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Factors 10 || Number Systems || Quantitative Aptitude || CAT Preparation 2024

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Number System by Ravi Prakash | Quantitative Aptitude for CAT 2024
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CAT PREPARATION 2024
How to Prepare for Quantitative Aptitude
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24 авг 2024

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Комментарии : 77

@VishalThakur-gx3ji 3 года назад

In between lecture I look at you and think that I wish I have the similar mind like you ...I would have cleared all the exam 🤣

@ss590 11 месяцев назад

Even I imagined this each & every time I look at him.....even just for that 1 day.....🙈

@FunkyyKidsTV 18 дней назад

Yes even me too😂😂😂

@nityanandamaji645 3 года назад

4:58 An absolute brilliance! I knew the concept of abcabc form, but never thought like this. I couldn't stop myself but comment

@shrutigupta-fk1rm 4 года назад

When you solve a question, I don't get single doubt. You are amazing sir

@alokkumargupta3121 4 года назад

N=a^1*b^1 isnt it possible if n has 3 factors??

@nef_nef 4 года назад

@@alokkumargupta3121 The only number which has 3 factors is a square of a prime number

@genialassaulter3855 3 года назад

@@alokkumargupta3121 No

@master__oogway777 Год назад

Sir,you dropped this 👑.

@monishmoolya8919 Год назад

Drop dezz nuts

@siddharthsuman3429 5 месяцев назад

Sir in the first question how come 1001a and 1001b are there as there should be 1000 and not 1001. Please help

@samirgandhi8838 4 года назад

One of the best teachers out there

@gauravagrawal2826 8 месяцев назад

sir in 1st question we can also take 101101 as the 6-digit number so it will also give: 7*11*13*101, and 101 is 3-digit prime number having 2 factors. So at the end ans will come as 16 factors

@Sockwards 4 года назад

if i write 33333333 as 3*11*1010101 and then according to what you taught, all prime numbers except 2&3 are of the form 6k+-1, then I can check that 1010101 is equal to a form of 6k+1 where k=168350; thus making it prime. so maybe what you said about all prime numbers being of the form 6k+-1 does have cases where it fails

@swapneelrao8276 3 года назад

Bro, it's not like that. All the prime nos. are in the form of 6k+-1 but reverse is not true which he has clearly explained. If you want to cross check, even 25 is of the form 6k+1 but that doesn't make it prime. Hope you got it!

@shubhamjaiswal1031 Год назад

sir you told, "please remember everything i say not a single word is out of context".. Our response as students- "Roger that ! Captain"

@Colonel9898 2 месяца назад

Love you from Andaman Nicobar 🇮🇳

@ManuSrivastava_ 2 года назад

Thank you so much sir.❤❤

@ranjanagehlot9631 4 года назад

Great concept sir! Thank you 🙏

@PrinceKumar-ju6sd 2 года назад

thank you very much sir for your efforts 🙏

@shivamkumar-ey1kw Год назад

facing problem to splite the big no like 33333333......

@navishek6550 Год назад

Your lectures are really helpful than k you

@lakhyadas1345 3 года назад

can somebody help me out in understanding if n.o of factors having 2 is prime and having 3 factors is also prime

@bewithpallabi3120 2 года назад

Areh obviously, think about it how can a non prime 3 digit number can have 3 factors, obviously that will have more factors than that.

@kailashbalodi9899 2 года назад

@@bewithpallabi3120 thanx for this

@pratyush5172 2 года назад

prime no has 2 factors i.e 1 and the no itself, but if we square a prime no. then we have 3 factors i.e. 1, the no itself and the prime no. that is squared. NOTE: squaring a prime no will make it a composite no since it'll have more than 2 factors now but only numbers with 3 factors are squares of prime except single digit numbers 4 & 9.

@rupashreenth 2 года назад

Thank you so much sir. You are the best 🙏❤️

@sneak_peakkkk Год назад

how can i access the quiz?

@ThatMBAstudent 6 месяцев назад

11:11💫

@cumulusmusic100 11 месяцев назад

Thank you Sir🙏

@ironmanwillbeback5541 Год назад

How can I access the quizzes???

@yashmehrotra6726 10 месяцев назад

last question use ABCD=3333 its easier

@guitarunique4592 4 года назад

Great content

@deepakgulia3863 4 года назад

Thank you sir

@kshitijbalonie4361 4 года назад

Thankyou sir

@rohitagarwal7466 2 года назад

Cam anyone explain about what concept he talking about in last question in 23:13

@merohan619 7 дней назад

Sir had already discussed some hard number and their factorization in prev video. Sir is using the same thing to apply it here.

@spkbusinessD-- 2 года назад

shivam kamat (35) 20-9-2021 thank you sir 🙏

@shubhampipara1259 4 года назад

How would be find factors when digit is repeating odd no. Of time times? Like 7777777

@vedantmishra3697 4 года назад

Have u got the ans dude, if yes then pls tell

@shubhampipara1259 4 года назад

@@vedantmishra3697 no bro i guess this trick works only in even no of numbers

@harshitbhadouria6536 4 года назад

answer is same 32f

@harshitbhadouria6536 4 года назад

16f****

@sakshamgupta3276 3 года назад

@@harshitbhadouria6536 how?

@rajdebnath9681 2 года назад

Sir we can do this sum in simplest way 8f*3f=24f

@AkankshaSingh-wy5yq 3 года назад

cant we just put 3 in place of pqr and solve for the factors further without putting any prime square or something because it is already mentioned that pqr has 3 factors. @13:00

@nikitayadav5236 3 года назад

exactly! coz sir already mentioned that prime numbers only have 2 factors

@yes3635 2 года назад

You guess are preparing for 2021?? How much syllabus did you covered (probably all) I completed only 30% i still have time??

@Gautam_OG 2 года назад

10:00 24:00

@user-cr8me9im7g Год назад

in pqr has 3 factors 2 cases are done. why not third case where =7x11x13x(p1xp2)?

@venkatreddyreddy6924 10 месяцев назад

P1 and p2 no.of factors will be 6 . But in the question they have given only 3.

@janhvivish8536 3 года назад

how is it 1001? please explain

@AkankshaSingh-wy5yq 3 года назад

10^3 a + a = 1000a+1a= 1001a

@yes3635 2 года назад

I don't know why sir stretched it so much every prime repeating number divided by orginal number gives 101. For eg 1313÷13= 101, 131313÷13= 1001

@edifier_shay 7 месяцев назад

Thank you sir for the wonderful lecture! i am gonna crack CAT 2024 easily!🎉 i have made a study group for cat aspirants, details are in the about section of my channel.

@deepthigoud7996 Год назад

16:14

@rajvirsingh2599 3 года назад

Can someone please explain me that how the brackets became 1001a 1001c 1001c?

@poonamarya9965 3 года назад

Same doubt

@naina2744 3 года назад

Divisibility rules

@singhswapnil283 3 года назад

1000a+a=1001a..nd so!

@AkankshaSingh-wy5yq 3 года назад

10^3 a + a = 1000a+1a= 1001a

@sshvibha 3 года назад

in ABCABC "A" is in 10^5's place (lakh"s place) , "B" IS IN 10^4'S place (ten thousand's PLACE) ,"c" is in 10 ^3 that is thousands place ,10 ^ 2 is in hundereds place .10 ^1 is in tens place ,10^0 is in units place .therefore we can write 10^5 A+10^4 B+10^3 C+10^2 A+10^1 B+10^0 C.separate A ,B AND C TERMS . THEN (10^5 A+ 10^2 A)+(10^4 B +10^1 B)+(10^3 C + 10^0 C ) 10^2 A( 10^3 +1) +10^1 B(10^3+1)+10^0C (10^3 +1) TAKE (10^3 +1) COMMON (10^3 +1) (10^2 A +10^1 B+ 10^ 0 C) 1001 (10^2 A +10^1 B+ 10^ 0 C)

@suryavoroy3527 Год назад

Watch later

@alokkumargupta3121 4 года назад

N=a^1*b^1 isnt it possible if n has 3 factors???

@sjsthomasnick3002 3 года назад

If N=a^1 * b^1, then number of factors = (power of a + 1)(power of b + 1) Which becomes number of factors = 2*2=4 So any number of the form a^1 * b^1 will have 4 factors and not 3 factors. A number having 3 factors will be of the form N = a^2. Number of factors = power + 1 So, power = no.of factors - 1 Hence a number having 3 factors is of the form a^2