i do a lot of crafting and hate having to pay so much for so many templates. Your tutorials have saved me so much. Thank you so much for making this Grandmas budget. I have also referred your videos to other senior crafters. The guy who says it doesn't work is full of fecal matter.
For those wondering why it didn't work, it's because the construction is approximate: if |AB|=1, the radius |A5| = sqrt((4+sqrt(3))/8) ≈ 0.8465, instead of sqrt((5+sqrt(5))/10) ≈ 0.8507. Still, it means 0.5% precision, so it should definitely look OK, taking line thickness into account (as the video demonstrates).
Thx a lot I was struggling a lot in this subject and i am writing an exam in about 1 and a half hours. But i am now positive i am going to ace it all thx to you 😁
Ty very much i was having a hard time on my assignment draw a perfect same angle and side pentagon u really helped me❤❤❤i sub and like im really thankful i just need to watch a hexagon one and im good tysm again😊❤❤❤❤
A few years ago I searched for a method for construction of the regular pentagon which contained proof of its own veracity... I could not find one, so I came up with a new method which is impossible to forget. It starts with the Unit Circle, then finding the mid-point of the radius on the X-Axis, then add 1/2 of Root 5 to 1/2 and you get the Golden ratio on the X-Axis. Use your compass centered on the golden ratio point, and draw a circle with radius of golden ratio... Thus there will be 2 golden triangles drawn, one above the X-Axis, and one below it... The 3 points going through the Unit Circle are by definition 3 of the 5 points you need to make a regular pentagon, so just draw in the final two points. I should record a video of it, and post it on RU-vid. The base angles in an isosceles golden triangle are 72 degrees, which is 1/5th of 360 degrees...! 1/2 of root 5 is obtained by making the line-segment between points (1/2, 0) and (0, 1), then just use Pythagorean Theorem to confirm.
This looks very convincing, yet it turns out to be an approximation. If the base length AB is 1, then the height of point 5, h5 = (1+sqrt(3))/4; The angle we want is a= 2pi / 5. But in the drawing you think you should get tan(a/2) =2/(1+sqrt(3)); So a = 2 arctan[2/(1+sqrt(3))]; which gives a= 1.2638 However, 2pi/5 is 1.2566. It's only about 0.57 percent off. I got a little suspicious because this seemed such an easy construction. Too easy to be accurate 🙂 But pretty nice anyways.
Well i guess i need to find a video explain the middle point method then come back when you placed the compass on 6 where is the compass set just random? Depend on the compass distance spot 5 could be out in space, ive Watched 3 different channels on how to draw a pentagon and every video theres a question i do appreciate you talking the other videos play music donr talk and just start slapping lines down and readjusting the compass and the title says SUPER EASY, probably is once you learn how
At this point you will have to wait, as I am working on other videos at the moment. What I can recommend is to find the point used for a hexagon and just double the distance. That will give you the point for a dodecagon.
Hi, Am not sure why, but the crossing point to my point E is outside of the circle. I did exactly what you said, step by step, but :( I had the starting (A-B) line 8.09mm long. I don't know if the decimal os affecting it. I really need your help
@@Wimmas I was really careful and accurate with my compass and I even did it twice. But still. It gave me the same results 🤔 When I watch how you do it: It's like you using magic or something 😅 But it must be what you've said about that 5% diff
I was taught this same method over 21 years ago, and all efforts to recall failed until I watched your video. Thank you very much for this very straight to the point video.
circumference of 18.22m divided into 30pcs arc, i want to draw one of the arc with 1.45m radius instead of 2.9m radius. pls assist me i have sent message to you on messager facebook too
