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Fischer to Haworth shortcut for Glucose and Fructose 

Leah4sci MCAT
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28 сен 2024

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Комментарии : 8   
@ursamajor5744
@ursamajor5744 4 месяца назад
Is it because D-glucose’s hydroxyl groups are in equatorial position, so it is more stable in that conformation?
@Leah4sciMCAT
@Leah4sciMCAT 4 месяца назад
Exactly 💯
@fatts96
@fatts96 2 дня назад
amazing explanation, u saved me once again!
@Leah4sciMCAT
@Leah4sciMCAT День назад
I'm so happy to hear that!
@kroliia3116
@kroliia3116 2 месяца назад
What happens to the purple “H” that’s attached to the red “O” that attacks?
@Leah4sciMCAT
@Leah4sciMCAT 2 месяца назад
Good question! The red "O" becomes deprotonated in solution and loses that purple "H". It is no longer a part of the structure when glucose is drawn as a Haworth projection.
@ShikahAlmuharif
@ShikahAlmuharif 27 дней назад
This really helps me thank u sm ❤
@Leah4sciMCAT
@Leah4sciMCAT 20 дней назад
You're so welcome!
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