How to check Palindrome Number || Basic Programming Questions Series

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In this video, we will learn how to write a program to check the given number is Palindrome or not.
Learn:
1. check the given number is Palindrome or not.
2. write different test cases
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Опубликовано:

6 янв 2019

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Комментарии : 39

@guddipatel9506 5 лет назад

Great Tutorial but your program won't work if the given number is Negative, for eg: -121 or so....so in a while loop instead of (num > 0) use while(num != 0) and it will work for all the test cases

@shwetankmishra4531 3 года назад

negative numbers are not palindrome number

@19863960 5 лет назад

sir i hope would u complete programming video series at least 50-60 program mainly from string & array

@sumitsaha9782 2 года назад

private boolean isPalindrome(String str) { String revStr = new StringBuffer(str).reverse().toString(); //can also use StringBuilder instead of StringBuffer return (revStr.equalsIgnoreCase(str)); }

@luckylily9561 5 лет назад

Thank you... U thought nicely.. Can u make more videos of stings, arrays, nd patterns..

@anushaka2171 5 лет назад

public static void StringRev(String string){ String t; t=string; StringBuffer reversestring = new StringBuffer(String.valueOf(string)).reverse(); System.out.println(reversestring); if(t.contentEquals(reversestring)) { System.out.println("It is a PALINDROME"); } else { System.out.println("It is NOT a PALINDROME"); }

@naveenautomationlabs 5 лет назад

Good one.

@sarojjha9243 4 года назад

Not working, it reaches all-time to else part and displaying not a palindrome.Someone please check the code

@AmanSaxena-qk9tm 4 года назад

@@sarojjha9243 A bit optimized code with less var : public static void RevString(String str) { StringBuilder rev = new StringBuilder(str).reverse(); if (str.contentEquals(rev)) System.out.println(str + " is Palindrome String."); else System.out.println(str + " is not Palindrome String."); }

@abraham2961 5 лет назад

Hi thanks for this programming

@abraham2961 5 лет назад

Without reverse method String original, reverse = ""; Scanner in = new Scanner(System.in); System.out.println("Enter a string to check if it is a palindrome"); original = in.nextLine(); int length = original.length(); for (int i = length - 1; i >= 0; i--) reverse = reverse +original.charAt(i); if (original.equals(reverse)) System.out.println("The string is a palindrome."); else System.out.println("The string isn't a palindrome."); }

@yolwasmirzat 5 лет назад

Hello , if you have time can you please cover Anagram , Duplicate Word , Permutation, Determined Largest Word please , Thank you

@ramkumarreddy6775 5 лет назад

Palindrome String program: public class PalindromeString { public static void isPalindromeString(String name) { String rev = " "; int length = name.length(); for (int i = length - 1; i >= 0; i--) { rev = rev + name.charAt(i); } System.out.println("The reverse of the name - " + rev); if (rev.equals(name)) { System.out.println(rev+ " - is a polindrome"); } else System.out.println(rev+ " - not a polindrome"); } public static void main(String[] args) { isPolindromeString("MADAM"); isPolindromeString("Madam"); } }

@20_SinManya 5 лет назад

I have one doubt: Is '1001' is a palindrome (Note the single quotes before answering)?It would be very nice if you can show the program using strings.

@shankarpk89 5 лет назад

An alternate approach - Single program for both integers and strings package largestNumber; import java.util.Scanner; public class Palindrome { public static int[] checkPalindrome(Object x) { int flag = 0; int a[] = new int[2]; String str = String.valueOf(x); int length = str.length(); if (length % 2 == 0) { for (int i = 0; i < (length / 2); i++) { if (str.toUpperCase().charAt(i) == str.toUpperCase().charAt(length - i - 1)) { flag++; } } } else { for (int i = 0; i < (int) (length / 2); i++) { if (str.toUpperCase().charAt(i) == str.toUpperCase().charAt(length - i - 1)) { flag++; } } } a[0] = length; a[1] = flag; return a; } public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("ENTER SOMETHING"); Object x = sc.nextLine(); System.out.println(x); int[] b = checkPalindrome(x); if (b[1] == (int) (b[0] / 2)) { System.out.println(x + " IS A PALINDROME"); } else { System.out.println(x + " IS NOT A PALINDROME"); } } }

@aniruddhadey5889 5 лет назад

Thanks

@maafaque9842 2 года назад

public static void isPalindromeString(String name) { String original=name; int length=name.length(); String reverseString=""; System.out.println("Lenght of String:"+length); for(int i=length-1;i>=0;i--) { reverseString=reverseString+name.charAt(i); System.out.println(reverseString); } System.out.println("Reversed: "+reverseString); if(original.equals(reverseString)) { System.out.println("Its a Palindrom String"); } else { System.out.println("Not a Palindrom String"); } }

@shwetapandey8321 3 года назад

i tried this code this is also working public static void checkPalindrom(int x) { int num = x; ArrayList arr=new ArrayList(); while(num>0) { arr.add(num%10); num=num/10; } int c=0; int i=0; int j=arr.size()-1; while(i

@kapilrana2361 5 лет назад

Hi Naveen, Just wanted to know, Can we write the above program in below way. Or what an interviewer can say if I give the below answer. Please suggest and let me know what is the issue in this. public class PalindromeNumber { public static void main(String[] args) { int a = 252; String b = String.valueOf(a); StringBuffer sb = new StringBuffer(b); StringBuffer c = sb.reverse(); String d = c.toString(); if (b.equals(d)) { System.out.println("the number is palindrome number"); } else { System.out.println("The number is not a palindrome number"); } } }

@bheemshankar_pk 4 года назад

Great tutor

@naveenautomationlabs 4 года назад

Glad you liked it

@Kalaiarasan_Balu 5 лет назад

V expect more program videos

@tejastoley6714 5 лет назад

StringBuffer sb = new StringBuffer("Tejas"); sb.append("Toley"); system.out.println(sb.reverse);

@abineshm9695 4 года назад

hi sir , how to write a code to separate number,alphabhaet, special character from a ... string input = (a24js7f.%^ output =ajsf 247 (.%^ this was asked in recent interview,please explain

@asheshrastogi2389 2 года назад

To check if a given String is Palindrome public class PalindromeString { public static boolean isPalindrome(String str) { String rev = ""; for(int i = str.length()-1; i>=0; i--) { rev = rev+str.charAt(i); } if(rev.equals(str)) { return true; } return false; } public static void main(String[] args) { // TODO Auto-generated method stub System.out.println("'radar' is a Palindrome: " + isPalindrome("radar")); System.out.println("'selenium' is a Palindrome: " + isPalindrome("selenium")); System.out.println("'level' is a Palindrome: " + isPalindrome("level")); } }

@raghuveermh6869 5 лет назад

Solution for String Palindrome public static void isPalindrome(String a){ String b = " "; int n = a.length(); for(int i = n-1; i>=0;i--){ b = b+a.charAt(i); } if(a.equalsIgnoreCase(b)){ System.out.Println("The enterd String is Palindrome); } else{ System.out.println("The enterd String is not a palindrome"); } } Call this into the Main Method and pass the input String...

@renukachavan7442 5 лет назад

Program to check if a string is palidrome or not : public class PalindromeString { public static void isPalindromeString(String s) { System.out.println("Given string is :" + s); // reverse the given String String reverse = new StringBuffer(s).reverse().toString(); // check whether the string is palindrome or not if (s.equals(reverse)) { System.out.println("a Palindrome string"); } else System.out.println("not a palindrome string"); } public static void main(String args[]) throws java.lang.Exception { isPalindromeString(" madam "); isPalindromeString(" malayalam "); isPalindromeString(" renuka "); isPalindromeString(" abbc "); } }

@srinivasmuddappa9663 5 лет назад

If we give any palindrome number starting with 0 this logic does not work example 012210

@shyamchristypaul1058 4 года назад

public class PalindromeClass { public void isPalindromString(String str1) { String str2= ""; int i = str1.length(); for(i =str1.length()-1;i>=0;i--) { str2 = str2+str1.charAt(i); } //System.out.println(str2); if (str1.equals(str2)) { System.out.println("This is a Palindrome String"); } else { System.out.println("This is not a Palindrome String"); } } public static void main(String[] args) { PalindromeClass obj =new PalindromeClass(); obj.isPalindromString("teet"); } }

@standwithtruth2194 5 лет назад

String malayalam

@WMohanty 3 года назад

How to remember the logic man

@purushottamw 4 года назад

//String Reverse //String palindrome check //Case sensitive handle public class StringReverse { public static void main(String[] args) { ReverseString("kuuk"); } public static void ReverseString(String string) { string=string.toUpperCase(); String rev=""; //System.out.println(string.length()); //System.out.println(string); for(int i=string.length()-1;i>=0;i--) { rev=rev+string.charAt(i); } System.out.println("Reverse String is :"+rev); if(string.equals(rev)) { System.out.println("String is Palindrome: "+rev); } else { System.out.println("String is not palindrome: "+rev); } }

@abraham2961 5 лет назад

String pop

@myamazingvideos 5 лет назад

package introduction; public class PalindromeCheck { public static void main(String[] args) { String input = "nitin"; int i = input.length(); char[] ar = input.toCharArray(); boolean b = isPallindrom(i, ar); if (b==true) { System.out.println("Mr. Saksham Bahati, The number youve entered is pallidrome"); } else { System.out.println("Mr. Saksham Bahati The number you've entered is not pallindrome"); } } public static boolean isPallindrom(int length, char y[]) { int j = length - 1; for (int i = 0; i < length/2; i++) { if (y[j]==y[i]) { j--; } else { return false; } } return true; } } Thanks @naveen

@standwithtruth2194 5 лет назад

Thanks