Find The Area X, Of The Yellow Region Of The Square.

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Make Some line constructions. Label and join points. Locate the diagonal of the square and its adjacent angles. Use The Proerties Of Triangles, Trigonometry, Pythagora´s theorem And Measurement of plane shapes to find the required area of the yellow region.
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Опубликовано:

16 сен 2024

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Комментарии : 9

@PS-mh8ts 2 дня назад

It can be shown that if A and B are the areas, the area of the yellow region=AB/(A+B). With A=2 and B=4, we get: (2)(4)/(2+4)=4/3 square units.

@psykomarvin 15 дней назад

in your video : ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-aPcjW9TQAiQ.html the values on your problem are wrong, if BE is parallel to OF then the radius is "√10" and AB is "√10 minus √2" and not just√2

@psykomarvin 15 дней назад

or if AB = BO = √2 (so the radius is 2√2) CD & CB must be different : you must have CD = "2" and CB = "√7 minus 1"

@Center1ForMathematics 15 дней назад

Thank you for your great concern. Already, you should know that the given figure is a sector of a circle with a radius, R = 2√2 units and angle 135°, subtended at the center of the circle. I do not know where you got such information. The value of the radius is, already, been given. What left for you is to figure it out from the diagram. Parallel lines are not always, suppose to be in a horizontal position from your argument. They could be in vertical position, as well. BE and OF are straight lines and because CB is perpendicular to BE; such concept are extended to lline OF. Please, the radius is already been given in the figure.

@psykomarvin 15 дней назад

@@Center1ForMathematics try this and you will see the problem : put a dot M on BE so you have the square CDMB, now a dot N on the arc so the line ON cross the dot M and the angle AON is 90° and because BO is √2 so BG = GM = 1 so BM = CD = 2 and not √3 and radius must be √10 and AB = √10 minus √2 and is longer than BO. it's impossible to have the square CDMB in the quarter circle AON and AB = BO at the same time

@psykomarvin 15 дней назад

if we look closely we can even just visually confirm that AB is a little longer than BO on the video

@Center1ForMathematics 15 дней назад

@@psykomarvin Let me be sincere with you. You cannot be commenting about a question on another question. Are you commenting about a trapezium inscribed in a sector which subtends an angle of 135° at the center of the circle? Please, refer to the exact question(video). Also, you can attached a clear daigram of your solution and sent it www.mazananews.com/contact/ for easy explanation and understanding. Thank you for your good gesture.