Macho, habemos muchos que el lenguaje de los gringos, ni papa, ósea que te pongas las pilas y pienses en los demás que no tenemos ni idea del ingles. Un saludo, suscrito y LIKE.
Am I correct to say this is basically a joule thief? I can never get a joule thief to work but the way you did it here help me understand it better. I am going to try it.
its a type of joule thief, if never worked for you it's probably because you don't wind the coils at the same direction, also you can do it with a 555 timer easyer.
Simpler stationärer Aufwärtswandler, wie er in Elektroautos eingesetzt wird. Aber schöne Veranschaulichung! Bitte auch mal mit dynamischen Betrieb aufbauen 😃
boost converter need a feed back system so that voltage wont drop with change in load (duty cycle will increase / decrease with change in load). this can be use to demonstrate boost converter but its efficiency will be very low which mean your cell will be dead with in mints.
if u switch the position of inductor and transistor, and flip the diode so it blocks positive voltage from battery to caps, the rise in voltage won't be accompanied by currrent draw from battery, which simply means more output than input.
@@ruksanaparveen6342 I tried this and it works to boost the voltage stored in the capacitor as shown. In a practical application, a higher frequency, automatic cutt-off such as an oscillator would take the place of the manual switch. To see an example of a simple automatic circuit, google "Joule thief"
Sir could you please tell about inductors and wire gauze and magetic core how to find for example 3.7v to 5v boost converter to make in this regard how to calculate. Plz suggest
If it goes above 20v why doesn't the LED gets burnt out , last time I used 9v battery on a 3v led , it gets damaged , please explain sir , I'm in confusion
From this video I learned those voltage ratings for components arent accurate, more like minimum voltage with a rated wattage, he put a 20v source on one diode...
Please someone answer my question. I tried to make this but my wires were too small to carry any current from my battery, my battery was fine and it would send current through a 14 guage wire. But how can it pass through the inductor when the wire making it is so tiny
@ Tech Ideas Can you make with high output voltage like from 12 v DC / car battery (30 amps input), out put DC voltage around 35 and 48 volts with 5 and 10 amperes output Can make a video with circuit Diagram ?
A way late response but biggest role in here is MOSFET or BJT and also Coil to get higher amperage you would need more turns on Primary coil and Feedback coil and you need to use more expensive MOSFET or BJT that have high switching speeds higher the switch speed better the performance also you need high capacitance Capacitor so it can hold bigger charge. basically high switching speed will provide more power in general and will charge high capacitance capactior really fast high capacitance combined with better coil and mosfet or bjt will give much more power in the end when running on load also keep in mind the power lost as heat in mosfet or bjt so better cooling on them and youre set its really easy but needs better components hope i helped somehow :)
If that was a rechargeable AA1.5v and it's producing 20v, could any of that voltage be routed to a battery charger for the 1.5 or is amperage too low? If so, it would violate 2nd law of thermodynamics and other laws I don't quite understand but it would produce energy until life of battery but if it's that easy I'm sure someone would have made it long ago then turned it into a weapon
no es un ladron de julios, es un combertidor boost, en el ladron de julios se usan 2 bobinas con una conexion enlazada, en el combertidor boost es simplemente una bobina con sus 2 extremos
Sir ac non tuch testor aisa banye jo 5 miters dur se hi indicket karne lage sir kheto me achanak 230 volt tar gira rahata hai jo hame 5 bar Mar chuki hai sir please 2 din me banaye
