Factorisation | ONE SHOT | Chapter 12 | Class 8 | BYJU'S 

NAME : POSHALI HAVE ANSWER 🙋🏻‍♀️🙋🏻‍♀️🙋🏻‍♀️🙋🏻‍♀️ HOMEWORK QUESTION : 4yz ( z2+6z−16 ) ÷ 2y ( z+8 ) ANSWER : => 4yz ( z2 + 8z − 2z − 16 ÷ 2y ( z + 8 ) => 2z [ z ( z + 8 ) − 2 ( z + 8 ) ] ÷ z + 8 => 2z [ ( z + 8 ) ( z − 2 ) ] (z + 8) => 2z ( z − 2 ) => 2z^2 - 4z THANKYOU 😇😇😇😇 MA'AM I'M NEW TO YOUR CHANNEL 🙋🏻‍♀️🙋🏻‍♀️🙋🏻‍♀️🙋🏻‍♀️ BUT SAW YOU MANY VIDEOS 😀😀😀😀 AND YOUR TEACHINGS ARE SUPER, SUPER, SUPER, AMAZING. 🤩🤩🤩🤩 AND FUN IN ALL CLASSES 🎉🎉🎉🎉 AND ALSO ALL TEACHERS ARE ALSO AMAZING 👩🏻‍🏫👨🏻‍🏫 AND HAVE THEIR AMAZING 🎊🎊🎊🎊 METHODS TO TEACH. 📚

Hi mam I'm Himanshi Homework question's answer Q- 4yz(z²+6z-16)÷2y(z+8) (Frist cancel the same term) =2z(z²+6z-16)÷(z+8) (Then we have to do splitting the middle term method) =2z(z²-8+2z-8×2)÷(z+8) =2z[z(z+8)-2(z+8)]÷(z+8) =2z(z-2)(z+8)

Homework Question Answer:- 2z(z-2) The Session was very nice! 😊 These sessions are really a guide for my revision preparation. Thank-you Team Byju's for your efforts! Good going! Keep up the good work! 😊

You're the best maths teacher

1:08:19 mam in the first question the answer that i got is 5y( y - 4)-2z( y - 4) mam is this correct of am i doing wrong 1

33:16 (iii) is so easy It is crystal clear

Hello Mam I am Breme, The answer of HW question is 2z(z-2). I want next session on TIME AND WORK. Pls byjus team take my name, i have never been hw star. Thank you mam for this awesome session ❤❤

Great to learn from byjus Thanks Arsh maam ❤

Mam taught better than my teacher in school

Your teaching are so good

mam you made this chapter so easy to understand ❤

Mam , can you please minimise the use of hindi,but your class is 👏 🎉

Ma'am from my calculations I got the answer of homework question 4yz(z^2+6z-16) / 2y(z+8) as 2z(z+4)

ma'am I wish you were a maths teacher in my school, I really liked your way of explaining. I love u mam❤❤❤❤❤❤❤❤❤❤❤❤❤❤

Hi byjus. This session was amazing.... It helped me a lot. But I have a complain... I give every answer in every class correctly but then also I am not h.w star till now... Hence, Today's homework answer 2z(z-2) But byjus is the secret of our energy.

Hello mam i understood everything but , the problem no. 3 factorise following 40:38 can this answer be 2a (-2a + 2b -2c ) ?. Please solve this confusion please 🙏

Please teach Simple and Compund Interest

So good explanation thank you for teaching

I finished this one shot in half hour in the speed of 2x before one day of exam 😅😅😅😂😂

Hello Ma'am Homework answer is 2z(z-2) Maam super duper session Thanku so much ma'am

1:01:27 see the answer 1:06:24 see the answer both are different

Thank you ma'am so much for making us understanding 🤌❤️

1:03:40 Mam the number we find is -6 and 2 but you written 4

ans a4yz (z2+6z-16)

Hi mam My name is Himanshi Mam this is so easy but I lost marks because of my silly mistakes

My maths teacher will never reach this level of teaching Thank u Arsh mam ❣️❣️❣️❣️

Your teaching was clear and effective, but I would appreciate it if you could minimize the use of Hindi. Thank you

2z(z-2) btw thank you so much for clearing it😃

Thanks

The answer of the Homework Question is 2z(z-2) Step 1 4yz(z^2 + 6z - 16) ------------------ 2y(z+8) Step 2 2z(z^2 + 8z - 2z -16) ----------------------------------------- z+8 {Here we cut 2y from 4yz and just splitted the middle value) Step 3 2z[{z} (z+8) {-2} (z+8) --------------------------------------- z+8 Taking z+8 as common in the numerator, we get 2z(z+8)(z-2) ------------------------ (z+8) We cut z+8 from z+8, we get 2z(z-2) as our final answer The session was very useful 🔥but one thing I found confusing like you told factors of 2xy are 2 into x into x but that's the factorisation as we wrote it as product of prime factors not simply wrote 2, x and y so these must be factors that is 2, x and y not 2×x×y is it correct ma'am? And ma'am in 1:15:35 you have written wrong signs in denominator. Sorry ma'am I wasn't able to write answer yesterday Ma'am in the next session I want you to make menti quiz for Exponents and Powers, Mensuration, Direct And Inverse Proportion and Factorisation as it is coming in my unit test.

Middle term split is really really complicated 😅

Hw ans 2z(z-2)

yes mam

Mam really u teach very stupendous just in one shot 😊

Hii mam i actually like your video❤❤❤

47:21

Mam I dont understand fourth identity How i understand can you tell me please mam

Mam after listening to this video I had clearly understood this chapter

Your side view is ❤

Mam answer is : 2z^2 - 4z

15:42 😅Shree Ram😂

The answer of the Homework Question is 2z(z-2)

Mam my ans is 3ab(4a+5b)

Mam but a^2+b^2≠(a+b)^2

Hey Mam will the power prep course session videos available on this youtube channel

Mam your are the most beautiful teacher ❤ not only in looking but also in explaining the concept. ❤❤❤❤ * l ❤U*

12z(z−2)​ ------------ z+8

2z(z-2) ans

The session was amazing

my fav line it is halwa🤭😀

yes

👍👍👍

MA'AM PLEASE BRING A SESSION OF MATHEMATICS CH - 8 ALGEBRAIC EXPRESSION AND IDENTITES NCERT SOLUTION BECAUSE MY UNIT TEST ARE COMING SOON AND NEED THIS CHAPTER NCERT SOLUTION PRACTICE. 🖊🖊📚📚 I WANT TO SCORE HIGHEST IN THIS TEST ALSO, 📋📋📋📋 THIS IS A HUMBLE REQUEST TO YOU 🙏🏻🙏🏻🙏🏻🙏🏻

[1:06:35] Ha Ma'am

2z(z-2)

yesssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

Ok

Hi

Mam 2

By Gurasees Kaur Homework ans 2z(z-2) Thankyou

,🙏👍👍👍👍👍👍👍👍

,👍👍👍

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Hi😮😮😮

mam

Mam even south Indian and other people who can't understand your mother tongue "Hindi" ...... is seeing this video This is the main big request for the whole team that not to use hindi......

Hw question Ans :- 2z (z-2) This season is very helpful to me😊 And ❤Thank you ❤for this season❤ Explantion is perfect and very clear😊☺👍👍👍

4yz(z ^ 2 + 6z - 16) Spiliting the middle term = 4yz[z ^ 2 - 2z + 8z - 16] (Since - 2 + 8 = 6 and (- 2)(- 8) = (- 16) ) = 4yz[z(z - 2) + 8(z - 2)] = 4yz(z - 2)(z + 8) :. 4yz(z ^ 2 + 6z - 16) / 2 * y(z + 8) = (4yz(z - 2)(z + 8))/(2y(z + 8)) . = 2z(z - 2)

Hi mam I am Riddhi ANSWER: => 4yz (z2 + 8z2z-16÷2y (z+8) => 2z [z (z+8)-2(z+8)]÷z+8 => 2z [ (z+8) (z-2)] (z+8) => 2z (z-2) => 2z^2 - 4z THANKYOU for this nice , intresting and awesome , mind-blowing session . I really enjoyed this session.

can you use english CC plzz

stop using hindi

1:01:19 answer is wrong

Please communicate in English , I can't able to understand hindi please

So good explanation thank you for teaching

2z(z-2)

thank mam

HI