How to Find the Maximum or Minimum Value of a Quadratic Function Easily 

FINALLY FOUND THE VIDEO WHICH REALLY HELPED ME OUT FINDIND THE MINIMUM AND MAXIMUM VALUE WHICH SUCH A GOOD ANIMATION ,,,,HATS OFF TO YOU

these type of videos are a lifesaver

-b/2a came from the fact that this is a quadratic equation which means if you differentiate it you'll get 4x+5, and minimum or maximum occurs where dy/dx = 0, so 4x + 5 = 0, so x = -1.25 . Plug in this in the equation to get 0.875. We know that equation is opening upward (positive coefficient of x^2) and therefore 0.875 is the minimum.

thanks a bunch I've got an upcoming SAT test and I'm doing really good but then stumbled on a question in which I must calculate the minimum value of the function. I read its explanation but was left puzzled as it used a rule of: a(x-h)+k where h is the minimum I have not yet taken this specific rule at school so yours is a life saver

You saved me, I've been struggling for hours!

Hey there! There is also this formula they taught us at 10th grade. to find the maximum or minimum value without finding the x in : ax² + bx + c you can simply devide Δ by 4a to find the value of Y.

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Thank you , it helped a lot.

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Literal crime these videos didn’t exist when I was in high school

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x² - 2x + 3 in this eq by applying this method the ans is coming 3 but its min. Value is 2

Can someone please explain how he got f(-1.25)=0.875 at the end? I don't know how he solved f(-125)=2(-125)2+5(-125)+4 to get 0.875 I'm super confused.

What a video

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Lovely👍

How did you get 0.875 please tell mee

Danke

good 🎉

Btw if a range is given, this method might not work

W

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thank you