Me too, but then today I had to write this decoding and printing the digits out. In 9S08 assembly code. Oddly, I watched this after doing the same exercise myself and writing the code. Handy to have watched this, looks like I did it properly.
What kind of magical video is this. 100% clear explanation. Wow. Just wow. 7 minutes of a video that I would watch repeatedly forever so I could just experience the power of this video one more time
Hey girl... You really helped me... I was dead loss in converting the IEEE754 to decimal... And I am having an exam tomorrow... You're really a miracle!! You explain so simply and clearly... I just understood the converting in 7 minutes... Wow... Thanks a lot... You made my day.. ♥ 💕 😍 😘
Thank you so very much! This is the most helpful conversion video I have found. You break it down so it is so much easier to understand. This has helped me with my homework.
So TRUE bro! I leave the classroom with depression after every System Programming class now, because I simply just cannot understand the lecture. My prof gives the most confused explainations and not-so-good examples with his not-so-sexy British accent, which make his lecture more confusing. Sorry for being negative in here but I seriouslly considered take off my shoe and throw him with it. Like why should I pay my tuition if you want me study on my own?!
@@Mason-yj1ip are u indian??. If not,then chill bro. We indians pay a huge as tuition fees,can't complaint anyone,teach our friends and make ourselves to understand everything. 😂😂😂
Thank you so much! I'm a Stanford student and tomorrow I have a test on this stuff, I really appreciate it! I'm sure that if this comes up on the test I'll get those points for sure! Great explanation!
Thank you for your videos. I learned how to change between the floating and Decimal. In the step III, I use 1.10101×2^7. Then I can move the point to the right 7 times. so the result is 11010100, then turn it to a number based 10, it is 212.
i am from bits..just abt to give my midsem exams..was really worried as none of my friends explained me..randomly searched and found ur video..understood everything..Thanks a lot...may god bless you!!
Your way of teaching is amazing ! This video has cleared all my doubts . Thankyou so much!! I really want you to upload more videos that will help students like me.
Good thing to remember is that for simple questions like these, 2^7 is 128. which is always 1000 0000 in Base-2 (Binary). Once you get used to the simple numbers. At first glance, I knew 110 is 6. meaning it was 128 + 6 = 134. anything beyond 1000 (8) you should use the 2^x (where 1 is present) method. it's a lot more accurate if you're not confident with the basic binary
Thank you sis. Helped me a lot!!! Your voice is captivating me towards this subject and your handwriting is way too good. Make more videos,continue the good job.
You saved meee at work xD here's the python version : def IEEE754(n): # decimal to binary b = bin(n)[2:] # the binary in IEEE754 notation # add '0' bytes on the left if len(b)%4 != 0: v = '' for i in range((4-len(b)%4)): v += '0' b = v + b sign = b[0] # add '0' bytes on the right while len(b) < 32: b += '0' # compute exponent and mantissa exponent = int(b[1:9], 2) - 127 mantissa = computeMantissa(b[9:]) print("sign : ", sign, "exponent : ", exponent, " mantissa : ", mantissa) # compute the value final = (-1)**int(sign) * (1 + mantissa) * 2**exponent return final
