How To Replace Your Dice Set With A Single Die 

My set is just 1D3 and 1D4. You should see how many friends I lose when I have to roll a D%.

If you have a D24 at hand, just reroll if it gives you 21, 22, 23 or 24, and then you have a D20 also... no very accurate, but works.

You could use the d24 for d20. The way you would do this is to discard any rolls that are greater than 20, and roll again. Since the odds of such a roll are low, it works, and it doesn't change the statistics if the die is otherwise fair.

Interesting. Although, the way I'd replace the d% would be to use the d20 as a d10 to generate the digits. A lot less math and statistically closer to a proper d%, I believe.

Oh man, the d24 is classic... Doesn't do a d30 well either, but they haven't included d30 tables for a LONG time... :-)

Using the same logic you can just use a d12 and not hunt for a specialized die.

If you only want to do division, just use a d60.

2:22 To roll a d100, you just need two rolls of d20, either doing _(d10 -1)*10+d10_ or _(d5 -1)*20+d20._ They both give you a perfect d100, with all results from 1 to 100 being equiprobable. 2:33 What you did is seriously hurting my feeling. Stop it there, Satan.

Why be close to accurate for percentile when u just need to role the d20 as a d10 twice for a completely accurate percentile role?

As others have said, the easiest way to get 1-20 with a d24 is to discard results 21-24. But it's just as easy to get 1-10. From 1-20, just read the last digit, discard 21-24. So a 3 is a 3, a 13 is a 3, and a 23 is re-rolled.

Just get a d120 lol

What happened to the Facebook page?

I love the probability involved in rolling dice. I would love a manufactured 36 sided dice with the 2-12 outcomes for 2x D6. Do you know if there is such a thing out there?

That's a pretty neat idea to use math to replace most of your dice. I'd honestly like to keep my dice set as it is though but because I like carrying around a bunch of pretty multi-colored dice. XD I'm also glad that you mentioned in the segment of "how to roll a D3" is to roll a d6 and divide by 2. I do it that way as well, but I know a lot of people that roll D3s by rolling a D4 and then just rerolling the 4s, and I absolutely abhor that method. It's not a very exact replacement, and it generally just feels wrong.

You could also roll a D2 (coin-flip dice), and D5 if you use either a D10 or D20 as a support die. Or if you use the D24 and reroll things 21 and over, you can still use the D24 for a D5, and a D10, and a D20. But if you use that method, you can almost roll any die you can imagine. ;) (whanna roll a D17? Roll a D24, reroll everything over 17). As long you roll one die, this should work out. In games I'm used with (older), there is often D3 used. And sometimes I didnt have just the right die like D8 or D12 or something like that. Thats when I learned, that in many cases you can apply de divition (rounding up) to a die that has double or three numbers more. But you can also upscale smaller dice, by doing Low or High rolls. Say you want to roll a D20 but dont have a D20, only a D10. You cant just roll 2D10 and add the numbers, because then you cant get 1, and the chanses are shifted (bellcurve). What you do instead is first roll any die that can show a low and high number. Like the D10. If you roll 1-5, it is considered low, and if you roll 6-10 its considered high. Then you roll the D10 again, and if the first one was low, you dont add anything, and if it was high you add 10. Works with everything. It is the same thing as if you dont have a D24, (that would be great to randomize a specific hour something happens at a day), you could first roll a dice, any dice to se if it is Low or High, to se if it is AM or PM, then roll the D12 again. And that will cover the 24 hours of a day. From 1 to 24. Cheers.

Practically the answer is no by the fact how this "one die for all" works. As a D6 od maybe even a D12-replacement it might have its merits. So that makes you spare one die. You can not equally roll the numbers needed when you are on a D4, D8, D10, D% or a D20 roll. That replacement die has literally 12 actual sides. Rolling a D4 with that can land you one of then two blind sides making the chances working against you to roll anything from 1 to 4. Or a D8 throw? Catastrophy. The way this one-die-for-all is used possiblyleaving you with four blind sides to hit, lowering the chances even more as it did already with a D4 throw. Interesting idea but nothing else I'd recommend.

it truly isnt. roll a d4, you need a d4. if it says roll a d6, you need a d6 and so on and so on. dice are too small and weightless to whine about carrying them around. i have a few d24s but only for collection and amazement purposes. they have no use in RPGs unless the master is clever and creative enough to come up with a reason to let the gods choose a number between 1 and 24

With the maths presented here you'd never roll 13% or something like 37%. Neigh possible. Just go with the intended dice sets since they are not heavy and you can keep them in these little bags anyway.

Scuse me sir but is that a d24 u have there?.........I just have I question.........who made it and where can I get one?

My dice idea turns out to be a real thing lmao. I'm using thos d24 for my own ttrpg

I enjoyed this video, but I would rather use full dice set. It doesn't take up that much more space to carry. Besides, these days we have dice apps on our phones

dice are part of the fun. Actually play online games and not a huge fan of cg dice rolls. I like have all the different dice, the sound they make, the designs and colors are also pleasing. So getting rid of the dice for a single die kinda kills the fun slightly.

You don't even need dice. Just call up a friend on your phone, and ask them to say the first number that comes to their mind between 1 and 24.

My friend gave me a set of 15 different dice including a d24, which I thought was strange at first

Isn't d% just a d10?

Instead of rolling a D100 you can just roll a D20 5 times.

You can roll a percent with a D20 twice, taking the units digit of each roll

I have a idea Take your D24 and add a zero to the end It will be like a d10 and %d

D Ultimate: I'm about to end this man's whole career.

I lost my d 12 and can not buy anymore dice am screwed

You could get a d120 for d4, d6, d8, d10, d12, and d20

It's easy you use a d120 modulo x

You could also use 1d6 1d10 and 1d12

In an emergency, apps….

I like to have a separate set of dice to represent every class (only core classes, I’m not fuckin crazy) and whenever I have a character with an animal companion or steed or familiar or the like, THEY are represented by a set that is just a white d24 and a black d20. So the ranger are my green polyset and his dog can be just these two dice.

You can use six sided pencil as D3, D6, D12, D2, D4, D8.

I just have 5 sets of dice that a carry around (and some other random dice) but I mean, you could always use more dice

1:51 d3?

d30

Great job!

*laughs in d30*

You can replace the whole set with a D24 and a D20: D4 = D24 mod 4 D6 = D24 mod 6 D8 = D24 mod 8 D12 = D24 mod 12 D10 = D20 mod 10 D20 = D20

0:06 you said rude word you shouldn't say that in any times