I have this one question where there is a coffee (85°C) and a milk (35°C). The specific heat capacity for milk is 1.5 times the specific heat capacity of coffee. The mass of coffee is twice the mass of milk. I need to find the final temperature of the milk and coffee mixture..
You would do it the same way as in the example, except that you don’t have values for mass or C. But since every term in the equation contains both a mass and a C, you can leave them as expressions. Coffee: C Milk: 1.5C. Coffee: 2m. Milk: m So -2mC(T-85) = 1.5Cm(T-35) Since C and m are contained on each side of the equation they can divide out, leaving only one variable (T) to solve for.
