You are indeed correct...... my bad.... thanks for pointing it out ..... however, in this case, it does not change the answer because all it does... is add C' to the AxA' term ..... and AxA'xC' is still zero... best wishes 😊
There is a COMPOUND rule that allows you to remove the c' ..... and I not only gave it to you in another video, but I actually provided the proof by breaking it down using the simple basic steps.......so here is the compound rule ..... A +A'B = A + B .... (note A' gone .. for good 😁)..... here is the proof ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-vSH5eusYiVg.html
@@tonzaifavour I try to respond to all questions on all my videos ..... does not matter how old they are .... I would not be able to do this if my channel had 100K subscribers with loads of comments each day .... but it's small enough that I can still handle all the comments that come in each day 👍
@@StephenMendes I might be wrong but I think (AB + C)' = (A'+B') * C' . You somehow got A' + B'C'. I don't understand what you did. (prime means there is a bar)
@@MalekaParvin-z4k It is YOU who do not understand .... both sides of the above equality have the identical truth table .... IF you know how to "find a truth table from an expression" ? ..... so there must be a flaw in your understanding of that