this is exactly what i needed, i have been stuck at the concept of where the graph will "level off" and how the volume produced actually changes and this explained it perfectly! thanks lots!
Nice work... Beautifully explained. Also you can measurer the rate of reaction by taking the gradient of the slope 📐 Upstep/Across Dy/Dx The steeper the number, the faster the rate of reaction! Ps did you know that the 1 molar mass of CaCO3 is exactly 100g. Factors affecting the Rate of Reaction are: 1️⃣ Temperature 2️⃣ Concentration 3️⃣ Catalyst 4️⃣ Particle size 5️⃣ Pressure Wishing every student 💯 sucess in their GCSE exams. 😊
in the 10g and 5g one u explained very beautifully how there will be steeper and volume of gas produced difference but, will both of them end/finish the reaction at the same time? (the line reaching parallel to x asis)
It gets steeper the more concentrated the solution/ the higher the temperature - normally in an exam the marks would be 1 for it being steeper/shallower and 1 for where the line flattens :)