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Harvard University Admission Question| Can You Solve For x? | Algeria 

Spencer's Academy
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In this video, I'll be showing you step by step on how to solve this Harvard University Admission Problem using a simple trick.
Please feel free to share your ideas in the comment section.
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24 сен 2024

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Комментарии : 5   
@aryanuddin1903
@aryanuddin1903 4 дня назад
x=-6
@mrinaldas9614
@mrinaldas9614 5 дней назад
At the the qusrtic stsge z& Z^4 could have been replsced by k^2 (k =z^2).
@SpencersAcademy
@SpencersAcademy 5 дней назад
Yeah. I had already made one substitution. I didn't want to introduce another substitution.
@yurenchu
@yurenchu 5 дней назад
(x+9)⁴ + (x+11)⁴ = 706 ... let u = x+10 ... (u-1)⁴ + (u+1)⁴ = 706 (u⁴ - 4u³ + 6u² - 4u + 1) + (u⁴ + 4u³ + 6u² + 4u + 1) = 706 2u⁴ + 12u² + 2 = 706 2u⁴ + 12u² = 704 u⁴ + 6u² = 352 u⁴ + 6u² + 9 = 361 (u² + 3)² = 19² u² + 3 = ±19 u² = -3 + 19 OR u² = -3 - 19 u² = 16 OR u² = -22 u = ±4 OR u = ±i*√22 x+10 = -4 OR x+10 = +4 OR x+10 = -i*√22 OR x+10 = +i*√22 x = -14 OR x = -6 OR x = (-10 - i*√22) OR x = (-10 + i*√2)
@SpencersAcademy
@SpencersAcademy 5 дней назад
Fantabulous heart 👏
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