Japanese | Can you solve this? | Math Olympiad

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10 сен 2024

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Комментарии : 7

@thelifeclass 25 дней назад

Interesting 🎉

@prollysine 26 дней назад

by fakt. , (b-7)(b^3+7b^2-65b-456)=0 , b=7 , b^3+7b^2-65b-456=0 , (b+8)(b^2-b-57)=0 , b=-8 , b^2-b-57=0 , /// b=(1 +/- V229)/2 , roots are not integer , /// , evaluation , a=b^2-57 , case₁ , b=7 , a=49-57 , a= -8 , case₂ , b= -8 , a=b^2-57 , a=(-8)^2-57 , a=64-57 , a=7 ,

@MasterTMathsClass 24 дня назад

Nice one

@prollysine 24 дня назад

@@MasterTMathsClass Thanks ! I would like to understand math better, thank you for the many valuable tasks!

@MasterTMathsClass 24 дня назад

@@prollysine Good to hear. You're welcome.

@thelifeclass 25 дней назад

Interesting 🎉

@MasterTMathsClass 25 дней назад

Glad you think so!