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How to Determine if a Set of Vectors is Linearly Independent [Passing Linear Algebra] 

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You see if you can find nonzero weights when writing the zero vector as a linear combination of the vectors in the set.
Interesting Theorem : If a set of vectors contains the zero vector, that set is automatically linearly independent. Why is this? Continue reading:
Think about the linear dependence relation: you pick zeros for all the weights for all the nonzero vectors in the set, but then for the zero vector you can pick ANY NUMBER for its weight and you will get the zero vector as a linear combination. In doing this, you've written a linear combo of the vectors in the set that equals the zero vector, and that one weight was nonzero, right? So, you've done it. The set is linearly dependent bc you can write a linear dependence relation.
Skip the background info: 2:09
Skip to how to eyeball: 6:14

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7 авг 2024

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Комментарии : 64   
@LyndseyNguyen116
@LyndseyNguyen116 9 месяцев назад
4 years later and you're still helping people... ur a legend, thanks man!
@Winklemanus
@Winklemanus 5 лет назад
I can tell the guy who does these is handsome.
@stemsupport3645
@stemsupport3645 5 лет назад
love u graham
@simmzlingsmthiyane1809
@simmzlingsmthiyane1809 3 года назад
Focus
@odgarig8601
@odgarig8601 9 месяцев назад
My boy thirsting in linear algebra comments section. Y'all wild.
@jonahs92
@jonahs92 3 часа назад
Lol you were right 😏
@coohjay
@coohjay 4 года назад
i love how the voice cracking got more and more intense as the video went on, great vid btw :)
@angelahuynh5074
@angelahuynh5074 3 года назад
it's probably cause he's so passionate about math
@Quiyum
@Quiyum Год назад
thought I was the only one lmfao
@angelahuynh5074
@angelahuynh5074 3 года назад
We just learned about linear dependence this week and your explanations make it easier to understand :-)
@GF-wf8rt
@GF-wf8rt 2 года назад
Very good video. You don’t explain it using annoying theorem lingo. Quick and easy ways to check a span. Thanks!
@abbycash
@abbycash 4 года назад
THANK YOU. Very helpful and easy to understand
@quinn4856
@quinn4856 7 месяцев назад
I watched this video the night before my first linear algebra exam and now I'm watching it again the night before my linear algebra final lol
@michael654
@michael654 2 месяца назад
I watched this video when I was 5 years old. Now I won the Nobel prize in math.
@rohhanbhardwaj
@rohhanbhardwaj Месяц назад
@@michael654 whattttttttttt
@estherabass7389
@estherabass7389 Год назад
thank you so much! i love how straightforward this was!
@spookybrojo7186
@spookybrojo7186 2 года назад
This really breaks it down, thanks!
@danielprive6
@danielprive6 3 года назад
Archer's teaching Linear Algebra now
@thienphan1764
@thienphan1764 2 месяца назад
Really appreciate the videos, can't thank you enough 🙏🙏
@babi9500
@babi9500 2 месяца назад
2:00 man after so many vids you're the only one who answered my question thanks sm
@Gabriel-dm2ru
@Gabriel-dm2ru 10 месяцев назад
THANK YOU YOU ARE A LIFE SAVER
@stepbystepscience
@stepbystepscience 2 месяца назад
Your definition at the beginning of the video was very good, most other sources make it way too complicated.
@huitzilopochtli2872
@huitzilopochtli2872 3 года назад
Thank you so much!
@definitelynottigerwhitten5865
@definitelynottigerwhitten5865 6 месяцев назад
Thanks brofessor!
@charliefleming3859
@charliefleming3859 Год назад
great stuff
@xeeshankhan725
@xeeshankhan725 Год назад
You are going to help me pass my Exam >> XD
@GB2G
@GB2G 5 месяцев назад
Thank you
@cyrrender
@cyrrender Год назад
nah jit was goin thru puberty in this video 😭 jokes aside thx for the great explanation!
@williamhogrider4136
@williamhogrider4136 Год назад
Thnx man ;)
@drealslimshady
@drealslimshady 3 года назад
what if there are more elements in each vector than vectors (ex. a 4x3 matrix) would that also mean it is automatically linearly dependent?
@Lucas-yh5zz
@Lucas-yh5zz 2 года назад
Hi! not necessarily, for example if you had these two vectors: (1,3,5,7) and (2,6,10,14), you can see they are not linearly independant as the second one is clearly two times the first one. pd:I know it's been 8 months, so you probably don't need the answer anymore, but other people may.
@liveforkillarpit
@liveforkillarpit Год назад
@@Lucas-yh5zz its after 1year helps me . thanks
@yusufmoola6471
@yusufmoola6471 2 года назад
or u can find the determinant and see that it equals zero so its linear dependent.
@toddchavez4610
@toddchavez4610 2 года назад
My go to method
@respectpartii6302
@respectpartii6302 Год назад
only works in square matrices, so this is a most general method presented in the video.
@crazygreekpvp6635
@crazygreekpvp6635 3 месяца назад
GOAT
@ok-sj7bx
@ok-sj7bx 3 месяца назад
What if there are more variables in the vectors than the matrix has columns? For example vectors v_1 = (1,2,3) and vector v_2 (2,3,4) would come out (just play along) and have one free variable but that would still mean they have two "stable" variables? Which technically would be enough to form a plane? Or would it still shrink in size and form a line, since that would still mean there is a solution other than 0 for the coefficients c_1*v_1+c_2*v_2=0-vector.
@ok-sj7bx
@ok-sj7bx 3 месяца назад
Nvm literally the last comment responded to this.
@Sam-iy4in
@Sam-iy4in 2 года назад
king
@cagataytekin6372
@cagataytekin6372 9 месяцев назад
hoca aldin bizi sirtina gidiyoruz
@Coolpanda77454
@Coolpanda77454 4 месяца назад
question: according to the last example, is the opposite also guaranteed? If we have more entries in each vector than the number of total vectors, does that make it linearly independent?
@monsieurLDN
@monsieurLDN 4 месяца назад
No only if every column has a pivot. Pets say that you have a set of 2 vectors with 3 entries. If the two vectors are multiples (which is the same as overlapping) the set would be lineary dependent
@ok-sj7bx
@ok-sj7bx 3 месяца назад
@@monsieurLDN Lol check the newest comment, I literally asked the exact same question and then read one comment down and you answered my question. Thanks!
@cmdrbobert9862
@cmdrbobert9862 2 года назад
I don't really grasp how you know what you're doing to row by using c1, c2, and c3.
@thehamsterarmy2380
@thehamsterarmy2380 2 года назад
He's solving for the pivots variables in each row by using the columns in that row
@matteos.3438
@matteos.3438 Год назад
your comment about the theorem that states if a set contains the zero vector makes it linearly independent is incorrect - it's the other way around because if one of the vectors were zero then we would have a dependence relation
@monsieurLDN
@monsieurLDN 4 месяца назад
Doesn't it depend? you can only use the trivial solution of 0 to represent a 0-vector
@monsieurLDN
@monsieurLDN 4 месяца назад
Nvm
@GenuinePeacefulTimes
@GenuinePeacefulTimes Год назад
having only a trivial solution defines linear independence. you said we don't want that at the 3:00 mark. lmao you are wrong
@user-vw8ow3pm6u
@user-vw8ow3pm6u 11 месяцев назад
Okay so why did my professor make it so complicated for no reason
@thabelangncube7539
@thabelangncube7539 Год назад
can you show us how you went about the row reduction, am kinda getting some weird values
@gattinocurioso6852
@gattinocurioso6852 11 месяцев назад
mee to
@SpeaksYourWord
@SpeaksYourWord 9 месяцев назад
1:54 wtf is that supposed to mean
@healthstellar8701
@healthstellar8701 2 года назад
5:54 nice
@chrisdeluisa6648
@chrisdeluisa6648 2 года назад
9:00
@ASD-6132
@ASD-6132 Год назад
@@chrisdeluisa6648 6:09
@amb.jworld3127
@amb.jworld3127 Месяц назад
Are you teaching those who are Learning it for the first time or are you lecturing a pro😒.
@jameshindle4000
@jameshindle4000 Год назад
Phattest gg's
@PURPLECUT
@PURPLECUT 2 года назад
some people know how to teach some don't and this guy does not.
@thehamsterarmy2380
@thehamsterarmy2380 2 года назад
honestly it made a lot of sense
@EigenA
@EigenA Год назад
I thought he did a good job. Maybe we should look at ourselves before commenting on the qualities of others.
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