How Can This Possibly Solve?!

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** TODAY'S PUZZLE **
A quite ridiculously beautiful sudoku today from kuraban. Named after the Led Zeppelin song Battle Of Evermore (for reasons that are opaque!), it is almost mystifying that this puzzle can solve uniquely and yet it does!
Have a go at the puzzle here:
sudokupad.app/gPdj8GrQrR
Rules:
Normal sudoku rules apply. Digits along an arrow must sum to the digit in that arrow’s circle. Along a marked diagonal, digits cannot repeat. Cells separated by a single knight’s move (in chess) cannot contain the same digit.
** NEW JAMES BOND SUDOKU HUNT OUT ON 1 APRIL **
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Apart from the new James Bond sudoku hunt, there's:
- Simon's latest forays into the world of Islands Of Insight
- Mark's video looking at the new OneUp puzzle from Rodolfo Kurchan.
- his solve of Region Geometry by Emre Kolotoğlu (3hr 36min long...!)
- Mark's solve of The Times Club Monthly cryptic crossword
/ crackingthecryptic
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▶ Contents Of This Video ◀
0:00 Theme music & puzzle intro
1:52 Please check out our Sudoku Club
2:30 Rules
3:56 Start of Solve: Let's Get Cracking
▶ Contact Us ◀
Twitter: @Cracking The Cryptic
email: crackingthecryptic@gmail.com
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Simon Anthony & Mark Goodliffe
Box 102
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(Please note to use our real names rather than 'Cracking The Cryptic'.)
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Опубликовано:

5 авг 2024

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Комментарии : 156

@GourmetBurrito 3 месяца назад

I would love to meet someone like Simon at a party. A person who can clearly communicate his passions and explain, what is likely to be for him, the most basic "secrets" without being judgemental or patronizing. Sounds wonderful

@vezonn8010 3 месяца назад

I imagine Simon at a party asking you to follow him to a secret room in the back of the building just to tell you that the digits 1-9 sum to 45

@annek3296 3 месяца назад

I also would love to meet up with Simon at a party! (I don't think, though, that there are many like him to be found at a party.)

@BigAsciiHappyStar 3 месяца назад

I would love to perform my unofficial CTC theme song if I ever met Simon at a party 🎵😀

@Stephen-Fox 3 месяца назад

Simon - Basically all of the youtube sudoku solving channels, actually - feel like they embody xkcd 1053. Happy to take people on a journey of being one of the lucky 10,000.

@gandalf_le_rouge 3 месяца назад

Luckily we live in a world of sudoku where Simon might very well be very a interesting person 😀

@kuraban1 3 месяца назад

Thank you Simon for the kind comments. Your memory is quite good. It's just over a year now, and couldn't be happier. Loved your solve. It's no surprise to me that so many people use Phistomefel to solve this, given the initial setup, however it's not necessary at all. Just lots of wonderful coloring. So happy to see so many people enjoying this.

@Paolo_De_Leva 3 месяца назад

Wonderful visually minimalistic construction. Fully deserved to be featured on CTC. 👏👏👏👏👏👏

@Paolo_De_Leva 3 месяца назад

Phistomefel was not needed and I did not use it, but it can be elegantly used at the very beginning of your solve to prove, by contradiction, that the corners of the ring must contain *6-7-8-9.* If there is no *6* in the corners of the *green ring,* by arrow logic there can be only one *6* in the ring: 1 + 2 + 6 = 9, but by diagonal logic you need to place two *6s* in the *orange squares.* This is incompatible with *Phistomefel's theorem:* the green ring and the orange squares must contain exactly the same set of digits. See also *iceberg54321's* comment below.

@sampathkumar-ej7xl 3 месяца назад

The emptyness of the grid was welcoming along with the simple well known rules. I absolutely loved solving it. Thank you

@GuilhermeCarvalhoComposer 3 месяца назад

I loved the puzzle! And I did solve it just by coloring, happy to see that's how the setter thought of it too :)

@arnoudh6203 3 месяца назад

"There is no 5 in this puzzle" "Definitely." ~Simon 2024

@iceberg54321 3 месяца назад

18:43 SImon missed the logic that the corners of the ring had to be 6789 because even if there was one six in the sides, it could not cover both diagonals, (you would need to put two sixes in the corners and could only place one). Also, missed taking out a green 3 flash in row 9. :)

@rubenvanbeesten 3 месяца назад

Yes, exactly what I was thinking!

@Paolo_De_Leva 3 месяца назад

Thanks for pointing this out. I missed it too. So simple, after understanding it. 🤦‍♂ If there is no 6 in the corners of the Phistomefel *ring,* by arrow logic there can be only one 6 in the ring (1+2+6 = 9), but by diagonal logic you need to place two 6s in the Phistomefel *squares,* which is incompatible with *Phistomefel's theorem:* the ring and the square must contain exactly the same set of digits.

@asbjrnfossmo1589 3 месяца назад

@@Paolo_De_Leva Yep, missed it too. That would have shortened my solve by a LOT of time.

@18Wolves77 3 месяца назад

I've never been able to complete a 4* puzzle before... and have been scared away from trying because of that and stick to 2 or 3* difficulty. I liked the look of this puzzle on the video, so gave it a go not knowing how difficult it was supposed to be... and completed it in just over half an hour with no real issues. Opened up many more puzzles I'll now not be scared to try

@Paolo_De_Leva 3 месяца назад

This puzzle was not very difficult. The crucial deduction about *r6c5* was easy to find, in my opinion.

@Babinzo 3 месяца назад

Simon’s recent streak of rotationally symmetric puzzles makes for a visually pleasing experience

@johnh2052 3 месяца назад

For me, the key was noticing that the arrow in box 8 couldn't have a 6 on it (i.e. be 126). If it did, it would force a 3 into R7C9 and that would make two of the centre circles 9s--broken. So, the arrow in box 8 is selected from 1234, giving a quadruple in the row. After that, colouring the 6789s led me eventually to the solution.

@HunterJE 3 месяца назад

16:17 Once again pointing out that for the diagonals version of this proof the "pinwheel" in the cells highlighted here in green is an unnecessary digression (that pattern *is* relevant to the proof for the knight's move version which is I think the source of the confusion), it is sufficient that if a digit does not appear in the phistomefel set it cannot appear on the diagonals in boxes 1, 3, 7, or 9 (since all cells on the diagonal in those boxes are either on the ring or in the 2x2s), and so the copies of that digit on both diagonals are forced in to box 5 and so must be at their intersection to avoid repeating...

@emptyset1312 3 месяца назад

At 36:02 you ask "Is it impossible to put a 1 on all four of these arrows?", and it turns out the answer is actually yes, but the reason why is fairly complicated. But the puzzle will break if we assume that's true. Both the positive and negative diagonals need to have exactly one 1 on them. Since the center cell is not a 1, and that's the only shared cell between the two diagonals, that means that the two diagonals together must have exactly two 1's. However, from the 1234 quadruple in box 5, we know that there's a 1 somewhere on one of the diagonals in box 5. Which means outside of box 5, there is exactly one more 1 on a diagonal. If we're assuming there's a 1 on all four central arrows, then in the corner boxes, the 1's must appear in the outermost 2x2 regions (i.e. the outer Phistomophel regions). But this turns out to break, since we're only allowed one more 1 on the diagonals. Per our reasoning from earlier, we MUST place another 1 on one of the diagonals in the corner 2x2s (since the diagonals together need two 1's). But no matter where we choose to put the 1, it breaks the puzzle. It's a bit hard to describe the general case, but to give an example: if we put 1 in R2C2, we now must put a 1 in R8C1, since in box 7 it cannot go on the diagonal by our reasoning nor in row 2 by sudoku. Similarly, 1 must also appear in R1C8. But now there is nowhere for 1 to go in box 9, and the puzzle is broken. Upon inspection you'll find that the puzzle breaks in a similar way regardless of where we try to place the second 1 on the diagonals.

@zirco77 3 месяца назад

Indeed. That's a key deduction that Simon missed at first then went on grinding its way out with other smaller deductions. Another way of saying it: if you have four 1's in the ring, then you have four 1's in corners. No matter how you place those four corner 1's (still observing sudoku rules), you'll either have 0, 2 or 4 of them on diagonals. But we need exactly one since there's exactly one in the middle box, and that breaks. From there I could color all center and ring 1234's, which then expanded as pairs in boxes 2, 4, 6 and 8. This made placing other digits easier that what Simon had to go through.

@MichelKoopmansch 3 месяца назад

@@zirco77 I agree with you Zirco,the coloring exercise stays more symetrical for a while and makes the solve more joyful I think

@RKelleyCook 3 месяца назад

I feel for the poor miscolored 3 sitting in Simon's row 9 blindspot

@samueldeandrade8535 3 месяца назад

Indeed. :( . Just unacceptable.

@emilywilliams3237 3 месяца назад

Of course this was fun to watch. Even though I have seen dozens of yours and Mark's videos solving arrow/diagonal/knight's move puzzles, I always feel that I learn something from you, Simon. Thank you!

@davidrattner9 3 месяца назад

Every day is a learning experience from Simon and Mark !🙂

@tracydmcgrath 3 месяца назад

This might be my favorite puzzle if all time. Bravo kuraban

@davidrattner9 3 месяца назад

Beautiful puzzle and setting from you Kuraban!!! Loved everything about it! Would so enjoy and cherish meeting you Simon at a Party!!

@kuraban1 3 месяца назад

Thanks David. As always, the real pleasure is just seeing others enjoying solving one of my puzzles.

@pvandewyngaerde 3 месяца назад

Saying Diddly while wearing green reminds me of Ned Flanders (48:54)

@chocolateboy300 3 месяца назад

I finished in 148 minutes. This one felt like is was on the brink of collapsing for what seems like forever. I felt like I was making progress throughout the whole puzzle and it kept resisting. Luckily, coloring and persistence helped me complete this puzzle. I quite liked it, but it was a gauntlet for me. Great Puzzle!

@ericpraline1302 3 месяца назад

I really enjoyed this puzzle, more so than any other for a while for reasons I cannot fully explain. Something about the way it was engineered and the fact that I was able to solve it in a reasonable time no doubt helped. Thanks.

@stevieinselby 3 месяца назад

Fascinating to prove during this puzzle that PotatoHead's law that there _may_ be no more than 1 digit that doesn't appear on the Phistomering in a knights move or diagonal puzzle gets doubled up to there *must* be 1 digit that doesn't appear on the Phistomering in a knights move _and_ diagonal puzzle!

@MatthewMorris6148 3 месяца назад

1:23:45 (With conflict checker, also, fun number). Very cool puzzle. Spotted the ring fairly quickly, and I had a lot of fun coloring. Very pretty board by the end of it.

@TobiasBrown27 3 месяца назад

Same 😁 had a rainbow board by the end. I didn't have to do math until I had a color nailed down for nearly every square. 1:11:34 for me!

@FrancisFjordCupola 3 месяца назад

42:30 in ... "That's a nine! That's my first digit!" says Simon. "Was I that bad?" wonders the five in the center. I always love seeing how much effort genius takes and how much it takes away the ability to see what's right in front. And I'd still love to meet Simon at parties.

@r0bbiegill 3 месяца назад

This took me a long time, but I completed it! Used letters for 5-9 and was able to place all of them. Was able to identify which letters represented five and six and place a few fours. But I really struggled to figure out which letters were 7-9. I finally realized I needed to put the two non-central arrows in conversation with each other. Once I know which circle has an eight and which had a nine, the puzzle flowed very nicely from there. It did take me an awful long time, but I really enjoyed every minute of it!

@HitchHitchHitch 3 месяца назад

There's a tendency for 5s to be the middle digit in a lot of these puzzles... I wonder if Simon and Sven might consider adding a new song and animation to the repertoire... maybe, "that's a.... five in the middle with you"??

@awebmate 3 месяца назад

or "I got 5 on it" ;)

@mathmethman 3 месяца назад

At 15:55 there is a simpler logical path than adding in the green dominoes. If a number is not in any of the blue cells or any of the orange cells but it must be on a diagonal, it therefore has to be in one of the central three cells on that diagonal.

@Pulsar77 3 месяца назад

I had a different break-in using the phistomefel ring. Every high digit (6, 7, 8, 9) must appear on both diagonals. So, is it possible for 6 to go on both diagonals in orange? The answer is no, because then we would have to put two 6s in the blue ring, but not on the blue corners (because those are on the diagonals, each of which already contains a 6). So we would have to put two 6s on a blue arrow, which is impossible. Therefore, there is exactly one 6 on a diagonal in orange, and one 6 on the other diagonal in one of the blue corner cells. The same reasoning applies to 7, 8, and 9 (but we already knew that one of each goes into a blue corner). Therefore, the blue corners of the ring contain 6, 7, 8, and 9.

@zirco77 3 месяца назад

Good one! That's the "alternative" deduction to the "four 1's problem" I went with. Yours is simpler, thus better, as far as "nice break-ins" go.

@Pulsar77 3 месяца назад

@@zirco77 Cheers. I was quite pleased with myself, until I saw that Simon's break-in was 10 times easier 🙂. But it is more general, because it doesn't involve the two extra arrows.

@francoisduez601 3 месяца назад

It's true and I came to the same conclusion differently, but that doesn't prevent to have two 6s in blue and in orange...

@Pulsar77 3 месяца назад

@@francoisduez601 Correct, but it's enough make progress.

@inspiringsand123 3 месяца назад

Rules: 02:36 Let's Get Cracking: 04:02 What about this video's Top Tier Simarkisms?! Phistomefel: 11x (10:08, 16:02, 18:26, 27:22, 27:26, 30:30, 31:09, 31:12, 35:53, 45:14, 45:26) Knowledge Bomb: 1x (07:17) Diddly Squat: 1x (48:54) And how about this video's Simarkisms?! By Sudoku: 11x (06:29, 08:31, 16:30, 39:39, 40:16, 46:22, 47:49, 48:27, 50:08, 52:43, 53:48) Hang On: 9x (22:38, 24:00, 30:20, 45:05, 45:05, 46:27, 50:05) Ah: 9x (13:18, 19:38, 19:48, 21:01, 30:20, 37:25, 42:08, 55:39, 55:39) Brilliant: 8x (39:06, 39:09, 42:13, 42:13, 55:33, 55:36, 56:19, 56:26) Clever: 6x (00:56, 04:16, 04:29, 04:33, 46:37, 56:56) Sorry: 5x (25:24, 26:40, 33:17, 41:50, 41:50) In Fact: 5x (09:36, 12:00, 15:31, 19:48, 42:42) Pencil Mark/mark: 5x (22:05, 37:43, 51:15, 51:17, 51:25) Nature: 4x (29:23, 34:54, 45:44, 45:54) Lovely: 3x (01:31, 01:34, 01:34) Obviously: 3x (02:08, 13:46, 15:10) Symmetry: 3x (01:00, 01:07, 29:43) Triangular Number: 3x (05:44, 20:30, 42:25) I Have no Clue: 2x (14:47, 29:12) Beautiful: 2x (01:23, 24:05) Shouting: 2x (41:53, 41:54) I've Got It!: 2x (39:04, 45:05) Weird: 2x (26:20, 38:03) Good Grief: 1x (24:05) What on Earth: 1x (29:00) What a Puzzle: 1x (55:31) The Answer is: 1x (39:11) Nonsense: 1x (41:26) Missing Something: 1x (29:15) First Digit: 1x (42:33) Take a Bow: 1x (56:59) If I Trust my Pencil Marks: 1x (51:25) Shenanigans: 1x (01:48) Bizarre: 1x (38:03) Proof: 1x (13:08) Whoopsie: 1x (45:46) Box Thingy: 1x (25:48) We Can Do Better Than That: 1x (40:21) Losing my Army: 1x (13:18) Most popular number(>9), digit and colour this video: Sixteen (9 mentions) One (95 mentions) Green (48 mentions) Antithesis Battles: Low (8) - High (4) Even (5) - Odd (1) Row (12) - Column (9) FAQ: Q1: You missed something! A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn! Q2: Can you do this for another channel? A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!

@mstmar 3 месяца назад

i got into a rabbit hole in this one. my middle was completely different from simons. (colors are at 32:00) basically i noticed that if green was 8 then a lot was constrained, so with some investigation, i noticed purple would need to be 1 and yellow would be at least a 234 arrow making yellow a 9. so if green is 9 then red and blue aren't 9s, and if green is 8, then yellow is 9 and again red and blue aren't 9s. this means that red and blue arrows can only contain the digits 1-4. then like simon pointed out at 32:15, if some of the arrow cells are 1-4 then we can place them in the center box. so i went coloring my 1-4s. r3c4 = r6c6 and is in 2 places in box 8. r3c6 = r6c4 and is in the same 2 squares as the prev pair. we can do something similar with r4c3 and r6c3 to color a few boxes. then i decided i just need to show that green and yellow can't have 6's, which would let me color a lot more of the low digits. yellow is pretty easy to show doesn't have a 6, since if it does, purple is 3 and both green and yellow would need to be 9s. so more coloring which gets a lot of restrictions, but in the end it was all about as useful as a chocolate teapot and had to find the restricted high digits like simon.

@artursruseckis4242 3 месяца назад

(Edit: bit messed up, describing the wrong path I did instead of the right one) Yep, I also got the 8-9 interaction due to 8 requiring a 1 on its arrow and its consequences of 1-4 being in red/blue arrows. I was so frustrated that Simon kept asking "wrong" questions, so I scrolled the slider seeking for when finally the 9 will disappear from blue and red. To my surprise, when the digit 9 disappeared, it disappeared from yellow ... I was like "WHAT?!?" Interestingly that my solve from that moment revolved mostly about color coding 1-4, while Simon did completely opposite and color coded large numbers. Two completely opposite paths to same result.

@angec9908 3 месяца назад

I love the knowledge bombs

@ratosphere 3 месяца назад

14 is not equal to 16, it's less

@frankjiang1857 3 месяца назад

Finished in 100:06. Loved how the knight's move interacted with the arrows to create small constraints which added up to the final solve. Since I'm not good at arrows or knights move, I consider it a win to be able to see the interactions. Fun puzzle!

@nochsta 3 месяца назад

Interesting that while either the diagonal or anti-knight constraint means that there can’t be more than one digit not on the Phisto ring, the combination of BOTH rules means that there MUST be such a digit.

@jonathanallan5007 3 месяца назад

When did the old "If I trust my pencil marks ...and I _do."_ become "If I trust my pencil marks ...I might as well; I'll _risk_ it."? @51:20 #lostsimarkisms

@CapKhoury 3 месяца назад

What a solving experience that was. It seemed completely hopeless that it would ever solve all the way through until suddenly, somehow, I was done.

@rigeborod 3 месяца назад

The other way to beak into it is to notice you cannot have four 1s in four corner 2x2 boxes: 1) rule out 1 from Phistomefel corners (because we have at least 3 ones in the ring). 2) On the diagonals 1 cannot be in the center box for both of them, so on at least one of them it should be in the corner 2x2. 3) There's only one 2x2 with 1 on the diagonal (the opposite one cannot have 1 cause of the same diagonal and the other diagonal have its 1 in the center box). 4) Starting with any of 2 diagonal cells in that 2x2 you cannot put more than three ones. 5) This allows us to fill a lot of grid with 1234 or 6789 depending on the cell. 6) After that we can count how many 6789-s we have in our 2x2 boxes on the diagonals: they have two 6789-s each which accounts for all 6789-s in our 2x2-s. That means all other digits which are not on the diagonals in 2x2s are indeed 1234-s. That helps to fill more cells.

@mrrobotman5299 3 месяца назад

You can pretty easily prove the nature of the 9 arrow by trying to place 4 ones in the corners after proving Phistomefel. It can't be done therefore the 9 arrow is 2, 3, 4

@Gonzalo_Garcia_ 3 месяца назад

30:41 for me. I got the idea for the break-in pretty fast, but going through all the colouring wasn't easy at all. Great puzzle!!

@matthewphillips5911 3 месяца назад

That was a brutal solve. Not gonna lie, I had to go to Simon for insight a couple of times I got stuck. Very satisfying finish though.

@shiftyhexahedron7891 3 месяца назад

Took me just over 112m. What an elegant puzzle.

@yaelvercammer5468 3 месяца назад

01:29:49 - artificially slow because I was in a meeting at the same time. Couldn't resist the fun look of this puzzle - symmetry is always so pleasing :D

@TheClawNinja 3 месяца назад

I agree with the title of this video...??? How? Can't wait to watch this one.

@Mephistahpheles 3 месяца назад

Didn't get far, but pleased with myself for figuring the inner 9 arrow had to be a 234 right at the start: 7, 8 & 9 have to go in the Phistomophel ring corners. If 6 isn't in a corner, it must be on BOTH diagonals in the outer boxes of Phistomephel....putting two 6's on the Phistomophel ring. The 2nd would break the diagonal or an arrow.

@Pulsar77 3 месяца назад

Yep, I had the exact same idea! It's quite beautiful, really. A shame that it didn't turn out to be necessary to solve the puzzle.

@AndreAy1975 3 месяца назад

Solved it with much help from the video.

@JohnGottschalk 3 месяца назад

I feel like the same thing is happening here as in the squishy sudoku.

@CastorQuinn 3 месяца назад

The most beautiful geometry of the year so far.

@timcampbell9871 3 месяца назад

I think the key point that Simon missed was that if there are 4 ones it’s impossible to put a 1 on exactly one of the corner diagonals; you can either do 2 or 0. This confirms 9 = 2+3+4, and lets you easily color all the digits 5-9, leading to a very satisfying finish.

@titusadduxas 3 месяца назад

1:37:58 - I did restart it again after my colouring got confusing and by using letters I was able to fill in most of the grid. The disambiguating at the end proved a bit harder for me but I got there in the end.

@joakrage3972 3 месяца назад

I think it felt like it would have been easier to colour the 1234 quadruple in the middle box as soon as that was possible

@srwapo 3 месяца назад

61:27, like 20 of those minutes were staring at the grid and not seeing a pair I pencil marked in box 7 ruled out of the pairs I pencil marked in box 4 thanks to the knight's move. You'd think me going through the Chess Sudoku app would have made my brain better at catching these things.

@darreljones8645 3 месяца назад

Technically, Led Zeppelin's song "The Battle of Evermore" refers to a scene from "The Hobbit". A similar pattern holds for the name of another "Led Zeppelin IV" song, "Misty Mountain Hop".

@martinbull-gundersen8878 3 месяца назад

Very cool puzzle. You really didn't need Phistomefel for this (at least I didn't use it). I was lucky and found that AK sudoku on Simons yellow 789 quite early. I also noticed one thing that Simon overlooked that helped a lot: Simon did say that the tip of the arrow in column 9 had to be a 1 if green was 8, but he missed what that meant for 9 in box 5. It meant that if green was 8, yellow wouldn't have a 1 on the arrow, and had to be 9. But again - very nice puzzle and nice solve!

@artursruseckis4242 3 месяца назад

Wow, did not expect this. I went completely different path than Simon did, in fact - completely opposite. After the obvious break-in in center box, I asked question - what are the consequences of green being 8? Eight must have 1 in it, so it forces the pink arrowhead to be 1 (the 1 in box 6 serves the inner boxes 8), and that in turn makes the yellow arrow sum to 9 (can't have 1 on arrow any more). So we have established, that in central box 9 can go in only two places - either it is green sum (R5C6), or if it is not, then R5C6 is 8 and that forces yellow sum (R6C5) to become 9. So we can release 9 from other two sums, which forces them to have only small digits in their arrows. At that moment I start color coding them and everything unfolds very nicely. So I was quite frustrated that Simon could not see the effect of 1 in 8 sum for such a long time, I started to look in scroll bar previews for when the 9 will disappear from two other sums ... instead of that the 9 disappeared from yellow R6C5... I was shocked. So instead of proceeding with knowledge that 9 is not in red and blue, Simon proceeded with fact that 9 is not in yellow. But not only that. My solve revolved around color-coding the small digits (1-4), which nicely revealed that R6C9 is the digit that is not in 1-4 range, Simon proceeded with color-coding large digits... wow, two completely opposite paths to the solution...

@kuraban1 3 месяца назад

Cookie coding the small digits was my solve park when testing this. I saw that Phistomefel could be used, but you definitely described my intended path.

@piarittersporn 3 месяца назад

Brilliant puzzle.

@Moolers 3 месяца назад

This was kinda easy, but still a lot of fun.

@awebmate 3 месяца назад

I agree, nice relaxed medium hard puzzle with no particular break-in and no hard thinking required.

@Squishy3757 3 месяца назад

Look at that 6789 ring around the puzzle!

@JoRo-hw8dl 3 месяца назад

I only stumbled across this wonderful channel 4 months ago and I am completely hooked ever since. Thank you CtC for being a very good feel part of the internet! :)

@timdunkley9173 3 месяца назад

I find it easier to remove the colouring once I have identified the correct digit.

@kibels894 3 месяца назад

Was there a way to deduce that blue was the other of the 8/9 pair besides green? It seemed like it should be, and it ended up being, but I couldn't find how to prove it.

@RichSmith77 3 месяца назад

I guess you're not going to be happy with the answer "Yes. Solve the entire puzzle, like Simon does in the video. Then you will have deduced blue is the other of the 8/9 pair". (Sorry)

@RecreationalCynic 3 месяца назад

79:20. I enjoyed that. Plus, I actually got to use Phistomefel and PotatoHead's anti-knights theorem for once.

@David_K_Booth 3 месяца назад

You beat my time by 18 seconds! Very enjoyable puzzle.

@prakashpatel7089 3 месяца назад

Jousting technique on board? (7,4)

@alienrenders 3 месяца назад

39:46 for me. If you use colouring, it kind of solves itself. Still, nice one!

@DonaldSjervenE 3 месяца назад

I had trouble putting 4 1s in the 4 corner 2x2s.

@vanciervancier 3 месяца назад

Simon you don't have to be so ashamed of pencil marks (with numbers, colours or any kind of mark) across boxes. Marking where a digit could be in a column or row is completely valid. Granted it can get murky within cages and segments across boundaries but i'd rather you left them in. however if that does help make your workings clearer for you that's also completely fine.

@aatmansupkar8747 3 месяца назад

How do people go about making such puzzles? Like, how do you get the guts to try to make a puzzle which goes 'oh knights move digits are all different'?

@PuzzleQodec 3 месяца назад

Sometimes it's just playing around and discovering that a particular setup is surprisingly restricted. And then you go analyze it and hopefully discover why, and put in clues to showcase what you found and narrow it down to a unique solution. What I like about this particular puzzle is how efficient the clues turn out to be. There's nothing tricky, the clues get used more than once, and the way they make the puzzle resolve is grandiose. Takes a lot of polish to get it there!

@maht0x 3 месяца назад

there are some videos on the channel of setters explaining their process

@stevesebzda570 3 месяца назад

@3:20 that "positive diagonal" Question: What would that diagonal be called if in the 4th (IV) quadrant? It's leading up to 1 on these sudoku grids/graphs. I've rationalized these into the 4th quadrant (with -1 at the top and -9 at the bottom) So, what's that diagonal called in the 4th quadrant?

@David_K_Booth 3 месяца назад

The diagonal that runs from (1,-1) to (9,-9) has negative gradient, and the one that runs from (1,-9) to (9,-1) has positive gradient, so I would expect that they would be named accordingly.

@stevesebzda570 3 месяца назад

@David_K_Booth I'm just now realizing what you're saying. Are you saying quadrants 1 and 4 are the same? I would think 1,-1 to 9,-9 would be positive in the negative direction. You're saying that's negative (the same as quadrant 1)?

@David_K_Booth 3 месяца назад

@@stevesebzda570 Yes - in all four quadrants, what matters is whether, as you read from left to right, the cells steadily ascend (positive gradient) or steadily descend (negative gradient). When I was a maths student, I would have phrased it as "The gradient (or the slope) is invariant under translation", but that was years ago.

@stevesebzda570 3 месяца назад

@David_K_Booth okay. Cool. Thanks. You want to hear a funny story? You see how we're saying "1,-1" and "9,-9?" EDIT: ^^ that's x,y That's how I wanted the rows/cols designations to go. I finally got us all uniform saying r/c. I suggested we do row (being it was horizontal like the x-axis) and col (it being vertical like the y-axis). But it wasn't 'til about last summer that I realized the numbers along the x-axis were actually the columns , and the numbers up the y-axis were actually the rows. I had it backwards by mistake. We're doing y,x when we should be doing x,y. I had it backwards by mistake, and have us all uniformly mistaken. That's why I've been rationalizing it into the 4th quadrant ( -1 at the top and -9 at the bottom). I got us all "uniform," but iniformly incorrect. Lol 😆 Funny?!

@David_K_Booth 3 месяца назад

@@stevesebzda570 Yes exactly! From a maths background, I write coordinates (x,y) ((left to right, down to up) but as someone who's used spreadsheets since the 1990s, I also sometimes think (row, col) (up to down, left to right). This can lead to the sort of miscommunication that crashes space probes. 🙂

@bait6652 3 месяца назад

Interesting for this puzzle you can prove 4 1s can't go on PF-ring so 9sum=234.

@psiphiorg 2 месяца назад

Quite a challenger! I did a lot of coloring, first for 5's and then for each of the center high digits, and ended up with multiple colors in several cells. My time today was 54:08, solver number 4744.

@5t757 3 месяца назад

I managed 50:50. Love this type of ruleset.

@Rach881101 3 месяца назад

37:40 for me. Nice puzzle!

@bait6652 3 месяца назад

Design is letter /colour complete solvable...fun stuff. Knights Rule on this design is fun But made.an error on letter-digit map

@zirco77 3 месяца назад

We've got pre-recorded videos for quite a few days now. Let's hope that's because Simon is on holidays. 🤞

@Anne_Mahoney 3 месяца назад

I think he is, based on last Friday's crossword video, which of course can't be pre-recorded. And I hope he's having a wonderful time. 😺

@zirco77 3 месяца назад

@@Anne_Mahoney of course, silly me. I didn't think about that one. Thank you!

@_-_-Sipita-_-_ 3 месяца назад

13:41 for me.

@Grantherum Месяц назад

Sometimes I wonder if they should call some of these sudoku puzzles... "numbers by paint"... since thats kinda how they have to be solved in the long run.

@DarrenNakamura 3 месяца назад

Finished in 104:45. Not easy!

@stephenmccarthy1795 3 месяца назад

Perhaps I cheated by assuming I knew how the 9 arrow must be composed. Is there a way to know early on?

@kuraban1 3 месяца назад

There are a couple of tricks, mentioned above, although it can still solve without doing that early.

@awilliams1701 3 месяца назад

The yellow arrow is 7 or 8 and can't have a 5, so it's 1 AND 4 and then either 2 or 3.

@mattbendzinski4945 3 месяца назад

Love the title (LZ)...

@gandalf_le_rouge 3 месяца назад

Chocolate teapot quadruple spotted :D

@jakejarvis6683 3 месяца назад

Simon, I would love to bump into you at a party. That would make the party worth attending.

@matthewjohnson6360 3 месяца назад

I wonder how proposal puzzles couples are doing?

@kuraban1 3 месяца назад

This particular couple is doing very well Matt. :)

@anaayoung9142 3 месяца назад

How this can solve? I don't know.. we must watch to see! 😊

@awebmate 3 месяца назад

I do not see any reason to be surprised that it does solve.

@anaayoung9142 3 месяца назад

@@awebmate I know, it not that hard. But I was joking with the tittle! =)

@SteubenThursday 2 месяца назад

bro said 4/5 difficulty. we're just chimps to simon i think.

@Unbounded7 3 месяца назад

I figured out there were only 3 1s and 126 was impossible. WIth 12 1234s in only 16 spaces excpet they can only be on the line 4 times total leaving 8 more 1234s in the none line squares of the phistomfel

@user-kt9vr1wj6y 3 месяца назад

40:25 for me nice puzzle

@LednacekZ 3 месяца назад

36:03 for me. It was not as hard as i thought.

@theredstoneengineer6934 3 месяца назад

28:01 for me

@michaelmatter1222 3 месяца назад

That's one reason it might be called the positive diagonal 😉

@soocool78 3 месяца назад

53:18 - he eliminates 3 with a quadruple, but only 3/4 boxes he says has a 3 in it. So technically lucked out there!...insane solve (i say the above as if I could ever solve this puzzle in a million years lol)

@smet145 3 месяца назад

I think that was sound logic. There are 4 cells with only 4 possible digits to put in them. It doesn't matter that he has eliminated 3 from one of them - there must be a 3 in one of them as there are 4 cells all in the same column with only 1, 2, 3 and 4 as options.

@buster2256 3 месяца назад

The 4 marked cells in the column only have 4 possible digits as options. So you need all 4 options to fill all those cells, and that is independent of the options on an individual cell. And as the 3 was one of those 4 options, it can't appear in the bottom cells. If it did, only 3 digits would be left for the 4 marked cells. I hope I explained that one correctly.

@FleckerMan 3 месяца назад

They don't all need to contain a 3, they all contain only digits _from_ 1,2,3,4 so 1,2,3,4 must exist in those 4 cells, and the rest of the column can't have 1,2,3,4 :)

@RichSmith77 3 месяца назад

Simon's quadruple logic is sound, as others have already said, but I noticed there was a 23 pair in box 7 that also resolved the 3 in box 8, by knight's move.

@soocool78 3 месяца назад

@@FleckerMan my god my sudoku logic is so bad. Its why i can barely solve the puzzles that are less than 5 stars without have "all errors" turned on or not using hints.

@veggiet2009 3 месяца назад

I feel like Simon gave up on phistomaphel too quickly, because he's sure that a green digit is on the ring but didn't really question where it would go in the corners

@stevesebzda570 3 месяца назад

These are just too difficult I imagine (54 minute video/solve from Simon and all). Maybe I'll look at it later (if time provides -- I got laundry to pick I just found out -- and making dinner for myself). Good luck, Simon. PS: ^^ there's a comment for the "algorithm" for ya though..

@MattYDdraig 3 месяца назад

34:41 Sing as you raise your bow Shoot straighter than before... Absolutely brilliant puzzle (and a great song)

@baumundallesandere 3 месяца назад

kind comment passing through

@MoonIn420 3 месяца назад

never been this early:)

@Myko82 3 месяца назад

I think positive/negative diagonals should be reversed, because the origin of the coordinate system is in the top left and not bottom left as is usual.