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FDR - Storey's method and q values 

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See all my videos at www.tilestats.com/
1. FDR and BH method
2. Storey's method (01:20)
3. Estimate the FDR (02:38)
4. q values (09:22)
5. Storey vs BH vs Bonferroni (13:48)

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19 ноя 2021

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Комментарии : 15   
@hdrevolution123
@hdrevolution123 2 месяца назад
tremendous lecture. Thank you so much
@dmitriidoroftei4478
@dmitriidoroftei4478 6 месяцев назад
Omg, you saved my exam Big Data and Analytics exam of tomorrow, thank you, super helpful (watched all 3 vids)
@tuskofgothos2637
@tuskofgothos2637 10 месяцев назад
Your channel deserves more subscribers! This channel is definitely not a false discovery 😂.
@nudibranchia3773
@nudibranchia3773 2 года назад
Your videos helped me to understand the whole concept of FDR so fast. Thanks a lot!
@tilestats
@tilestats 2 года назад
Great!
@unbridled_exciton
@unbridled_exciton 2 года назад
Great video! Thanks for sharing!
@nadee1005
@nadee1005 Год назад
amazing explanation, thank you.
@Mr1Kr
@Mr1Kr 2 года назад
Very clear. Thank you.
@mikhaeldito
@mikhaeldito 2 года назад
What is the reason behind the lack of adoption of Storey's method? I rarely see it in papers.
@tilestats
@tilestats 2 года назад
The BH has been around longer and is easier to implement. Also, Storey's method requires that you have a very large number of p-values so that you can analyze the distribution of these. That might be a few reasons.
@willw234
@willw234 2 года назад
Thanks for the informative video. But be careful - Storey's method can break down when a large proportion of the null hypotheses are false, see "Paradoxical results of adaptive false discovery rate procedures in neuroimaging studies", Neuroimage. 2012 Dec;63(4):1833-40. doi: 10.1016/j.neuroimage.2012.07.040. Epub 2012 Jul 27.
@tilestats
@tilestats 2 года назад
Thanks for sharing your knowledge. I wish I had included that Storey's method might reject more H0 than if one uses the unadjusted p-values, if a large proportion of the H0 are false, which is the nature of the FDR.
@shiyiyin3403
@shiyiyin3403 2 месяца назад
The only use of the first part of the calculation (8:48) was to get the m0 from lambda? in other words, it is saying p=0.05 is q=0.0739. The second part (10:37) uses m0 to calculate all the q-values from largest to smallest. I wonder if one can calculate specific q-values, just using the first part of the math. Say p= something, I should get the q for that p. why use the part 2 math to calculate when part 1 is working great?
@user-gi5ld6iw2q
@user-gi5ld6iw2q Год назад
How to code it in R
@tilestats
@tilestats Год назад
Use the package qvalue.