@Funda Of Web IT Please can you show how To get id MY PROBLEM 👇example UPDATE table SET name= brk, age=jc WHERE ID=John The question how do I get ID (John)??? Please do Update data direct From Webpage.
The idea of update is to modify what a record contains, I expected for you to PRE-LOAD the form with what is contained in the DB record, and then to edit it using the form, and then to update.
please tell me where is the problem. I have done as same as shown in your video. But when I am trying to update data it shows "Data Not Updated". I have also check the db name and fields name. updation body{ background-color:whitesmoke; } input{ width : 40%; height: 5%; border:1px; border-radius: 05px; padding : 8px 15px 8px 15px; margin: 10px 0px 15px 0px; box-shadow: 1px 1px 2px 1px grey; } Updating of Data into Arvind Prasad Database using PHP
When we have multiple email id's of people stored in our database. .can we make Gmail group of those people and send email automatically without manual forming the group?
please sir, help me. i already follow everything just like you did but it cannot update the data. Update User Info body{ backgroud-color:whitesmoke; } input { width:40%; height: 5%; border: 1px; border-radius: 05px; padding: 8px 15px 8px 15px; margin: 10px 0px 15px 0px; box-shadow: 1px 1px 2px 1px grey; } Updating User Info i dont know where i get wrong
Uncaught Error: Call to undefined function mysqli_connection(), how can i resolve it? im using xampp, i've done the database and ecc ecc, this error is from the index.php i have made, pls help me
Get data in textbox.. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-mzFQYL5Rx5k.html Update data from textbox.. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-8En_gF3S9BI.html
Aap puch rahe ho ki.... form k andr image use kar rahe hai toh kya kare... So.. to use image in form.. u hv to mention.. the form tag I.e.. action="" method="post" enctype="multipart/form-data" And input type="file"
i think you have given single quote ( ' ) in your table name, instead use tilde symbol ( ` ). you can even use without tilde symbol as given below: $query = "UPDATE yourtablename SET col1='$var1', col2='$val2', col3='$var3' WHERE id='$id' "; $query_run = mysqli_query($connection, $query); if($query_run) { echo "updated"; } else { echo "Not udpated"; }
