A mass of 10 kg is at a point A on a table. It is moved to a point B. If the line joining A and B is horizontal, what is the work done on the object by the gravitational force? Explain your answer
If the body is kept on the table horizontally to A - B WILL ALWAYS BE NORMAL OR CREATE 90 DEG. IN RAIDIANS ( PIE/2) AND ALSO IF THE BODY 'S WEIGHT IS 10 KG OR 10 THOUSAND KG WORK DONE = FS WORK DONE = FS COS THETA FIND OUT (90) AND IF FORCE IS GIVEN ALSO THE COS 90 OR PIE /2 VALUE IS 0 SO IT WILL BE MULITPLIED OR DIVIDE THE TERM WILL BECOME 0 SO WORK IS NIL THE WORK DONE SHOULD NOT BE IN 90 DEGREE IT'S FROM THE COOLIE'S MENTOR IS FAMOUS ANS -0 FOR YOU ALSO IF WE CONVERT 10 KG F = Mg NOW FORCE = MASS 10 × g can be 9.8 or 10 ALSO SO can be 98 or 100 and later on by multiplying you will get the work done 0 by horizontal slope between y and x axis to the point and point B.
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