Тёмный
No video :(

Henderson-Hasselbalch equation | Acids and bases | AP Chemistry | Khan Academy 

Khan Academy
Подписаться 9 млн
Просмотров 173 тыс.
50% 1

Keep going! Check out the next lesson and practice what you’re learning:
www.khanacadem...
One way to determine the pH of a buffer is by using the Henderson-Hasselbalch equation, which is pH = pKₐ + log([A⁻]/[HA]). In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution. When [HA] = [A⁻], the solution pH is equal to the pKₐ of the acid. View more lessons or practice this subject at www.khanacadem...
Khan Academy is a nonprofit organization with the mission of providing a free, world-class education for anyone, anywhere. We offer quizzes, questions, instructional videos, and articles on a range of academic subjects, including math, biology, chemistry, physics, history, economics, finance, grammar, preschool learning, and more. We provide teachers with tools and data so they can help their students develop the skills, habits, and mindsets for success in school and beyond. Khan Academy has been translated into dozens of languages, and 15 million people around the globe learn on Khan Academy every month. As a 501(c)(3) nonprofit organization, we would love your help!
Donate or volunteer today! Donate here: www.khanacadem...
Volunteer here: www.khanacadem...

Опубликовано:

 

22 авг 2024

Поделиться:

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист
Посмотреть позже
Комментарии : 28   
@n.k.3405
@n.k.3405 3 года назад
THIS CHANNEL HAS BEEN UP FOR YEARS AND YET THEY'RE STILL POSTING VIDEOS... AHHHHHHHHHH
@L_Lawliet1907
@L_Lawliet1907 2 года назад
They’re one of the biggest education platforms lol
@yourlocalscribe948
@yourlocalscribe948 2 года назад
@@L_Lawliet1907 los santos
@Bedlaminhavana
@Bedlaminhavana 4 месяца назад
What an amazing, short concept video. Thank you!
@azca.
@azca. 2 года назад
1:50 - How did you get the Ka value?
@arthurchan4277
@arthurchan4277 2 года назад
google. it should be given if you need it on an exam.
@MrBoomington
@MrBoomington 3 года назад
We actually had to prove this equation in the A-level exam. Yeah been 2 months now I kinda forgot it lol
@randomvideos4296
@randomvideos4296 2 года назад
What exam board?
@reemalzubaidy6037
@reemalzubaidy6037 2 года назад
U sound like Sheldon from Big Bang theory thank u
@divyasingh8147
@divyasingh8147 2 года назад
Such a good explanation I hve ever seen.
@reginakatilo7032
@reginakatilo7032 Год назад
The lesson was cool... Thanks 😊
@mothman663
@mothman663 3 месяца назад
Thank God for Khan Academy...
@yaminaboub-jo2lb
@yaminaboub-jo2lb 3 месяца назад
Thank you , this is really helpful
@Logan-tg5we
@Logan-tg5we 11 месяцев назад
yet again another video I have wasted time watching that doesnt include how to calculate acid and base concentration for the equation. 7 min of my life I will never get back, thank you so much for not helping in any measurable way.
@xinyi9118
@xinyi9118 9 месяцев назад
dont be a debby downer
@micaelawillet8760
@micaelawillet8760 5 месяцев назад
you can use an ice table. There are other videos that explain how to find the h3o and oh concentrations.
@charliebrett7510
@charliebrett7510 3 года назад
At 3:50 I’m confused. I thought a weak acid partially dissociates into its ions in an equilibrium EQUALLY in a one to one ratio e.g CH3COOH->CH3COO- + H+. So the concentration of CH3COOH ALWAYS equals the conc of CH3COO- providing the volume of the buffer solution is constant. As m=cv c=m/v and so same moles/Same volume should give same conc for both CH3COOH and CH3COO- each time? Why is it 6 and 4? Can someone please explain?
@dawsonlin5929
@dawsonlin5929 3 года назад
Weak acids dissociate into their ions at an equilibrium based on their Ka value, so they don't always dissociate into a one-to-one ratio all the time. Furthermore, a buffer solution is formed by mixing a weak acid and its conjugate base, the concentrations of which are up to the scientist conducting the experiment. This buffer solution happens to have a ratio of 6 to 4, so he is calculating the pH in this particular scenario. Hope this helps!
@charliebrett7510
@charliebrett7510 3 года назад
@@dawsonlin5929 so to recap, weak acids can dissociate into even amounts of their ions or uneven amounts of their ions based on their Ka. So in a calculation you would have to know the moles of the ions it dissociates into and the weak acid separately as there is rarely a 1:1 ratio. And thank you so much!
@Protimonride
@Protimonride 3 года назад
Thank You. 🖤
@syedashobnam2573
@syedashobnam2573 10 месяцев назад
Or u can think it like this more conjugate base = more basic and higher pH, more acid= acidic solution less pH.
@LINKJW
@LINKJW Год назад
thank you!
@subhamkarmakar3320
@subhamkarmakar3320 2 года назад
Nice
@sapphireherkimere128
@sapphireherkimere128 2 года назад
What to do if there is a x10 on the pKa given to us while finding the pH, example is pKa = 1.28 x 10
@thomasrimer1611
@thomasrimer1611 2 года назад
That just means the pKa is 12.8 1.28*10=12.8, that is scientific notation
@L_Lawliet1907
@L_Lawliet1907 2 года назад
Like the other guy said, it’s just scientific notation. Just move the decimal place to the right by one.
@eliasnakhle8534
@eliasnakhle8534 3 года назад
MATH
@SD33396
@SD33396 3 года назад
Hi sir
Далее
MCAT Chemistry: Henderson Hasselbalch How To
22:51
Просмотров 2,2 тыс.
Buffer Solutions
33:21
Просмотров 1 млн
Henderson-Hasselbalch equation derivation
7:24
Просмотров 58 тыс.
Buffer Calculations
7:11
Просмотров 136 тыс.