U kidding me ?? Why aren't you not uploading anymore ???? Your way of explaining things are EXTREMELY good like seriously u are making all things simple !
No. Assume D_1 is ON and D_2 is OFF. If D_1 is ON, then V_A = 2 V. But then the cathode of D_2 is lower than 3 V, meaning D_2 must be ON, contrary to our assumption.
there is no current flowing through R which means it's a short circuit with no potential difference, if V was to change that would imply that there was current flowing but we assumed earlier that I = 0. (since there is no current flowing in the circuit then the Voltage is the same(5 V)at any point higher than the ground)
