When you substitute z=1 into the equation 3z + (2+I)w = 11-i, it becomes: 3(1) + (2+I)w = 11 - i, 3 + (2+I)w = 11 - i. Now, let's solve for w: (2+I)w = 11 - i - 3, (2+I)w = 8 - i. Dividing both sides by (2+I): w = (8 - i) / (2+I). To simplify, we can multiply the numerator and denominator by the conjugate of the denominator, which is (2-I): w = (8 - i)(2 - I) / (2+I)(2-I), w = (16 - 8i - 2i + i^2) / (4 + 1), w = (16 - 10i - 1) / 5, w = (15 - 10i) / 5, w = 3 - 2i. So, when z=1, the solution for w is 3 - 2i.
Sir, it's a humble request please start 1st years computer sir please JB bhi koi problem Hoti hai to uska solution aap k paas hi hota hai sir please is problem ko b solve krdein qst year ki computer start krdein please 😭🙏
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but maybe when we made eq( iii) amd we already have eq (ii ) or any eq. we have to add but when we aqtually made eq( iii) and (iv) from i and ii then we need to subtract
As for subtract and add Dekho agr opr or neche wale ke sign same hai tou subtract hoga e.g s se same s se subtract or agr sign change ho as you know change ko hum alter bhi kehte hai tou a se alter a se add yea method use kr sakte ho ap
Sir Q1 k part 2 me 17:15 duration of time me ap ne a²-b² wala formula use q nh kia jb k whn pe lgra hy ye formula or ap ne part 1 me lgaya bh hy. To kia hum use kr skte hn formula?
Sir app nai q no 1ka q no 2 jo dosri eq hai os mai jaha apnai kha hai kai sing change hoti to mai to sign change kardi but - - to + hota apnai kha + or likha -phir bhi apnai q solve kasy kardia 😮 plz ak bar koi dekhlai
1:29:36 sir ap na 3/34 ko shift kiya to us ka sign change nhi kiya baki sab theek tha Anyways thank you for this video Edited : sorry for complement because ap na mistake 10 seconds baad sahi kr di 😂☺
Sir, it's a humble request please start 1st years computer sir please JB bhi koi problem Hoti hai to uska solution aap k paas hi hota hai sir please is problem ko b solve krdein qst year ki computer start krdein please 😭🙏 😪