I'm taking calc 2 for the second time, and of course, it's online which makes it even harder. My professor barely explains anything (like how to calculate the K value...) You have been an absolute saviour thus far!! I love how you always explain each step and explain very clearly. Thank you so much! I think I can pass the class this time:)
i know im randomly asking but does someone know of a trick to log back into an instagram account? I was stupid lost the login password. I appreciate any tips you can offer me.
Bro u r the only tutor that teaches us step by step, my math teacher is like always skipping steps cuz apparently all my other classmates are geniuses and I'm just dumb. Thanks again man!!!
I'm taking Calc 2 and am preparing for my second test. Our text (probably the same one you use) has the answers you showed according to the book. I kept coming up with your answer (the more accurate way). I spent 5 hours trying to figure out what I was doing wrong. Then I found your video and now know I had the more correct answer all day! I have watched many of your videos and you do a great job. Thank you for making the videos. The videos have a timeless value. Even 5 years after making this one, it still works for students.
YOU ARE THE ABSOLUTE BEST!!!!!! I got the same answer you got and couldn't for the life of me figure out how the back of the book got their answer. you make this SO clear!!!! thank you so SO SO much!!!!!!!
You are awesome brother! I read the chapter and I asked my teacher for help but he did a terrible job explaining !! You did it in 7 minutes .. you save me, thank you.
Here I was doing this exact question thinking I was crazy for getting this answer again and again. Thank you for showing both ways to find K! What were they smoking when they wrote this chapter? It's easy to calculate without a graphing calculator, yes, but sooo wrong.
The book's way almost feels lazy, but the intuition behind it is pretty interesting since you don't have to use a calculator. This video was very helpful.
seems like a recursion issue to me. Went from estimating cos x^2 to estimating some craziness just to get a k value for an estimation. One would need to estimate the maximal again and again, ad infinitum.
Thank you!! You are amazing I was doing my homework and keep getting it wrong because I was using the none book way but thanks to you I was able to get my homework done❤
where does the 12n^2 or the 24n^2 come from. My profs notes say that for midpoint on a single interval is (k/4x1-x0))*((x1-x0)/n)^2 and for composite (k/4x1-x0))*((x1-x0)/n)
What if the question asked to find min number of subintervals of int of (x)dx,x from 1 to 2 for error from true value to be less than 10^-4? Using either Simpson or trapezoid rule.
uses crt; type TFunc=function(x:real):real; function f(x:real):real; begin f:=cos(sqr(x)); end; function trapezoid(f:TFunc;a,b:real;n:longint):real; var i:longint; h,s:real; begin h:=(b-a)/n; s:=f(a)+f(b); for i:=1 to n-1 do s:=s+2*f(a+i*h); trapezoid:=h*s/2; end; var esc:char; a,b:real; n:longint; begin clrscr; repeat writeln('Podaj przedzial calkowania'); readln(a,b); writeln('Podaj liczbe iteracji'); readln(n); writeln(trapezoid(@f,a,b,n):1:10); (* In some versions of fpc we dont need at operator and function call will look like this writeln(trapezoid(f,a,b,n):1:10); *) writeln; esc:=readkey; until esc=#27; end.
Mmmmmm... The error bound approach it''s ok ...but a better approach is to use truncation error as shown in this video ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-dYN-ZbJwRjE.html ? For me, it makes more sense the use the truncation error in order to estimate the N value for the trapezoidal/Simpsons rules instead of the error bound. Would you agree ? Thanks.
