Imine and Enamine Formation Reactions With Reductive Amination

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This organic chemistry video tutorial provides a basic introduction into imines and enamines. An imine can form in the reaction of a ketone with a primary amine and enamine can be produced by mixing a ketone with a secondary amine. The imine and enamine can be reduced to amines by reductive amination with NaBH3CN.
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Опубликовано:

18 сен 2024

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Комментарии : 35

@TheOrganicChemistryTutor 7 месяцев назад

Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Math & Science Videos: www.patreon.com/mathsciencetutor/collections

@vishkavayomi4726 3 года назад

Thank you!! I watched your most of organic vdos.. It helped me lot!! Your explanation is very clear and understanding... thank you again ☺️

@lavina3535 4 года назад

The enamine formation mechanism wasn't there in my textbook. Thanks for explaining :)

@oliviacasale8941 3 года назад

My textbook does imine formation differently here a NA is done first by R-NH2 to form an oxygen anion and then that is protonated with H-A+

@TheMaskedRacoon1 Год назад

I think imines and enamines can also be reduced to secondary and tertiary amines using Aluminum Galinstan amalgam in an ethanol distilled water solution.

@weezy224 2 года назад

just wanna listen to your voice before i sleep every single day

@mdjabir9817 4 года назад

Really good explaination

@nvel5612 2 года назад

missed a plus charge on N after NH3 attacked carbonyl. ~3:40

@ajnewyork3690 4 года назад

at mark 1:04, you mentioned that the more substituted alkene would form. But in the organic chemistry as a second language book, it said the less substituted alkene would actually be the major product. Which one is correct?

@tomatrix7525 4 года назад

AJ New York well, not sure why that book says that, but more subbed alkene always form as a major product as they are more stable.

@tomatrix7525 4 года назад

Unless the stereo chemistry prohibits them forming

@diegogaetes.9628 4 года назад

Hofman´s rule... Depends on the context

@siddharthagotur7449 2 года назад

I think you are talking about the hoffman product. It happens with E2 elimination reactions generally in which the nucleophile is bulky (e.g: t-butO⁻) or if there's a bad leaving group present (NR3 ⁺).

@ranjithvurs1086 Год назад

I know saytzeff product is major still I saw in some video that, in this enamine formation, double bond formed is Hoffman cause of repulsion of methyl group or something

@jesusmrosario-claudio4104 3 года назад

Thank you once again.

@misakichan372 3 года назад

U R The best👍🏻👍🏻

@lalmalsawmachhangte620 6 лет назад

Great job...thanks

@dogeyna9181 4 года назад

You should try solving IIT &JEE papers 😜

@taniapradhan7480 3 года назад

👌👌👌

@yungcashregister8587 3 года назад

Thank you so much!

@SnehaR380 2 года назад

how many here coz enamine came in Jee unexpectedly??

@Nobody-xp6ip 9 месяцев назад

@bredbutter 9 месяцев назад

@anushkadixit49 9 месяцев назад

Mee , i was doing jee mains papers of 2022 and it came unexpectedly 😅

@SnehaR380 9 месяцев назад

Got 5611 rank in 2023 Feeling nostalgic Now in iiitA and conditions don't seem any better I m studying more than Jee here and seeing 200 students unplaced in final year in such a repute clg is really heartbreaking ND demotivating

@factshut8663 9 месяцев назад

@@anushkadixit49same 😅

@davidd5682 3 года назад

Thank you!

@sanskarkurude 2 года назад

Thank you ❤️

@patrycjaprzedwojska1072 9 месяцев назад

I've seen different mechanism for reductive amination, how do I know if this one is the right one?

@goofyaaahhandle 8 месяцев назад

mechanism arent real for the most part, so like a single reaction can have multiple correct mechanisms considering none of them is scientifically impossible... this is what my prof said atleast