Question in 13:15: Since vmax=λ/(4*Tc) it follows that Chirp B will have half the maximum measurable velocity than Chirp A (we assume that Chirp B has twice the Tc of Chirp A). However Chirp A and B will have the same velocity resolution :)
In the slide at 7:43 do you actually mean pi/2 instead of pi? because in the third case it can be regarded as (about) -145° and fulfills abs(omiga) < 180°
As long as we can guarantee that abs(omega) < 180 degree, unambiguous velocity estimation is possible. Without this constraint the third case has two solutions : +215 degrees or -145 degrees. With the constraint that abs(omega)
Why do we measure phase changes over 2 CHIRP cycles and not on the phase difference of the transmission signal to the phase of the received signal? It doesn't make sense, we are testing 2 transmission signals regardless of the components of the surrounding objects
The reason for measuring phase changes over 2 CHIRP cycles is to mitigate the effects of noise and interference on the measurement. In a radar system, the transmitted signal is reflected off of objects in the environment and the resulting signal is received by the radar receiver. The phase of the received signal depends not only on the distance to the object, but also on the path length of the signal, which can be affected by reflections, refractions, and other interactions with the environment. As a result, the phase of the received signal can be noisy and may not accurately reflect the distance to the object. By measuring the phase change over 2 CHIRP cycles, the effects of noise and interference can be averaged out, resulting in a more accurate measurement of the distance to the object. This is because the phase change over 2 CHIRP cycles is proportional to the distance to the object, and any noise or interference that affects the phase of one cycle will cancel out when the phase change over two cycles is calculated. In other words, by measuring the phase change over 2 CHIRP cycles, we are able to reduce the effects of noise and interference on the measurement and obtain a more accurate estimate of the distance to the object.
