Even and Odd Functions 

This video is only about 6 minutes long and it helped me more than my professor could in 40 minutes.Thank you so much!

OMG...my teacher made this appear to be like rocket science, this guy is FANTASTIC! Thank goodness for you tube and people who can really explain a process.

Beautiful, this short 5 minute video is straightforward unlike the rest of the videos. Thank you.

Dude.... thank you so much. You are so much better at explaining this stuff than any of the T.A.'s at my school.

Sir u are a great teacher and help students out when their own teachers cant teach.

omg thank you i finally understand how to do this

Good Video... I have a test in 30 minutes and wasnt too clear about even, odd functions and this helps greatly!

i have a test on all this and you explained it a heck of a lot easier than my teacher :) thank you!

I paid $190 for a textbook that made this super confusing. My goodness, youtube is amazing. Thank you!

This video helped me understand much better! Thank you for your help! math test is monday. thanks once again.

You're the real MVP

This is amazing. Thank you. I am so tired of math teachers making everything so much harder than it needs to be. Thank you for making it easier.

Thnx for the video ...I really learned the process of determine even or odd function with only one view... Excellent teacher!

jesus christ that was easy, cheers dude :)

yes sir this helped a lot. my teacher took a day explaining this, i didnt get it. and now i got it in 5 min just by watching your video.

thanks you so so so very much. you have shaved like 2 hours off my study time, and probably helped me get an A on this test :)

What a great video you have out together!. Thank you for taking the time to explain this in such a clear way =)

Thank you my man, you saved me bout couple hours worth of struggle

Thankyou soooo veryyyy much. This saved me in my finals. I was struggling with this before I saw your video. Thanks again. :-)

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Thankkk youuu, I saw it after 15 years❤

9 years later and still helpful

Thanks a lot dude. it seems like im actually learning more on youtube than i do in lectures

This was so helpful!! Thanks for the video.

It is positive because once you change that first x value (x^6) into -x then the negatives cancel out because it has an even root. Other than that, everything else is positive as well. Hope that helped.

Thanks from Kazakhstan!

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Great video! Big help for my exam

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Fantastic very well explained

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Great teacher!

Funny how this 5 minute video explains this concept more clearly than a one hour lecture, Thanks a bunch man.

f(x)=sqrt(x) f(-x)=sqrt(-x) Since sqrt(-x) doesn't equal sqrt(x), f(x) is not even. Since sqrt(-x) doesn't equal -sqrt(x), f(x) is not odd. Thus, f(x)=sqrt(x) is neither.

Thank you so much!!!! This what such a clear explanation

great thanks alot very clear and practical and understandable

Extremely helpful.

i need this for our prject. :D thanks !

honestly im an advanced student and nobody simply told me 'plug -x in, if its the same thing it was, its even. if its the opposite of what it was, it's odd. if it doesnt match either, it's neither. a very easy concept commonly made difficult.

Thank you so much! Wish you were our video class teacher in BJU or A Beka! :)

Great explanation.. Thank you so much!

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Thank you lifesaver! Same with other people. my teacher isn't very good at explaining....

Thanks Man i realy appretiate it

damn finally a person that can explain this well!!!! jeeeez.... thnx a lot sir

Be careful. (-x)^2 means (-x)(-x) which goes to just x^2. Thus, we get 2x^2 for the middle term.

great explanation!! thank you very much. keep up!!

I'm attempting to determine whether or not the square root of x is even, odd or neither. I am assuming that since the square root of x looks like x½. and since there cannot be a negative under the radical it is an even function? Please confirm or deny if possible

question for number 3:... the second to last equation you wrote out = -x^3 + 2x^2 -1.......... wouldnt that 2x^2 be a negative??? Correct me if I am wrong. I need to understand why it is positive.

thanks! this helped so much

Great video. It would have been nice to see the graphs of even and odd functions though

How can you determine algebraically if the function is symmetrical across a certain line, eg. x=2?

Thank you this really helped

what do you do when their is no negative to factor out of the f of x when looking for negative f of x

thank you for explaining this, it really helped! and it was very easy to understand! :D

THANK YOU!!

helps a lot! thanks!

What happen to example 2 3(-x)^2 =3x^2? Is it not -3x^2?

Thank you, very helpful:)

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Infinite thanks !!!

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Thank you so much

Thank you!

HOLY BALLS. Thank you. My teacher sucks.

you're gold dude

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Thanks for your help full video

THANK YOU SO MUCH

Thank you sir!!!

where did those x came from :(

Thanks for the vid!

what if the equation is y=1-cos(x) does that mean that this one is neither??

wait for example 3) how did u get from (-3)[in the power of]2 + 2(-x)[in the power of]2 - 1 ---> -x[in the power of]3 +2x[in the power of]2 -1 ... isnt it supposed to be -x[in the power of]3 + -2x[in the power of]2 - 1 ??

if only i had found this before the test :P

thank you man!

THANK YOU VERY VERY MUCH :)

thanks Randy

holy cow this was easier than I thought. My teacher made it seem very hard =/

how to determine if it is symmetrical?

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why math is hard ? are we going to use this in our real life ?

Thanks man

@kristijanadrian For the common student learning pre-calculus, neither is a valid answer. You may be correct, but that won't help you with doing a test for a pre-calculus teacher.

The reason 2x^2 is positive is due to BEDMAS, the exponent -x^2 becomes positive and then all one has to do is put the 2 in front of the question, resulting in a positive 2x^2.

this helped me thanks a lot ;)

Thank you soo much :)

Thank you

Has anyone ever told you you sound EXACTLY like Casey Affleck? P.S. Great video.

Thanks man!

And they say you have to get use to prof and there ability to speak english thanks man :P