Hey, MicroStudy here, and oh wow, thank you so much for the unexpected feature! I was completely caught off-guard when it popped up in my sub box hahaha So the intended step for the ending involved the step you touched on earlier in the solve. In the bottom left corner, you successfully figured out that R9C1 (of the inner grid) couldn't be in the same region as the outside clue. The same thing applied for R9C7 and its outside clue, which causes it to have a 1 clue outside and either a 2/3/5 region inside. With a bit of thinking (I'll leave this as an exercise to the reader haha), it would end up being forced to be a 2 region which should smoothen the blow of the ending a little bit :) Another thing I'd like to point out was the top right corner didn't have to have a domino on there. I will admit, this is one of the more unforgiving sections of the puzzle. But the key thing to note was that regardless of whether R3C9 (of the inner grid) was a 2 or a 3, it always causes R3C8 to be a 4, which should remove all the "big region" options that were a bit hard to visualize. Nevertheless, I really enjoyed watching you solve it! The epiphany on the bottom left was quite a joy to see, and I do apologize for making you hungry!! You definitely deserve a feast after that.
When I got to that point I simply deduced that R9C7 had to be a 2 or 3; after that I could tell that in both instances R8C9 had to be the last 6, which sorted out the rest of the puzzle. Fun solve for sure!
Let's Get Cracking: 05:32 Simon's time: 1h10m15s Puzzle Solved: 1:15:47 What about this video's Top Tier Simarkisms?! Scooby-Doo: 1x (24:38) Diddly Squat: 1x (15:44) And how about this video's Simarkisms?! Ah: 26x (06:07, 08:30, 09:17, 09:43, 10:15, 10:38, 14:40, 14:45, 17:42, 17:45, 17:45, 18:55, 27:23, 27:28, 29:21, 31:52, 31:52, 31:52, 35:24, 36:12, 39:59, 41:05, 41:27, 43:44, 48:16, 1:05:58, 1:07:10, 1:11:37) Hang On: 16x (04:38, 16:49, 18:55, 27:28, 27:28, 27:28, 30:40, 35:08, 36:37, 37:57, 54:57, 54:57, 56:42, 59:31, 1:04:05) Sorry: 9x (09:02, 09:47, 17:48, 34:07, 35:24, 47:29, 56:47, 56:47, 56:47) Wow: 6x (17:08, 38:35, 45:12, 57:06, 1:03:49, 1:15:46) Good Grief: 5x (01:22, 04:24, 36:50, 49:08, 58:01) Clever: 5x (09:23, 09:23, 19:06, 36:09, 1:10:14) Beautiful: 5x (15:22, 36:50, 48:21, 48:23, 49:08) In Fact: 5x (37:12, 40:23, 44:13, 53:08, 1:15:59) Bother: 4x (26:48, 28:56, 1:03:39, 1:07:43) Nonsense: 4x (15:23, 23:10, 26:58, 56:51) Brilliant: 4x (00:41, 1:01:44, 1:01:45, 1:15:20) Obviously: 4x (18:06, 19:34, 20:39, 23:53) Surely: 3x (31:50, 1:12:29, 1:13:15) What Does This Mean?: 3x (42:32, 45:15, 1:07:21) What on Earth: 2x (11:14, 15:44) Stuck: 2x (15:11, 1:01:48) Pencil Mark/mark: 2x (50:55, 1:06:25) The Answer is: 1x (24:29) Lovely: 1x (19:25) Break the Puzzle: 1x (38:49) Elegant: 1x (1:15:29) Off and Running: 1x (12:03) Take a Bow: 1x (1:16:15) Flurry of Activity: 1x (43:16) Puzzling: 1x (1:16:17) I've Got It!: 1x (09:21) Plonk: 1x (59:48) Chromatic: 1x (15:23) Fabulous: 1x (1:15:52) That's Huge: 1x (34:35) Have a Think: 1x (50:36) Serendipitous: 1x (58:17) Weird: 1x (34:48) Most popular digit and colour this video: Four (210 mentions) Green (14 mentions) Antithesis Battles: Even (3) - Odd (0) Outside (7) - Inside (2) Black (5) - White (1) Row (12) - Column (11) FAQ: Q1: You missed something! A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn! Q2: Can you do this for another channel? A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
Easier way to finish it: At 1:08:35, Simon thinks about the last clue at the bottom row. At this point, how can that clue be anything other than 1? If it is bigger than 1, it must grow to the cell above, then we are saying something like: "put 2 at row 8" or "put 3 at row 7" or "put 4 at row 6" etc. Clearly none of these work for that column. So, it must be 1. Simon also finds out that, it would be 1, in the hypothecated scenario, after thinking, 1:09:10 . He just did not realize that it's the only option.
I think the conclusion at 27:15 was not the most eloquent moment, but I believe the main reason it breaks is that we would send a 4 to the cell that is restricted to 237.
Yeah that logic confused me although he is right. Putting a 4 there would force a 4 in the out of grid cell directly below due to the 4 found four cells above. But your proof is much easier to grasp and leads to the same deduction.
@@xfan420bush9 no it could have also been a 5 or a 6. I don't see anywhere in the rules that it has to point to the *first* instance that we see the digit
It's possible to show at least that there are no larger-than-digit-sized regions that interact with the clues in any way*-the room indicies cannot be larger than 9 or they'll point off the grid, and if a clue cell had a number greater than 9 in it its region would have to cross over an index cell (and therefore break) since there are at most 9 clue cells available on a side. *I am not sure if a large central region that just doesn't get seen by any of the clues is ruled out, though seems like it'd be tough to fit in
You probably wouldn't be able to make such a puzzle unique. A variant of this with a 10 as the pointer could be fun, where the 10 then says "the clue on the opposite side of the grid is the same as the one next to this cell"
@@christophdietrich4240 Yeah I went back and forth on the uniqueness, couldn’t quite rule out the possibility of surrounding say a 10 cage with enough different size regions that it can’t be subdivided without same-size regions touching, but yeah that would be part of the challenge…
Is it to be assumed from the start that all numbers entered into a cell are from 1 to 9? Seems like it since that is what the app allows but that is not actually stated in the rules.
It's not necessary to assume it here. There have been fillomino puzzles featured in the past where regions have been greater than size 9, even though the software doesn't allow a number larger than 9 to be entered as a "final" number. You just have to get creative and either enter them simply as pencilmarks, or use hexadecimal letters.
78m27s. This was my first time working with numbered rooms, the interplay with filomino made for some interesting deductions, though I feel like I used ariadne's thread/proof by contradiction a whole lot more than I wanted to
took me 75 minutes to solve this one. i found it quite difficult. i've been working on more of these puzzles myself before watching the videos now that i have more free time, and i'm surprised by how consistently my times are to simon's.
66:25, welp, I was able to solve it. I think my biggest hurdle was remembering that the digits "outside" of the gird had to by in x sized regions, so had to merge with other cells (unless it was a 1).
Has Simon not done a numbered rooms puzzle before? He seemed less than confident during the rules section. Mark has certainly done a few on the channel, but I wouldn't have guessed it was 100% of them...
As far as I know, he's only actually done one Numbered Rooms puzzle on the channel. This was last year and it had letters and stuff, it was a bit hard for him to follow back then as well if I remember correctly. These types of puzzles are hard lol.
I broke my puzzle because I did not consider the possibility of a t tetromino in the bottom left corner. Had to look up what I did wrong EDIT: had to come back two more times to figure out what logic I failed :(
can we get a video where you solve the puzzle real time without trying to explain to us... like you are in a competition and all the complex logic in your head you use... then an explanation video reacting and explaining the first step
classic, at 16:20 trying to figure out if it can go one way (and believe to prove that it can), but doesn't bother trying to prove if it can go the other way
Well, that sent me down an interesting Google rabbit hole. I particularly enjoyed reading an article called "Don't you dare use 'comprised of' on Wikipedia: one editor will take it out". 😁 (RU-vid apparently doesn't like it even if I just gave the name of the hosting website.)
@55:00 you say, ”May be I can prove these are the same" about the vertical domino in the top right. Unless I missed it, I don't think you ever do prove this conjecture, but you assume it to be true from then on. Edit: @1:00:13 you claim "We know these are the same". I don't think you've proved that.
I think the proof that they are the same stems from the fact that the upper cell cannot be 1. It must therefore grow downward, making both cells the same. I didn't do a careful analysis on the orange cells adjacent, so maybe this idea could fall flat once they are considered.
@@siegel880 At this stage, I think the upper cell could have been a 6 and grown to the left and the lower cell be a 7 (or 8) and grown downwards. It fairly quickly runs into problems with the third 4 down the right, but Simon doesn't show this.
Simon: "Let's take a closer look at cell X" .... Simon does something else. Simon a bit later: "Let's take a closer look at cell Y" ... Simon does something else. A bit later: "I don't want to bifurcate" ... Starts bifurcating. Also Simon: tries one value for a cell that has two options; doesn't get anywhere; does NOT try the other option. .... I've now lost my voice because of all the yelling at the screen. 😀
57:40 rather than prove that the top-right corner vertical domino digits are equal, it was assumed. My question is, why cant the top one be red while the bottom one became 2? That is the only possibility for them to not be equal. The reason is that, should the top one be red, the bottom one being 2 would mean that the next cell over is 4. Then red is either 4, which contacts the off-the-grid 4 region, or larger, which it is blocked from being by pre-placed digits and the presumptive digits just below it.
Numbered rooms are a bit tricky, I think, a type of indexing that I have to keep saying aloud to myself in order to remember what is referring to what. I enjoyed watching you solve this one, Simon, despite how mysterious some of it seemed to me!
I finished in 146 minutes. I need some help at first, because I'm not used to Fillomino rulesets. After watching Simon do the first set of numbers, I started to get the hang of it. This is a fun puzzle, but my lack of experience really slowed me down. I did make it through, though. Although, the possibility of 1s was my biggest enemy. Great Puzzle!
For the finish, starting at 1:06:00, I looked at the outer edge cell next to the 6. What can that be? It must be a number that appears in the column. It cannot be a 6 (already next to a complete 6). It cannot be a 4 (would run into a completed 4 region getting out). It cannot be a 2 (getting out would cause a run of three 2s). A 3 doesn't work because it would cause a run of four 3s. The only number that works is a 1. Then the "index" number cannot be a 5 (no room to build a 5 region in the corner), so it must be either a 2 or a 3. Playing with the 3 option you'll find that doesn't fit in the corner.
I got about 60 minutes in and broke the puzzle. I rewound and spent another ten minutes trying to find my bad logic but couldn't. Either going to start over or just watch the video to see what I did wrong. Edit: after a full reset (keeping my time), I ended with a time of 147:05. Great puzzle, I loved it, I just wish I hadn't broken it the first time. I never figured out where I went wrong with it, but I got the solution in the end.
I messed up several times on this one, and thought my time was awful; but was pleasantly surprised to find my time wasn't too far off Simon's. Nice puzzle :D
A more elegant solution for the end: The rightmost digit of the last row is either a one or the same as the one above it. It's easy to work out that it has to be a one. Now the digit above the one is either 2,3 or 5. It cannot be 5 because of space constraints 5 would then be transported from the final column to a place it cannot go. It cannot be 3 because you couldn't fill the bottom digit of the final column then
At the end I thought the cells left. There are 10 cells left one ist a 4 and one is an 8 - so 8cells left. And then what are possible regions - with These you can exclude all except the right regions
doesn't the 4 in row one require a 6 in r1c9 far earlier than it's placed? I haven't finished watching and it's surely possible that I'm the one missing something but...edit, I guess there could be other 4s that make that cell not a 6?
