How to calculate the lateral deflection of a steel flagpole 

This channel is absolutely fantastic! Thank you so much for helping people that are looking to improve their knowledge. You make it look so easy and simple. Thank you for your time and effort that you put in this people like me will really appreciate all the hard work you do :)

I worked through the example, a Hollow section with a diameter of 139.7mm and thickness of 4mm (bluebook hot finished) has an I value of 3.93x10^6 , therefore using the formula within this video should produce a deflection of 13mm... 13 < 20 deflection limit. Thereby satisfying the deflection check. Or alternatively, if you want the same section size, 5mm thickness should suffice for a 114.3mm diameter. Thanks for the great videos! Only just found this channel, but can't wait to watch more! :)

great to have an insight of the structural design of RC shear walls. thanks

Can you carry out a calculation for the flagpole foundation in compacted gravel/clay ground, the hole to be drilled with an auger, or an excavation filled with 40n concrete.

V Good, can you kindly tell me the little more about the deflection formula. Thanks

At the end, how was height/300 determined as the limit for lateral deflection?

Add a vedio on design of monorail beam and an eot

In your example, Ix is incorrectly calculated because you took the inside radius to be (D - t) / 2 instead of (R - t) or (D - 2t) / 2.

thanks very good example..but i think ..I for section 1625480 mm4

Limit h/300 in wich norme?

If the Thickness of Pole is 3mm, shouldn't the Inner Radius = Outer Radius - 3mm? How can the inner Radius = Outer Radius -1.5mm instead???

I for a tube is 0.049*(D^4-d^4) - avoid use of r , as it does not exist without measuring diameter first. I say you have the wrong answer for deflection. And question can not be answered as outside diameter or thickness was not stated.