You can use the pH at equivalence to figure out the Ka of the acid that was titrated. Be careful ... rounding errors can be costly here so don't round until the very end. Check me out: www.chemistnate...
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can I start doing it with Na+ instead of CN-? would it make any difference if I am doing so? also the number of steps would drastically decrease so why didn't you just started with it?
+Monkey D. Luffy As long as one of the reactants is strong the reaction will go to completion. In this case NaOH is a strong base so the reaction will go to completion even though HCN is a weak base. You almost had me trippin burh.
This may seem like a very confusing concept, however for titration related problems, you must consider the "total" volume/amount used. 20 mL of NaOH (Base) was added to 20 mL of HCN (Acid) to titrate the acid, so the total amount is 40 mL.
I think of it more like a "dilution" concept. When you titrate the base, you're not just adding the base, you're also adding water. The new volume of the water would be the volume of the water in the acid and the volume of the water from the base you just added. Therefore, the volumes are additive.
