSICS WALLAH BUT ALSO CHEMISTRY WALLAH

*TEACHER*- *Le -Chatelier's principle* *ME*- *Le chat le re ye principle*

sir poore you tube pe kyaaa aap jaise teacher poore desh duniya mei ginee chunee hotey hai aap ke andar josh aur jazbaa hai aaap karate hai concepts ko crystal clear ...!! may god bless you. your each and every lucture's explanation is awesome..aapse padhkar physics aur chemistry se har student ko pyaar ho jayee agar kisi bhi bacche ko aapse naa smjh aaye tohh wo phir mann buddhi hai...you are one of the best teacher in the world🤩👍 aapko bharat ke bacho jaur usse jude uske padosi desh kee bacho ki dil se dua nikalti hai may you acheive more success in your life ...!! stay happy and healthy ...!! and stay the same sir as you are thank uh so much...!!😊 jitni tareef karein aapki utni kam hai hai you are the best teacher...!! thankss alakh sir😊💖

Inert material Constant pressure forward

i am blessed to find this channel. i dont have words to thank u sir.

Sir ka favourite dialogue " Hello baccho,kya haal chaal?

38:16 sir has committed mistake there, as in habers process the forward reaction is exothermic and not endothermic so low temp is favorable instead of high temp.

1. Temprature high (bcz : N2O4 do heat absorb than convert in NO2) 2. Pressure low 3. Inert material was like advantage for this reaction 🙏... ..........🙇 Tx so much sir 🙇.......... .....🙇for solve all type of doubts🙇.......

Dislike krne wale wo teachers hai jo itta accha kbi padha nhi payenge..jlte h sb.

Last question, pressure low , temp high, inert material, forward rxn

For last question ∆H= 58 Kj/mole Ans= N2O4 add,p low,T high,in constant p inert materials should be added.

Pressure-low At constant pressure- Inert material addition will increase yield

Sir, I am studying bsc however I am watching your videos to solve my doubts and concept..... Thank you so much physics walhaa

Favorable conditions for the last reaction :- 1 : By increasing the concentration of [N2O4] or by removing [NO2] 2 :Pressure should be low 3 :Can't define temperature 4: at ∆P=0 then forward reaction (which will not help in increasing the production )

Sir aapne to kaha tha ki inert gases ko add krne se koi change nhi aata

M also ex allen student Lekin vaha samjh ne aaya tha Aapne sari problem he solve kar de sir g thanku

Alakh pandey is the best teacher for physics as well as chemistry amongst all the teachers I have seen so far 🤗🤗🤗 What is ur opinion guys 🤔🤔

1:07:45 - Sir, i) Temp. decrease karenge kyunki, increase karne se reaction backward jayega { since, np > nr }, jo hume nhi chahiye. Pressure decrease karenge kyunki phirse reaction warna backward jayega { since, np > nr }, nhi chahiye. Inert material daalna parega taaki reaction forward jaaye { since, n of NO2 > n of N2O4 }, wahi chahiye.

Sir the answer of the last question : Low pressure Addition of inert gas And temperature is high

I learnt this chapter so perfect by seeing your lectures sir...we're paying alot on tution and actually learning from you without anything..

Last question's answer :- HIGH TEMP , LOW PRESSURE, INERT GAS AT CONSTANT PRESSURE

1:07:46 For maximum yield of NO2 Pressure - low And inert gas should be added

Home work Temp- high, ( heat acts as rectant in the decomposition of dinitrogen tetroxide, the reaction is endothermic) Pressure_low Inert material -needed with constant pressure

Homework question Temprature= no change Pressure= decrease Inert matrial = at constant pressure should be added

Exceptional teaching style sir...best teacher of physics and chemistry ever...especially for classes 11th and 12th..🙏🙏❤❤

I have seen very few teacher which revise all topic which they explain and Alakh Sir is one of them.

Forward direction

Inert material- present Pressure- low Temp.- high

Pressure low Temperature should be high Addition of inert material at constant pressure

thankyou sir, mujhe chemical equilirium kabi samaj me nahi aata tha par ab mera sara consept clear ho gaya

Last question answer: Pressure: low Inert material: forward Temprature: no effect

Temp should be high bcoz this is decomposition reaction. Pressure should be low. And inert material should be added at const. Pressure

Our True HERO Sir Alakh Panday😊😊 ... Respect and gratitude from Pakistan

1: 07: 37 Temperature = high Pressure =low Inert material required at constant pressure

Temperature high Presure low Inert material at constant pressure

"CHUHA" has a separate FAN BASE.....

there is no effect of temp. the reaction is preferred at low pressure addition of inert material will result in more productivity . . thank you

Sir Ji, pressure should be low, Inert material should be added at const. Pressure, And Temp. Should be high...

is this exothermic or endothermic? u ve nt given

An extremely intelligent teacher who cleared all my queries regarding this chapter - Respect from Pakistan 🇵🇰

Your T-Shirt "RISE ABOVE" is a strong motivation for every pwians 🌠🔥

Sir for N2O4=2NO Pressure Should be low Temperature Should be High Inert Material for constant Pressure should be added..

Last question answer Temp- Not given Pressure - At low pressure Inert material required for yield of the reaction

I am studying in PW offline but although I am watching these old videos of alakh sir❤

Temp-high(endothermic) Pressure-low Inert material should be added 👍👌

Temp---decrese Pressure---decrese Ya I know heat is not given And even not that it is exo or Endo But pressure directly proportional ...to temp And even Inert material should be added 💖🔥 Thx sir for your love and support 👍

Great explanation easily understood!!