You have no idea how scared I was because of this subject now after watching almost all of your videos I feel excellent thank you for providing this awesome content free of cost.
Thanks to the tutor...u r awesome in your way of teaching....I've watched all your videos on digital electronics....and they have helped me clear my concepts...and all probable questions regarding the topic....thanks a lot....thumbs up for ur job....keep making more such videos on more topics...
this is the first time ..m subscribing anything on you tube...hats off u guys..in none of the books give this as deep as u have taught....really appreciable!!!!
When we make the K-map cells for determining J1, K1, J2 & K2, why do we consider the present state values of Q1 & Q2 instead of next state values of Q1 & Q2 ?
well i know what reduces likes is actually those students opening your sessions day before exams and after lockdown ,opening before exam sheet ,, both parties forget to like this video (in state of fear)
3 days for my Endsems , coming from one of the top Engineering institutes in India , but i can say with 100% certainty that only this guy can help me pass DSD 😇🙏 Edit: I passed guys , almost half of my class is up for retest , ese paper was very tough 😭
I typed it wrong sir the previous one i.e instead of using Q1 and Q1* for finding j1 using k-map u have used Q1 and Q2.why sir ? Would you please help me in this aspect
the final diagram is wrong.You have considered Q1 as the MSB throughout the entire video. But in the end, you drew the diagram Q1 as LSB. The flip flops should be reversed.
no the circuit is corect. bcoz he fed i/p frm ryt to left.. so its the same case when we fed i/p lft to ryt and see o/p in inverse form(i.e. last f.f have msb) so either u inverse o/p or i/p.
I think as the circuit is synchronous (without feed forward), the placement of the flip flops shouldn't matter as long as we know that Q1 is MSB and Q2 is LSB
For people getting confused about MSB LSB!. It is a "synchronous counter" i.e one flip flop doesn't depend on the output of the previous flip (getting clock from the previous one) like in async counter!. So initially he took q1q2 (with q1 as MSB) and he did the procedure with the same! and in the diagram eventhough he drew q1 first and q2 second EVEN if he drew q2 first and then q1 IT DOESN'T MATTER!! what matters is what YOU CONSIDER AS MSB. So if q1 is initially considered as MSB then in the FINAL the same q1 MUST be taken as MSB and fed to some other circuit (perhaps?) but the representation doesn't matter!. ALTHOUGH things would've been clear if he had taken q1 as q2 and q2 as q1!. Ask me any doubts if u have!
@@-A-Rohith I forgot I left this comment. I got gate rank 3000 in my first attempt landed top CS product jobs and now it's 6 years. But thanks for saying thanks. You brought some memories