Gene Cloning - Past Year Questions | CSIR GATE

Подписаться 234 тыс.

Просмотров 6 тыс.

50% 1

In this video I have discussed about Gene Cloning past year questions asked in CSIR and GATE entrance exams.
Please watch Gene Cloning Part 1 here - • GENE CLONING In Detail...
In molecular biology, cloning a gene means inserting the sequence of the gene into a plasmid, which is a small piece of circular DNA that can be "transfected" into a bacterial strain, where the plasmid will replicate to many, many copies. The plasmid carries an antibiotic resistance gene, so when the bacteria are grown in the presence of the antibiotic, only those bacterial cells with the plasmid in them, can multiply.
This allows molecular biologists to easily propagate and grow vast amounts if the gene, and also to manipulate it in many ways, for example to introduce mutations to study its function, etc.
Please watch this video for more detail. If you like this video please like and share this video, and don’t forget to subscribe and click on bell icon for new videos.
Subscribe: www.youtube.co....
Related Videos:
DNA Cloning | Part 2 - Enzymes used in Gene Cloning • DNA Cloning | Part 2 -...
DNA Cloning Part 3 - DNA Modifying Enzymes | Nucleases • DNA Cloning Part 3 - D...
DNA Cloning Part 4 - Restriction Endonucleases • DNA Cloning Part 4 - R...
DNA Cloning Part 5 - Linkers and Adaptors | DNA ligation | Recombinant DNA Technology | In Hindi • DNA Cloning Part 5 - L...
#Genecloning #CSIR
#BaaYo

Опубликовано:

26 сен 2024

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист

Посмотреть позже

Комментарии : 34

@BaaYo 8 месяцев назад

To access notes and practice questions, please join our Telegram channel t.me/baayo_official

@inlandsea929 2 года назад

Desperately waiting for your lecture .... haven't seen the teacher as u r❤️ love 💕

@sandeepkalita7125 2 года назад

Thank you Ma'am. Please continue your lectures. Best wishes for you Ma'am.

@kanupriyasingh8714 2 года назад

Pls come up with more such pyqs as it is very helpful and off course the way u teach is amazing, I can quickly understand the concept.

@GhulamHussain-bw9tj 2 года назад

Once again not related to my subject. However Understood the entire lecture. Teaching methodology is soft and based on deep knowledge. A lot of respect ma'am from Pakistan.

@BaaYo 2 года назад

Thank you

@satyajitchowdhury3350 2 года назад

The answer to question no 11 is Option C. From the map we can see the the total size of the vector along with the insert is 3000+2000=5000bp(1kb=1000bp). When BAM H1 and Hind III cuts the construct we get one fragment of 500bp as it was told in the question that the insert has a Hind III site at 500bp downstream from its first codon and the Bam H1 site is at the beginning of the insert. So we get a band at 500bp and another band at 5000-500=4500bp=4.5kb which is in option C. And in case of Hind III and Pst1 digestion we first get a 1500bp(1.5kb) length band as Hind III site is 500 kb upstream of the first codon and Pst1 site is at the end of the insert. And the total length of the insert is 2000bp. So the band length should be 2000-500=1500bp=1.5kb. The other band will be of 5000-1500=3500bp=3.5kb in length. In the options C justifies all these. So C is the right option.