FIND GIVEN NUMBER IS PRIME OR NOT IN JAVA

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26 сен 2024

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Комментарии : 21

@EDU_Chu 24 дня назад

Actually we have to add a count variable and initialise to 0 and update after each divisible and if count == 2 print prime else non prime. In the particular program if gives u even or odd rather than prime and non prime.

@srikanthpelluru9994 22 дня назад

The for loop makes the difference. We are checking from 2 to given number -1. Of anything is divisible, then we are printing not prime and returning the cursor. It works for all the scenario

@vishaljadhav4652 2 месяца назад

package JavaProgms; public class primeOrNot { public static void main(String[] args) { int num = 5; int count = 0; if (num > 1) { for (int i = 1; i

@nxplusgaming3583 5 месяцев назад

Bro 9 is not prime but this programme is give output as prime It's just printing even and odd

@SiriSreeTechTutorials 5 месяцев назад

I’m not sure why you guys get such wrong output. For me it is working fine. Please do double check the program

@nxplusgaming3583 5 месяцев назад

@@SiriSreeTechTutorials no bro program is right i was wrong sorry 😔

@vishaljadhav4652 2 месяца назад

package JavaProgms; public class primeOrNot { public static void main(String[] args) { int num = 5; int count = 0; if(num > 1) { for(int i = 1; i

@nileshgurung9437 9 месяцев назад

What if we put 2

@SiriSreeTechTutorials 9 месяцев назад

Then this will get fail… I notice that and expect the question from followers. Before if, we should check the value is greter than 2 or not, if not then print as not prime and return..

@himanshulowanshi5121 8 месяцев назад

This program is even odd numbers

@SiriSreeTechTutorials 8 месяцев назад

If it is even odd number program, I would have written (num%2==0) condition, why we need for loop before this condition. And then I am verifying (num%i == 0) That makes this program as prime or not