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Inequalities 3 | CAT Preparation 2024 | Algebra | Quantitative Aptitude 

Rodha
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Advance Algebra by Ravi Prakash | Quantitative Aptitude for CAT 2024
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11 апр 2019

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Комментарии : 59   
@binnapaul2126
@binnapaul2126 2 года назад
Sir, I have been following your content for some time now and I have to say there are so many concepts taught here that can't be found anywhere else which makes solving questions so much easier and faster. Thank you so much sir. Also a humble request, please do upload videos on pipes and cisterns back again.
@Rodha
@Rodha 2 года назад
Never deleted
@yashasharma9963
@yashasharma9963 3 года назад
Great level of thinking + great level of explaining that thinking = Rodha.
@Atulvermaa76
@Atulvermaa76 3 года назад
is that you comment on all videoss
@monishmoolya8919
@monishmoolya8919 Год назад
We got a stocker here
@AkshayN-rh5ek
@AkshayN-rh5ek 10 месяцев назад
@@monishmoolya8919 stalker*
@aahistachirps
@aahistachirps 2 года назад
Thank you so much, sir. This video has cleared all my doubts and your methods are much easier than the conventional methods of AM and GM.
@phoenixcrew6045
@phoenixcrew6045 10 месяцев назад
RAVI SIR YOU ARE A GEM OF PERSON NEVER HAD A TEACHER LIKE YOU BEFORE ........ SIMPLY THE BEST!!!!!!! THANK YOU VERY MUCH😍
@harshalxd7533
@harshalxd7533 Год назад
Super level of Questions to raise the thinking bar ! thank you for such videos!
@ksaikiran1781
@ksaikiran1781 4 года назад
i donno why but directly applying AM-GM concept is far more satisfying and less time consuming than the traditional method discussed above
@devashish4690
@devashish4690 4 года назад
true..wanted to just crosscheck if at 7:00 the answer should be 3^9? please acknowledge
@bhaskarmaniraj
@bhaskarmaniraj 3 года назад
@@devashish4690 Yes, even i got the same answer through am and gm method.
@Rodha
@Rodha 3 года назад
@@devashish4690 no. Right answer is 3^10
@jaiganeshbaskar9888
@jaiganeshbaskar9888 Год назад
@@devashish4690 The value that you got is the maximum value of (x^2.y^3.z^4) by AM-GM method but in the question they asked the maximum value of (x^4.y^2.z^3) so for this case using AM-GM method will not fetch you the result.
@sujalsonkar1657
@sujalsonkar1657 2 месяца назад
will you please explain how ?
@vineetichake5014
@vineetichake5014 Год назад
The great Ravi sir!
@ayushisingh1471
@ayushisingh1471 10 месяцев назад
Awesome Content .......Thankyou Sir.
@prithasingh6254
@prithasingh6254 Год назад
The first question was easily solvable by linear equations.
@nidhiyadav8903
@nidhiyadav8903 Год назад
Thanks a ton sir🌼
@Daredavil_298
@Daredavil_298 5 месяцев назад
Super content sir👍🙏🙏
@PratyushAtghara266
@PratyushAtghara266 Месяц назад
interesting topic, well explained👏
@swapnil5162
@swapnil5162 Год назад
Great 👍 sir
@aashita203
@aashita203 9 месяцев назад
Legend🤩
@tanmaydey3008
@tanmaydey3008 2 года назад
Thank You Sir
@vinaykapil1413
@vinaykapil1413 2 года назад
Sir, a humble request, please do upload videos on coordinate geo back again.
@Shivam_General_Fitness
@Shivam_General_Fitness Год назад
Thanku sir
@kunalmjain
@kunalmjain 4 года назад
Sir can we take ratio of x y z and then solve eqn
@muskantiwary606
@muskantiwary606 3 года назад
How can u identify the no. Is maximum or minimum? In 7th question, 2 is minimum and -2 is maximum . How please explain
@adityajain1984
@adityajain1984 20 дней назад
at 17:41, min can be 0, if we put a=-1
@arimachezhian8631
@arimachezhian8631 11 месяцев назад
Since it was never mentioned but both x and y to be positive in the first question. Can't we just assume a big value of negative x and corresposing y and yield Infinity as an answer
@debdipdutta3953
@debdipdutta3953 6 месяцев назад
this is the second lecture in inequalities🤗
@KlutchyRex
@KlutchyRex 17 дней назад
sir se ek sec phele answer likh kar khush hota hua main
@happy_bolta_hai
@happy_bolta_hai Год назад
Sir in first question... Cant X be -15 and Y be 15 as 2(-15)+3(15) = 45 and (-15)² + (15)³ = Maximum Value of x²y³.
@AbhishekKumar-kl9ug
@AbhishekKumar-kl9ug 2 года назад
@ 7:03 ques, shouldn't the values of x:y:z (max) be 24:8:9 got it by the traditional method we did in prev ques to this one and eventually we'll be getting largest value (24)^4(8)^2(9)^3. @Rodha sir plz correct me if I'm making an error.
@avijanpaul9367
@avijanpaul9367 11 месяцев назад
Well it’s just the ratio not the real answer to the question
@neelammaurya8970
@neelammaurya8970 4 года назад
in frst ques.if we keep close value as x=7, and y=8 then we'll get maximum value....y don't this to be done
@DhanushAdns
@DhanushAdns 3 года назад
Then the value of 2x+3y would be 2(7) + 3(8) = 38
@devarshpanchal9743
@devarshpanchal9743 3 года назад
Sir how is it possible that number and its reciprocal sum is =2 ifi take 100+1/100 then it is more than 100 how can it be 2 ?
@swapneelrao8276
@swapneelrao8276 3 года назад
Bro, read the questions carefully. Here he never said the value is 2. The "minimum value" is 2.
@Rodha
@Rodha 3 года назад
Min value is 2
@bhaskarmaniraj
@bhaskarmaniraj 3 года назад
@9:15 I got the answer as 9. through am and gm method.
@priyabratanayak4359
@priyabratanayak4359 3 года назад
Bro can you explain the am and gm method or share some link where i can find those!!
@bhaskarmaniraj
@bhaskarmaniraj 3 года назад
@@priyabratanayak4359 You can learn it from Takshzila RU-vid channel.
@bond-hn4wd
@bond-hn4wd 3 года назад
@@bhaskarmaniraj but its not full, we can still get problem with the fact the if we got maximum of addition and minimum of multiplication, then we have to rely on his teaching.
@ankitsharma-pf3zx
@ankitsharma-pf3zx 3 года назад
u did calculation mistake... in gm part u have to write product as [(2x/4)^4][(3y/2)^2][(4y/3)^3] ..now u will get right
@anoshirani5682
@anoshirani5682 10 месяцев назад
The 1st question is for maximum and 3rd question is for minimum, but we use the same rule for both. How is that possible?
@kronikevaporation6007
@kronikevaporation6007 10 месяцев назад
Look intently. 1st question is asking for product and 3rd is asking for sum. It's maximum for product and minimum for sum.
@TarunAsthana
@TarunAsthana 2 месяца назад
Is there any formula for (AB)min. When A+B=constant ?
@AbyjithK
@AbyjithK 2 месяца назад
Take A=1 and B= n-1 if A+B=n This will give the min value
@vibhavadhikari8013
@vibhavadhikari8013 3 года назад
2:29 Max value of (x^2).(y^3) is not 243 but infinity. For instance, x=-3, y=7, satisfy the equation 2x+3y=15, thus making (x^2).(y^3)=3087, which is greater than 243... Keeping reducing the value of x by 3 and y by 2 indefinitely, thus x approaches negative infinity and y positive infinity, thereby making the answer as infinity...
@garlapatisaibhargavreddy4834
@garlapatisaibhargavreddy4834 3 года назад
Actually question was incomplete. Their should be x and y are natural numbers. Hope you got it
@pradipto_de
@pradipto_de Год назад
@6:15 it should be (3 raised to 9)
@parvathymarangattu7097
@parvathymarangattu7097 Месяц назад
Yes it is 3 raised to 9
@parvathymarangattu7097
@parvathymarangattu7097 Месяц назад
And answer will be 19683
@vibhavadhikari8013
@vibhavadhikari8013 3 года назад
17:37 Error... Minimum value of expression is not 64, but 0. Put a=b=c=-1.
@Rodha
@Rodha 3 года назад
1st read the main statement Question at 12:22. a,b,c,d are positive real numbers. Already given.
@shishir6340
@shishir6340 4 года назад
2x+3y+4z=27 . solution is wrong. if we calculate x,y,z by normal method we get the values as x=8, y=8/3,z=3. this gives the maximum value as : 786432. but if we put your values to get maximum we get a smaller number than this.
@avinashbajpai7091
@avinashbajpai7091 4 года назад
Bro it's (2)x + (3)y +(4)z =27 . So if we put your values the sum will exceed the constant value of 27.
@akshat9282
@akshat9282 3 года назад
according to your values for x, y, z; the initial equation of 2x+3y+4z=27 is not satisfied
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