Yes this one is also great! Like the explaining of the two transistors cirrent mirror which is so full of different new insights to learn. These lessons in wich a circuitway is explained are full of lightbulb-lightingup-above-my-head-moments. Great and superusefull lesson, again!
@@sambenyaakov these lessons in wich you dig deeper into a circuit, explaining the reasons or options for some designchoises, these lessons i find always the most full with tons of knowledge, full with new ways to get insights. Also old things get finally clear while listening to these totally clear explainings. Like that lesson about the inner circuit of the 741, so full of things that were so often usefull i'll never forget anymore. At least for me these are so learnfull, it's a joy to follow. Ow i just wanted to say thanks for all this great teaching from your knowledge wich is so usefull and interesting for us.
Thank you for the video. Since the feedback is instantaneous voltage, how would you do the bode plot measurement? Where to insert the stimulus in this case and sense lines?
Very good Dr. Sam, we learn a lot from you, I do have a question no related to the subject, is why we can not put large filter at the input of Schmitt trigger inverter , or how can I figure the maximum capacitor value I can use to avoid shoot through for the CMOS inside the Schmitt trigger.
I used LM25180NGUR before. If you don't have the zener diode on the output side, the output can go very high voltage without a load. This causes an issue when production tests the board.
Hi Doctor Sam, A few questions would like to discuss with you 1. Could you please tell me why Ib could set the Ip current, do you have an example? I am confused with that 2. why do we need to use two PMOS or BJT to do that? why I cannot just only use two resistors R1 and R2 in my circuit, without PMOS I still can get the Vs voltage right? 3. In the DCM, the reflect voltage and voltage have a 0.5V error, how do deal with that error? 4. Why MPS's device can just only use two resistors to detect the output voltage and don't need to use transistors.
I would look at them as sort of matched pair, the left one is "controlled" by a constant current source. At start-up the left (and right) side are not conductiing. But the constant current source on left side drags down the voltage of left mosfet gate away from Vin = it will start to conduct at some point. It will not conduct more than 200uA set by current source though. The same gate voltage is applied on right side gate. The Right hand side mosfet will also conduct but it's Vds will vary proportional to the voltage swing it is experiencing due to the primary switching cycle and voltage divider set resistors as it is (automatically on it's own) balancing (or basically locked in by the fixed fixed gate voltage) trying to "match" the left hand side. I hope it helps... it's hard to describe with just text.
